Good day guys, I am having a bit trouble of how can I make this like xx month/s ago and year/s ago if the days reach the number of months/years. Is it possible ? Anyway I'm making a messaging module. This is my code. Advance thank you for your help guys
<?php
date_default_timezone_set('Asia/Manila');
$now = strtotime(date("Y-m-d H:i:s"));
$date = strtotime($key->message_date); //this is the date where message was sent
$dateDiff = abs($now - $date);
$fullDays = floor($dateDiff/(60*60*24));
if($fullDays==0)
{
echo " Today ";
}
else if($fullDays==1)
{
echo " Yesterday ";
}
else
{
echo $fullDays ." days ago";
}
$at=date('g:iA',$date)
?> at <?php echo $at?>
You can use this function you have Pass message time as an argument
function convert_time($ptime){
$etime = time() - $ptime;
if($etime < 1){
return '0 seconds';
}
$a = array( 12 * 30 * 24 * 60 * 60 => 'year',
30 * 24 * 60 * 60 => 'month',
24 * 60 * 60 => 'day',
60 * 60 => 'hour',
60 => 'minute',
1 => 'second'
);
foreach ($a as $secs => $str){
$d = $etime / $secs;
if($d >= 1){
$r = round($d);
return $r . ' ' . $str . ($r > 1 ? 's' : '') . ' ago';
}
}
}
In this function you can get "(1) second/minute/hour/day/month/year ago"
Related
I know this question has been asked 2-3 times before, and I am using a function which I found in one of the answers(check it here) from those questions, but it doesnt seem to be working fine for me, i asked there in comments but didnt get any reply, so I am opening a new question here. following is the code to get plain text date/time from a datetime(mysql type).
function getElapsedTime($time_stamp)
{
$ts = convert_datetime($time_stamp);
$time_stamp = $ts;
$time_difference = strtotime('now') - $time_stamp;
if ($time_difference >= 60 * 60 * 24 * 365.242199)
{
return get_time_ago_string($time_stamp, 60 * 60 * 24 * 365.242199, 'year');
}
elseif ($time_difference >= 60 * 60 * 24 * 30.4368499)
{
return get_time_ago_string($time_stamp, 60 * 60 * 24 * 30.4368499, 'month');
}
elseif ($time_difference >= 60 * 60 * 24 * 7)
{
return get_time_ago_string($time_stamp, 60 * 60 * 24 * 7, 'week');
}
elseif ($time_difference >= 60 * 60 * 24)
{
return get_time_ago_string($time_stamp, 60 * 60 * 24, 'day');
}
elseif ($time_difference >= 60 * 60)
{
return get_time_ago_string($time_stamp, 60 * 60, 'hour');
}
elseif($time_difference <= 60)
{
return get_time_ago_string($time_stamp, 60, 'minute');
}
}
function get_time_ago_string($time_stamp, $divisor, $time_unit)
{
$time_difference = strtotime("now") - $time_stamp;
$time_units = floor($time_difference / $divisor);
settype($time_units, 'string');
if ($time_units === '0')
{
return 'less than 1 ' . $time_unit . ' ago';
}
elseif ($time_units === '1')
{
return '1 ' . $time_unit . ' ago';
}
else
{
return $time_units . ' ' . $time_unit . 's ago';
}
}
function convert_datetime($str) {
list($date, $time) = explode(' ', $str);
list($year, $month, $day) = explode('-', $date);
list($hour, $minute, $second) = explode(':', $time);
$timestamp = mktime($hour, $minute, $second, $month, $day, $year);
return $timestamp;
}
I have added one more function convert_datetime() which turns mysql datetime date into timestamp, as I thought the function getElapsedTime() is expecting timestamp, because when I was passing normal datetime date(mysql format), it wasn't working. So now, I am passing mysql datetime to getElapsedTime() and converting it into timestamp using convert_datetime() function and using it to get string.
But when the date is expected to return for "minute" or "second", its returning in negative value. eg its returning "-182 minutes ago" for "2013-05-23 15:59:58"..
Anybody knows how to get it done?
This is much simpler using PHP's DateTime classes:-
function time_ago($time_stamp)
{
$time = new DateTime($time_stamp);
$now = new DateTime();
$diff = $now->diff($time);
return $diff->format("%h hours, %i minutes ago");
}
$diff is an instance of DateInterval.
If you wish you can specify the format you are receiving in $time_stamp by using:-
$time = DateTime::createFromFormat('Your format here');
Obviously you can adjust the output format to suit.
