I'm working on simple application using PHP and MySQL. Up to this point we needed to display items from database in HTML table. Simple pagination was implemented as well. It looks something like this:
+----+---------------------+
| 1 | Item 1 |
+----+---------------------+
| 2 | Item 2 |
+----+---------------------+
| 3 | Item 3 |
+----+---------------------+
| 4 | Item 4 |
+----+---------------------+
....
+----+---------------------+
| 5 | Item 25 |
+----+---------------------+
Not a rocket science. Now we add new functionality so we can (optionally) group items - We really create a 'lot' of identical items. We decided to add new column in database called groupID - which can be number or NULL for items not contained in any group. On web page we must display it as one element which expands when you click on it.
+----+---------------------+
| 1 | Item 1 |
+----+---------------------+
| 2 | Item 2 |
+----+---------------------+
| 3 | Item 3 |
+----+---------------------+
| 4 | Group 1 (Expanded) |
+----+---------------------+
| Group 1 Item 1 |
+---------------------+
| Group 1 Item 2 |
+---------------------+
| Group 1 Item 3 |
+----+---------------------+
....
+----+---------------------+
| 25| Item 25 |
+----+---------------------+
As you can see Number of items on one page may vary so we must treat items in group as one item, so simple 'limit 25' not working anymore. I wonder if I can make some clever mysql query which will work this way. I rather want to avoid to create new table in database which consists groups and relation to item table, because most of the groups will have only 1 Item. I don't believe this functionality will be used a lot, but You know - client. Also this system works on production for some time so I'd rather avoid such changes. Any Idea how to make it work? Also please keep it simple as possible, because this example is simplified. Real query is already bit complicated.
I also want avoid parsing it via PHP code, because it's just dumb to query all few thousands of rows and then discard all but 25-50 elements.
As you said some group ids can be null, I thought we should fix that.
When null, we use the item id to for the group and we use a prefix to make sure our new group_id is unique.
This is my solution using subqueries (not pretty, but seems to work):
SELECT
i1.id,
i1.itemgroup1
FROM (
SELECT
items.id,
IF(ISNULL(items.group_id),
CONCAT('alone-', items.id),
CONCAT('group-', items.group_id)) as itemgroup1
FROM
items
) as i1
RIGHT JOIN (
SELECT
items.id,
IF(ISNULL(items.group_id),
CONCAT('alone-', items.id),
CONCAT('group-', items.group_id)) as itemgroup2
FROM
items
GROUP BY itemgroup2
LIMIT 2
) as i2 on i2.itemgroup2 = i1.itemgroup1
** UPDATE **
Removed
WHERE
items.group_id IS NOT NULL
Related
Hey I am new to sphinx search.
In my query I retrieve course_ids. All the courses belong to a theme_id, but some of them can belong to more than 1 theme, so some of them are duplicated.
I set limits to my query to display results from 1-20, then 21-40... So 20 by 20.
But sometimes in those 20 results there are duplicated results, so for example if from 21 from 40 there are 3 duplicated results I want to remove them and then fill the 3 empty spaces with the next 3 results, so the query returns instead 21-43. Then 44-64...
I tried setGroupBy(), and it worked, but I don't want the courses to be sorted by course_id but with setSortMode(), so the course_ids are again duplicated.
How can I remove the duplicated records and keep the sorting?
Any help would be appreciated. Thanks
setGroupBy has a third and option argument, to specify the final sort order.
So can group by (for example) course_ids but still do the final sorting by weight (or whatever), rather than the default '#group desc'.
$client->setSortOrder( SPH_SORT_RELEVANCE );
$client->setGroupBy( 'course_id', SPH_GROUPBY_ATTR, "#weight desc" );
Still use setSortOrder, which determins WHICH of the rows from the course, is kept. Ie show the highest rank one first, which mimicks overall sorting of weight.
Looks like what you are looking for is exactly what REMOVE_REPEATS() does. Not sure it's available in the programming language clients. You'll probably need to use SphinxQL instead which is anyway recommended as the clients are outdated and miss a lot of functionality.
Here's an example:
Without REMOVE_REPEATS():
MySQL [(none)]> select * from testrt;
+------+------+
| id | gid |
+------+------+
| 1 | 10 |
| 2 | 10 |
| 3 | 20 |
| 4 | 30 |
| 5 | 30 |
+------+------+
5 rows in set (0.04 sec)
With REMOVE_REPEATS() by gid:
MySQL [(none)]> select remove_repeats((select * from testrt), gid, 0,10);
+------+------+
| id | gid |
+------+------+
| 1 | 10 |
| 3 | 20 |
| 4 | 30 |
+------+------+
3 rows in set (0.06 sec)
I have a page that displays a list of projects. With each project is displayed the following data retrieved from a mysqli database:
Title
Subtitle
Description
Part number (1 of x)
The total number of photos associated with that project
A randomly selected photo from the project
A list of tags
Projects are displayed 6 per page using a pagination system
As this is based on an old project of mine, it was originally done with sloppy code (I was just learning and did not know any better) using many queries. Three, in fact, just for items 5-7, and those were contained within a while loop that worked with the pagination system. I'm now quite aware that this is not even close to being the right way to do business.
