How to find out the number of days between two dates - php

i am trying to get number of days between two given dates, but while trying this way its not giving the number of days.
$pur_dt = date_create('2015-08-03');
$todate = date_create(date('Y-m-d'));
$diff = date_diff($todate,$pur_dt);
print_r($diff);
echo $diff->format('%R%a days');
if($diff>15) //checking condition if $pur_dt - $todate > 15
{
echo 'Hello you are not eligible';
}
else
{
echo 'eligible';
}
its not working, not giving the number of days between given two dates.


Try this. It is very simple.
<?php
$date1 = strtotime("2015-11-16 10:01:13");
$date2 = strtotime("2015-05-06 09:47:16");
$datediff = $date1 - $date2;
echo floor($datediff/(60*60*24))." days"; //output 194 days
?>


It's better using DateTime class, you can see comment(9) at PHP manual as it answer your question


Try this,
$pur_dt = date_create('2015-08-03');
$todate = date_create(date('Y-m-d'));
$datediff = $pur_dt - $todate;
$diff = $datediff/(60*60*24);
if($diff>15) //checking condition if $pur_dt - $todate > 15
{
echo 'Hello you are not eligible';
}
else
{
echo 'eligible';
}


Try This :
$pur_dt = Date('2015-08-03');
$todate = Date(date('Y-m-d'));
$pur_dt = strtotime($pur_dt);
$todate = strtotime($todate);
$seconds_diff = $todate - $pur_dt;
$$diff = floor($seconds_diff/(60*60*24));
if($diff>15) //checking condition if $pur_dt - $todate > 15
{
echo 'Hello you are not eligible';
}
else
{
echo 'eligible';
}


Try this
$pur_dt = date_create('2015-08-03');
$todate = date_create(date('Y-m-d'));
$diff = date_diff($todate,$pur_dt);
print_r($diff);
echo $diff->format('%R%a days');
if($diff->days>15) //checking condition if $pur_dt - $todate > 15
{
echo 'Hello you are not eligible';
}
else
{
echo 'eligible';
}

Related

Add 23 hrs 59 minutes as a unix time stamp in PHP

Can someone give me a working example of what my code should be as my efforts are getting me nowhere?
My code currently says have
if (isset($_POST['startdate'])) {
$startdate = DatePickerToTime($_POST['startdate']);
} else {
$startdate = strtotime('today midnight');
}
and
if (isset($_POST['enddate'])) {
$enddate = DatePickerToTime($_POST['enddate']);
} else {
$enddate = time();
}
which works.
However, I want to say if startdate is equal to enddate then add 23 hours and 59 minutes to enddate
I have read the documentation and am trying
if($_POST['$startdate'] == $_POST['$enddate']) {
$_POST['$enddate'] += date("h:i:sa", "23:59:59");
}
but this doesn't work.

$datetime1 = date('2009-10-11 12:30:00');
$datetime2 = date('2009-10-11 12:30:00');
echo "<pre>";
if($datetime1 == $datetime2){
echo "yes";
echo "<br>";
$datetime2 = date("Y-m-d H:i:s", strtotime("+23 hours 59 minutes",strtotime($datetime2)));
echo $datetime1."===================".$datetime2;
}
else {
echo "NO<br>";
echo $datetime1."===================".$datetime2;
}

check a date between two dates - PHP

I want to check a certain date that is stored in my DB, if this date is during this fiscal year it prints valid if it is not it prints invalid
here is my php code:
$init_date= date("2016/07/01");
$end_date= date("2017/06/30");
$i_date = strtotime($init_date);
$e_date = strtotime($end_date);
$date_db= strtotime($date);// this $date is retrieved from my DB
if ($e_date > $date_db && $i_date < $date_db)
{ echo "valid";}
else { echo "invalid";}
but the problem is that i don't want to set the start and the end dates manually, is there a way to make it dynamic? as it will be updated every year