// try this function
function time_ago($ptime) {
$ptime = strtotime($ptime);
if ($ptime) {
$etime = time() - $ptime;
if ($etime < 1)
return 'few seconds';
$a = array(
12 * 30 * 24 * 60 * 60 => 'year',
30 * 24 * 60 * 60 => 'month',
24 * 60 * 60 => 'day',
60 * 60 => 'hour',
60 => 'minute',
1 => 'second'
);
foreach ($a as $secs => $str) {
$d = $etime / $secs;
if ($d >= 1) {
$r = round($d);
return $r . ' ' . $str . ($r > 1 ? 's' : '') . '';
}
}
}
return '0';
}
// usage
echo time_ago('2013-05-23 15:59:58');
echo time_ago(date('Y:m:d H:i:s'));
// Output
43 minutes
few seconds
function timeago($ptime) {
$etime = time() - $ptime;
if ($etime < 1) {
return '0 seconds';
}
$a = array( 12 * 30 * 24 * 60 * 60 => 'year',
30 * 24 * 60 * 60 => 'month',
24 * 60 * 60 => 'day',
60 * 60 => 'hour',
60 => 'minute',
1 => 'second'
);
foreach ($a as $secs => $str) {
$d = $etime / $secs;
if ($d >= 1) {
$r = round($d);
return $r . ' ' . $str . ($r > 1 ? 's' : '');
}
}
}
lets say i have that function, and i have an sql result that give me an array with multiple time stamps in UNIX form. using a while loop, how can i use this function for each timestamp so each loop result would contain the time ago of each sql UNIX timestamp?
You could use DateTime class.
function timeAgo($ptime){
$date1 = DateTime::createFromFormat("s", $ptime);//HOPE THIS WILL WORK
$date2 = new DateTime("now");
$interval = $date1->diff($date2);
$diff = $interval->format('%y-%m-%d');
return $diff;
}
invoke this method on each iteration and pass in the timestamp from the DB.
I have a timestamp and would like to show my users... last sent 1 day, 23 hours, 54 minutes, and 33 seconds ago. I know how to get the difference in time...
$timePast = '2012-08-18 22:11:33';
$timeNow = date('Y-m-d H:i:s');
// gives total seconds difference
$timeDiff = strtotime($timeNow) - strtotime($timePast);
Now I am stuck not being able to show the time like above.
x day, x hours, x mins, x seconds where all the x's should add up to the total seconds time difference. I know the following...
$lastSent['h'] = round($timeDiff / 3600);
$lastSent['m'] = round($timeDiff / 60);
$lastSent['s'] = $timeDiff;
Need you help! Thanks in advance.
After this:
$timeDiff = strtotime($timeNow) - strtotime($timePast);
add:
if ($timeDiff > (60*60*24)) {$timeDiff = floor($timeDiff/60/60/24) . ' days ago';}
else if ($timeDiff > (60*60)) {$timeDiff = floor($timeDiff/60/60) . ' hours ago';}
else if ($timeDiff > 60) {$timeDiff = floor($timeDiff/60) . ' minutes ago';}
else if ($timeDiff > 0) {$timeDiff .= ' seconds ago';}
echo $timeDiff;
Don't do date math manually!
PHP can work out all of the date/time math for you, using the DateTime and DateInterval classes.
Getting an interval between two dates
$timePast = new DateTime('2012-08-18 22:11:33');
$timeNow = new DateTime;
$lastSent = $timePast->diff($timeNow);
// $lastSent is a DateInterval with properties for the years, months, etc.
Formatting example
A function for getting a formatted string might look like the following (though this is only one super-basic way, of many).