I am familiar with INNER JOIN and the use of subqueries, but I'm concerned that I may not be able to get all of this data using just one select query for the following reasons:
Items 1-4 are easy enough with a basic SELECT query, BUT...
Item 5 needs a SELECT COUNT AND...
Item 6 needs a basic SELECT query with an ORDER by RAND LIMIT 1 to
select one random photo out of all those associated with each project
(using FilesystemIterator is out of the question, because the photos
table has a column indicating 0 if a photo is inactive and 1 if it is
active)
Item 7 is selected from a cross reference table for the tags and
projects and a table containing the tag ID and names
Given that, I'm not certain if all this can (r even should for that matter) be done with just one query or if it will need more than one query. I have read repeatedly how it is worth a swat on the nose with a newspaper to nest one or more queries inside a while loop. I've even read that multiple queries is, in general, a bad idea.
So I'm stuck. I realize this is likely to sound too general, but I don't have any code that works, just the old code that uses 4 queries to do the job, 3 of which are nested in a while loop.
Database structure below.
Projects table:
+-------------+---------+----------+---------------+------+
| project_id | title | subtitle | description | part |
|---------------------------------------------------------|
| 1 | Chevy | Engine | Modify | 1 |
| 2 | Ford | Trans | Rebuild | 1 |
| 3 | Mopar | Diff | Swap | 1 |
+-------------+---------+----------+---------------+------+
Photos table:
+----------+------------+--------+
| photo_id | project_id | active |
|--------------------------------|
| 1 | 1 | 1 |
| 2 | 1 | 1 |
| 3 | 1 | 1 |
| 4 | 2 | 1 |
| 5 | 2 | 1 |
| 6 | 2 | 1 |
| 7 | 3 | 1 |
| 8 | 3 | 1 |
| 9 | 3 | 1 |
+----------+------------+--------+
Tags table:
+--------+------------------+
| tag_id | tag |
|---------------------------|
| 1 | classic |
| 2 | new car |
| 3 | truck |
| 4 | performance |
| 5 | easy |
| 6 | difficult |
| 7 | hard |
| 8 | oem |
| 9 | aftermarket |
+--------+------------------+
Tag/Project cross-reference table:
+------------+-----------+
| project_id | tag_id |
|------------------------|
| 1 | 1 |
| 1 | 3 |
| 1 | 4 |
| 2 | 2 |
| 2 | 5 |
| 3 | 6 |
| 3 | 9 |
+------------+-----------+
I'm not asking for the code to be written for me, but if what I'm asking makes sense, I'd sincerely appreciate a shove in the right direction. Often times I struggle with both the PHP and MySQLi manuals online, so if there's any way to break this down, then fantastic.
Thank you all so much.
You're able to do subqueries inside your SELECT clause, like this:
SELECT
p.title, p.subtitle, p.description, p.part,
(SELECT COUNT(photo_id) FROM Photos where project_id = p.project_id) as total_photos,
(SELECT photo_id FROM Photos where project_id = p.project_id ORDER BY RAND LIMIT 1) as random_photo
FROM projects as p
Now, for the list of tags, as it returns more than one row, you can't do a subquery and you should do one query for every project. Well, in fact you can if you return all the tags in some kind of concatenation, like a comma separated list: tag1,tag2,tag3... but I don't recommend this one time that you will need to explode the column value. Do it only if you have many many projects and the performance to retrieve the list of tags for each individual project is fairly low. If you really want, you can:
SELECT
p.title, p.subtitle, p.description, p.part,
(SELECT COUNT(photo_id) FROM Photos where project_id = p.project_id) as total_photos,
(SELECT photo_id FROM Photos where project_id = p.project_id ORDER BY RAND LIMIT 1) as random_photo,
(SELECT GROUP_CONCAT(tag SEPARATOR ', ') FROM tags WHERE tag_id in (SELECT tag_id FROM tagproject WHERE project_id = p.project_id)) as tags
FROM projects as p
As you said from item 1 to 4 you already have the solution.
Add to the same query a SQL_CALC_FOUND_ROWS instead of a SELECT COUNT to solve the item 5.
For the item 6 you can use a subquery or maybe a LEFT JOIN limiting to one result.
For the latest item you can also use a subquery joining all the tags in a single result (separated by comma for instance).
I have four tables. The first describing a mix of items. The second is a linking table between the mix, and the items. The third is the item table, and the fourth holds lot information - lot number, and when that lot starts being used.
mix
mixID | mixName
----------------
1 | Foxtrot
2 | Romeo
mixLink
mixID | itemID
----------------
1 | 1
1 | 2
1 | 3
item
itemID| itemName
----------------
1 | square
2 | triangle
3 | hexagon
itemLots
itemID| lotNo | startDate
-------------------------
1 | 22/5/3| 22/07/16
2 | 03/5 | 25/07/16
2 | 04/19 | 12/08/16
3 | 15/0 | 05/08/16
Now, I need to be able to fetch the information from the database, which details all the items from a mix, as well as the most recently used lot number, something like this:
itemName | lotNo
----------------
square | 22/5/3
triangle | 04/19
hexagon | 15/0
I've tried a dozen different mixes of joins, group by's, maxes, subqueries, and havings; all to no avail. Any help would be much appreciated, I've been pulling my hair out for hours, and I feel like my fingernails are just scraping at the solution!