This way your script will be a bit more dynamic.
// the below snippet checks the date retrieved from database
// against fiscal periods between years 2000 and 2050 and return the
// valid dates
$endYear=2000;
while($endYear<=2050) {
$end = $endYear.'/06/30';
$endDate = DateTime::createFromFormat('Y/m/d', $end);
$initDate = DateTime::createFromFormat('Y/m/d', $end);
$initDate = $initDate->sub(new DateInterval('P1Y'))->add(new DateInterval('P1D'));
$ddb = '2016-09-27';
$dateFrodDB = DateTime::createFromFormat('Y-m-d', $ddb);
if ($dateFrodDB>=$initDate && $dateFrodDB<=$endDate)
{ echo "valid\n";
echo "\tStartDate->\"".$initDate->format("Y-m-d")."\"\n";
echo "\tEndDate->\"".$endDate->format("Y-m-d")."\"\n";
echo "\tDateFromDatabase->\"".$dateFrodDB->format("Y-m-d")."\"\n";
}
$endYear++;
}
/* output
valid
StartDate->"2016-07-01"
EndDate->"2017-06-30"
DateFromDatabase->"2016-09-27"
*/
check this on PHP Sandbox

Try this,
<?php
$start_date = date('Y-m-d', strtotime(str_replace("/", "-", $initdate)));
$end_date = date('Y-m-d', strtotime(str_replace("/", "-", $end_date)));
$new_date = date('Y-m-d', strtotime(str_replace("/", "-", $date)));
if (($start_date < $new_date && $new_date < $end_date) || ($end_date < $new_date && $new_date < $start_date)) {
echo "valid";
} else {
echo 'invalid';
}
Here is working link

php date convert to seconds

I am storing the date of a post in mysql database in this form y/m/d I want to check if the post is older than 3 days. Is there any way I can convert it to seconds ? and then check like so:
if($mysql_date > $three_days_old){
echo "old post";
}else {
echo "new post";
}

Using a mix of date() and strtotime() :
$myDate = date('Y-m-d', strtotime($mysql_date));
$oldDate = date('Y-m-d', strtotime('3 days ago'));
if ($myDate > $oldDate) {
echo "old post";
} else {
echo "new post";
}

Try, strtotime, that can parse various time string formats.

You can do following :
$d1 = strtotime(date('Y-m-d', strtotime($mysql_date)));
$d3 = mktime(0, 0, 0, date('m', $d1), date('d', $d1)-3, date('Y', $d1));
$d2 = strtotime(date('Y-m-d', strtotime('3 days ago')));
if ($d3 > $d2) {
echo 'old post';
}else {
echo 'new post';
}

How to make a check if this timestamp is today,tomorrow or the day after tomorrow?

I would like to know how to check if the timestamp is today, tomorrow or the day after tomorrow.
I have e.g. :
$timestamp = "1313000474";
How to make a check if this timestamp is today,tomorrow or the day after tomorrow?
e.g.
if today then echo $output = "today";
if tomorrow then echo $output = "tomorrow";
if the day after tomorrow then echo $output = "dayaftertomorrow";
How to do this?
EDIT: corrected unix timestamp
Thank you in advance.

$timestamp = "1313000474";
$date = date('Y-m-d', $timestamp);
$today = date('Y-m-d');
$tomorrow = date('Y-m-d', strtotime('tomorrow'));
$day_after_tomorrow = date('Y-m-d', strtotime('tomorrow + 1 day'));
if ($date == $today) {
echo "today";
} else if ($date == $tomorrow) {
echo "tomorrow";
} else if ($date == $day_after_tomorrow) {
echo "dayaftertomorrow";
}