function format_interval(DateInterval $interval) {
$units = array('y' => 'years', 'm' => 'months', 'd' => 'days',
'h' => 'hours', 'i' => 'minutes', 's' => 'seconds');
$parts = array();
foreach ($units as $part => $label) {
if ($interval->$part > 0) {
$parts[] = $interval->$part . ' ' . $units[$part];
}
}
return implode(', ', $parts);
}
echo format_interval($lastSent); // e.g. 2 days, 24 minutes, 46 seconds
I took Kalpesh's code and made it work by using floor instead of round and by calculating the different frictions of the day. Here it goes:
function timeAgo ($oldTime, $newTime) {
$timeCalc = strtotime($newTime) - strtotime($oldTime);
$ans = "";
if ($timeCalc > 60*60*24) {
$days = floor($timeCalc/60/60/24);
$ans .= "$days days";
$timeCalc = $timeCalc - ($days * (60*60*24));
}
if ($timeCalc > 60*60) {
$hours = floor($timeCalc/60/60);
$ans .= ", $hours hours";
$timeCalc = $timeCalc - ($hours * (60*60));
}
if ($timeCalc > 60) {
$minutes = floor($timeCalc/60);
$ans .= ", $minutes minutes";
$timeCalc = $timeCalc - ($minutes * 60);
}
if ($timeCalc > 0) {
$ans .= "and $timeCalc seconds";
}
return $ans . " ago";
}
$timePast = '2012-08-18 22:11:33';
$timeNow = date('Y-m-d H:i:s');
$t = timeAgo($timePast, $timeNow);
echo $t;
Output:
1 days, 16 hours, 11 minutes and 18 seconds ago
You'll need a lot of if's, the modulus (%), floor() (not round())
Or Google ;-)
im having a problem converting time. for some reason it seems to be defaulting back to 1970 which i believe is unix default time. im using this code, when i run the program i get 42years instead of 2 years. what am i missing. please help
here is the code
<?php
function convertime($ptime) {
$etime = time() - $ptime;
if($etime < 60) {
return 'less than minute ag';
}
$a = array(12 * 30 * 24 * 60 * 60 => 'year', 30 * 24 * 60 * 60 => 'month', 24 * 60 * 60 => 'day', 60 * 60 => 'hour', 60 => 'minute' // 1 => 'second'
);
foreach($a as $secs => $str) {
$d = $etime / $secs;
if($d >= 1) {
$r = round($d);
return $r . ' ' . $str . ($r > 1 ? 's' : '');
}
}
}
?>
<?php
$ctime = 2009-02-23 10:09:00 //time from mysql
echo convertime($ctime);
?>
Wrap strtotime() around your timestamp:
$ctime = strtotime('2009-02-23 10:09:00'); //time from mysql
http://codepad.org/HWQrLwBy
You need to compare a timestamp to a timestamp.
<?php
function convertime($ptime) {
$etime = time() - $ptime;
if($etime < 60) {
return 'less than minute ag';
}
$a = array(12 * 30 * 24 * 60 * 60 => 'year', 30 * 24 * 60 * 60 => 'month', 24 * 60 * 60 => 'day', 60 * 60 => 'hour', 60 => 'minute' // 1 => 'second'
);
foreach($a as $secs => $str) {
$d = $etime / $secs;
if($d >= 1) {
$r = round($d);
return $r . ' ' . $str . ($r > 1 ? 's' : '');
}
}
}
?>
<?php
$ctime = strtotime('2009-02-23 10:09:00'); //time from mysql
echo convertime($ctime);
?>
try it
I want to convert a date string like "19.11.2009 14:00" into the age of it now like "for 2 minutes" or "for 1 week" or "for 2 days"
Is there some code around?
$dateString = strtotime('19.11.2009 14.00');
$now = time();
$time = $dateString - $now;
if($time > 60 && $time < 3600) echo $time/60.' minutes remaining';
else if($time > 3600 && $time < 86400) echo $time/3600.' hours remaining';
else if($time > 86400 && $time < 604800) echo $time/86400.' days remaining';
else if($time > 604800 && $time < 18144000) echo $time/604800.' weeks remaining';
else if($time > 18144000 && $time < 217728000) echo $time/18144000.' months remaining';
else if($time > 217728000) echo $time/217728000.' years remaining';
Something like this
define('MINUTE',60);
define('HOUR',60*MINUTE);
define('DAY',24*HOUR);
define('WEEK',7*DAY);
define('MONTH',30*DAY);
$pastDate=strtotime($dateString);
$seconds=time()-$pastDate;
if ($seconds>MONTH)
return $seconds/MONTH . " months";
if ($seconds>WEEK)
return $seconds/WEEK . " weeks";
if ($seconds>DAY)
return $seconds/DAY . " days";
if ($seconds>HOUR)
return $seconds/HOUR . " hours";
if ($seconds>MINUTE)
return $seconds/MINUTE . " minutes";
return $seconds . " seconds";
If you're in PHP 5.3 you could also use DateTime:diff.
$start = new DateTime('now');
$time_span = $start->diff(new DateTime($dateString));
var_dump($time_span);
This may not be 100% what you want obviously -- others have given you great answers -- but something like this may be a good alternative to a "human readable" date format.