This will give you the result you're after and will perform pretty well if you have your indexes done properly. I'm not sure how you're meaning to reference mix as it's not apparent in your sample output but I've included it in the WHERE clause so hopefully you can understand where you would use it.
SELECT i.itemName
, (SELECT il.lotNo FROM itemLots il
WHERE il.itemID=i.itemID
ORDER BY il.startDate desc
LIMIT 1) as lotNo
FROM item i
JOIN mixLink ml ON ml.itemID=i.itemID
JOIN mix m ON m.mixID=ml.mixID
WHERE m.mixName="Foxtrot";
I have one question about my database.
table inventory
_______________________________________
id_item | item_name | quantity |price |
--------+------------+----------+------+
1 | brake | 20 |60 |
--------+------------+----------+------+
2 | oil filter | 20 |80 |
--------+------------+----------+------+
table invoice
______________________________
id_invoice | items | quantity |
-----------+-------+----------+
1 | 1,2 | 4, 1 |
-----------+-------+----------+
So I'm going to display back items in a table as an invoice ( view purpose )
but I'm stucked at how to explode/ display it using SQL.
I mean I want to display it like this:
table html
_________________________________________
No | item | quantity | total price |
---+------------+----------+-------------+
1 | brake | 4 | 240 |
---+------------+----------+-------------+
2 | oil filter | 1 | 80 |
---+------------+----------+-------------+
I just need a simple code to make this function. I only left this function to complete my system.
Thank you!
Follow the following steps : (dont have the patience to write the code for you right now, I am a PHP beginner too)..
Get the list of Invoice items by a select query on invoice table with the invoice number criteria.
Since your items and comma-separated in the database, get the quantity(list) field into a string variable.
Apply the explode function on the quantity(list) variable and get the output into an array.
Loop through the array and build the html rows. If you want a quick and generic function to do this, and if you know how PHP functions work, you can use readymade code html_show_array from here to accomplish this step.
So I have this query:
SELECT * FROM cars {$statement} AND deleted = 'no' AND carID NOT IN (SELECT carID FROM reservations WHERE startDate = '".$sqlcoldate."') GROUP BY model
It basically checks the reservations table and then if there are reservations, it gets those carIDs and excludes them from the loop.
This is cool, so as there may be three dodge vipers and 2 are booked out it will only display the last one, and it will only display one at a time anyway because I group the results by model.
All that is good, however when it runs out of entries, so all the cars are booked out, the car does not appear in the list of cars. (As i clear from the query).
I would like a way to say if no rows of a certain car model are in the results, to display a placeholder, that says something like 'UNAVAILABLE'.
Is this possible at all? Its mainly so users can see the company owns that car, but knows its not available on that date.
You should probably handle this in the PHP, checking the number of rows returned and replacing the 0 with "UNAVAILABLE".
Based on TO comment:
In this case you want to look at
http://dev.mysql.com/doc/refman/5.1/en/case.html
This would need to go into the SELECT list like
SELECT
CASE car_count WHEN 0 THEN 'UNAVAILABLE'
WHERE ...
Without seen some of your data, its hard to give you a query, but if you move your subquery to your select expression, you could return the count available (which would be 0 when they are all reserved). Then when you display your data, you could then check if the count is 0, and display your unavailable message.
Edit:
Given the table cars:
+----+----------+
| id | model |
+----+----------+
| 1 | viper |
| 2 | explorer |
| 3 | viper |
| 4 | explorer |
+----+----------+
and the table reservations:
+-------+------------+
| carid | date |
+-------+------------+
| 1 | 2013-03-07 |
| 3 | 2013-03-07 |
+-------+------------+
A query similar to yours above will return:
+----+----------+
| id | model |
+----+----------+
| 2 | explorer |
+----+----------+
If you change it to something like:
SELECT
`outer`.`model`,
(
SELECT COUNT(*)
FROM
`cars` AS `inner`
WHERE
`inner`.`model` = `outer`.`model` AND
`inner`.`id` NOT IN(
SELECT `carid`
FROM `reservations`
WHERE `date` = '2013-03-07'
)
GROUP BY `inner`.`model`
) AS `count`
FROM cars AS `outer`
GROUP BY `outer`.`model`;
then you would get results like:
+----------+-------+
| model | count |
+----------+-------+
| explorer | 2 |
| viper | NULL |
+----------+-------+
If you then needed the NULL value to come back as a 0, you could use COALESCE, as Liv mentioned previously.
It's not pretty, and I'm sure it could be done a much cleaner way, but it does work.
There was a similar question asked here that might get you headed in the right direction. Check out the COALESCE() function.
The built-in function COALESCE() returns the first not-null value in its arguments. This lets you structure queries like SELECT COALSECE(foo, 'bar') [...] such that the result will be the value in column 'foo' if it is not null, or the value 'bar' if it is.