Keep your code clean...
$timestamp = "1313000474";
// Description demonstrate proposes only...
$compare_dates = array(
'today' => 'today!!',
'tomorrow' => 'Tomorrow!!!',
'tomorrow +1 day' => 'day after tomorrow? YEAH',
);
foreach($compare_dates => $compare_date => $compare_date_desc){
if(strtotime($compare_date) > $timestamp && $timestamp < strtotime($compare_date.' +1 day') ){
echo $compare_date_desc;
break;
}
}
EDIT: With this you dont have to worry if the timestamp is already without hours, minutes and seconds... Or create different output dates, replacing echo $compare_date_desc; by echo date($compare_date_desc,$timestamp);

<?php
$time = "20060713174545";
$date = date('Y-m-d', strtotime($time));
$now = date('Y-m-d');
$tomorrow = date('Y-m-d', time() + strtotime('tomorrow'));
$day_after_tomorrow = date('Y-m-d', time() + strtotime('tomorrow + 1 day'));
if ($date == $now){
echo "It's today";
}
elseif($date == $tomorrow){
echo "It's tomorrow";
}
elseif($date == $day_after_tomorrow){
echo "It's day after tomorrow";
}
else{
echo "None of previous if statements passed";
}

<?php
function getTheDay($date)
{
$curr_date=strtotime(date("Y-m-d H:i:s"));
$the_date=strtotime($date);
$diff=floor(($curr_date-$the_date)/(60*60*24));
switch($diff)
{
case 0:
return "Today";
break;
case 1:
return "Yesterday";
break;
default:
return $diff." Days ago";
}
}
?>

PHP Date Range Check

I have 2 date ranges
[contract_start_date] => 2011-10-20 [contract_end_date] => 2011-10-29
and I want to verify if the dates below are in range of the date range above
2011-05-05 and 2011-10-10
the dates given must not in any way exceed the range of the contract
Is there a function for this in PHP ?

See:: http://php.net/manual/en/datetime.diff.php
$datetime1 = new DateTime('2011-10-20');
$datetime2 = new DateTime('2011-10-29');
//PHP 5.3.0
$interval = $datetime1->diff($datetime2);
echo $interval->format('%R%a days');
//PHP 5.2.2
var_dump($datetime1 < $datetime2);
$datetime3 = new DateTime('2011-05-05');
$datetime4 = new DateTime('2011-10-10');
if ($datetime3 > $datetime1 && $datetime2 > $datetime1 && $datetime3 < $datetime2 && $datetime2 < $datetime2) {
//valid range
}//end if

$start = strtorime($contract_start_date);
$end = strtotime($contract_end_date);
$required_start = strtotime("2011-05-05");
$required_end = strtotime("2011-10-10");
if ($end > $required_end or $end < $required_start)
{
//out of range
}
if ($start < $required_start or $start > $required_end)
{
//out of range
}

This should give you exactly what you're looking for:
define(CONTRACT_START, "2011-10-20");
define(CONTRACT_END, "2011-10-29");
function checkDateRange($dateArray)
{
foreach($dateArray as $dateStr)
{
$curDate = strtotime($dateStr);
if($curDate < strtotime(CONTRACT_START) || $curDate > strtotime(CONTRACT_END))
{
return false;
}
}
return true;
}
$dates = array( 0 => "2011-10-02", 1 => "2011-10-25");
if(checkDateRange($dates))
{
echo "Dates are within range";
}
else
{
echo "Dates are NOT within range";
}

Find below code to get date difference in days, month and year:
<?php
function datediff($date1,$date2,$format='d'){
$difference = abs(strtotime($date2) - strtotime($date1));
switch (strtolower($format)){
case 'd':
$days = round((($difference/60)/60)/24,0);
break;
case 'm':
$days = round(((($difference/60)/60)/24)/30,0);
break;
case 'y':
$days = round(((($difference/60)/60)/24)/365,0);
break;
}
return $days;
}
//Example
echo datediff('2011-06-1','2010-8-30','D') . ' Days<br />';
echo datediff('2011-06-1','2010-8-30','m') . ' Months<br />';
echo datediff('2011-06-1','2010-8-30','y') . ' Years<br />';
?>

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