I dug this up from some code I used quite a while ago. I haven't tested this in a while, but last I remember it worked great. I wanted to replicate something like what Facebook uses, like "5 seconds ago", but it also works for the future, using "in ..." instead of "... ago". You can probably modify this to get as much or as little detail as you want.
/**
* Returns the amount of time that has passed from the current date
* or the amount of time from the current date until the specified date
*
* Returns in the form of a partial sentence. Some examples:
*
* In 25 days
* Tomorrow
* Yesterday
* 4 months ago
* Next month
* Last month
* (etc)
*
* #param string $date
* #return string
*/
public static function calculateHowLong($date) {
// start by converting to unix time
$when = date("U", strtotime($date));
$isPast = ($when < time());
$how_long = abs(time() - $when);
if ($how_long < 60) {
$return = "{$how_long} seconds";
if ($isPast) $return .= " ago"; else $return = "In {$return}";
} elseif ($how_long < 60 * 60) {
$return = (int) ($how_long / 60) . " minutes";
if ($isPast) $return .= " ago"; else $return = "In {$return}";
} elseif ($how_long < 60 * 60 * 24) {
$return = (int) ($how_long / (60 * 60)) . " hours";
if ($isPast) $return .= " ago"; else $return = "In {$return}";
} elseif ($how_long < 60 * 60 * 24 * 2) {
if ($isPast) $return = "Yesterday"; else $return = "Tomorrow";
} elseif ($how_long < 60 * 60 * 24 * 7) {
$return = (int) ($how_long / (60 * 60 * 24)) . " days";
if ($isPast) $return .= " ago"; else $return = "In {$return}";
} elseif ($how_long < 60 * 60 * 24 * 13) {
if ($isPast) $return = "Last week"; else $return = "Next week";
} elseif ($how_long < 60 * 60 * 24 * 7 * 4) {
$return = (int) ($how_long / (60 * 60 * 24 * 7)) . " weeks";
if ($isPast) $return .= " ago"; else $return = "In {$return}";
} elseif ($how_long < 60 * 60 * 24 * 30 * 2) {
if ($isPast) $return = "Last month"; else $return = "Next month";
} elseif ($how_long < 60 * 60 * 24 * 30 * 12) {
$return = (int) ($how_long / (60 * 60 * 24 * 30)) . " months";
if ($isPast) $return .= " ago"; else $return = "In {$return}";
} else {
if ($isPast) $return = "More than 1 year ago"; else $return = "In more than 1 year";
}
return $return;
}
It's probably a little sloppy, but feel free to make it better.
I see earlier answers offering long-winded, "Write Everything Twice" (WET) instead of "Don't Repeat Yourself" (DRY) code. Worse, they are not leveraging the modern might of PHP's DateTime class. All of the obscurity and verbosity of performing mathematical calculations on unix time can be avoided. #Sergi hints in the right direction, but neglects to offer a complete solution.
Because the scope of this question states that incoming dates will be in the past and they are to be compared to the current date/time, I'll offer the following snippet to provide generalized English expressions as described in the question.
To cover cases where a number of weeks is desired, a condition needs to be implemented because the DateTime diff object does not provide a property for w (weeks). This is the only part of the snippet that requires a mathematical calculation.
Code: (Demo)
$date = '10.11.2021 14:00';
$diff = (new DateTime($date))->diff(new DateTime());
$lookup = [
'y' => 'year',
'm' => 'month',
'd' => 'day',
'h' => 'hour',
'i' => 'minute',
];
foreach ($lookup as $property => $word) {
if ($diff->$property) {
if ($property === 'd' && $diff->$property >= 7) {
$diff->w = (int)($diff->$property / 7);
$property = 'w';
$word = 'week';
}
$output = "for {$diff->$property} $word" . ($diff->$property !== 1 ? 's' : '');
break;
}
}
echo $output ?? 'for mere seconds';
Output (as table using 03.12.2021 13:00 as static current datetime):
input
output
03.12.2021 13:00
for mere seconds
03.12.2021 12:59
for 1 minute
03.12.2021 12:32
for 28 minutes
03.12.2021 11:21
for 1 hour
03.12.2021 09:12
for 3 hours
02.12.2021 02:03
for 1 day
27.11.2021 11:11
for 6 days
25.11.2021 13:11
for 1 week
04.11.2021 15:15
for 4 weeks
10.10.2021 17:59
for 1 month
27.04.2021 01:35
for 7 months
27.04.2020 01:35
for 1 year
27.04.2009 01:35
for 12 years