I'm implementing bootstrap-slider in my CRUD, I have implemented it successfully in Create, the problem is when I try to edit it,
I want to get the current value from the Model. Idk how to do this.
This is for PATCH.
<div class="form-group">
<h3 class='box-title text-info'>Percentage</h3>
{!! Form::input('text','percentage',null,['id'=>'ex8', 'data-slider-id'=>'ex1Slider', 'data-slider-min'=>'0', 'data-slider-max'=>'100', 'data-slider-step'=>'5', 'data-slider-value'=>'50']) !!}
</div>
In your form instead of creating a new form. You will bind the form to the model.
{!! Form::model('modelname', [options here] !!}
All the fields will math the model's property values.
Edit
Here is an example
You must used something like this to create a EDIT FORM
{{ Form::model($smartphones, ['method' => 'PATCH', 'url' => 'smartphones/'.$smartphones->id]) }}
You get by using $(your_model)['inputID']...You can use in "data-slider-value"... Something like this
{{ Form::input('text','mem_ram', null, ['id' => 'mem_ram', 'data-slider-value'=>$smartphones['mem_ram']]) }}
Related
I have abstracts table in my database with the Abstract_Status_ID column, I am trying to create a button that changes every Status from '2' to '3'
I have tried to do this:-
My controller
public function publish($A_ID)
{
$abstracts = Project::find($A_ID);
$abstracts->Abstract_Status_ID= 3;
$abstracts->save();
return redirect('/AdvertisedProjects')->with ('success', 'Abstracts Published' );
}
my route
Route::put( '/projects', 'AbstractsController#publish');
Route::post( '/projects', 'AbstractsController#publish');
my view (projects)
Tried with the csrf token and without as eloquent docs says any post/put will be restricted without it.
#if (count ($abstracts)> 0)
#foreach ($abstracts as $abstract)
#if($abstract->Abstract_Status_ID == 2)
{!! Form::open(['action' => ['AbstractsController#publish' , $abstract->A_ID], 'method' => 'post' ]) !!}
{{ csrf_field() }}
{{Form::hidden('_method', 'PUT') }}
{{Form::Submit('Submit Changes',['class' => 'btn btn-primary'])}}
{!! Form::close() !!}
#endif
#endforeach
The error I am getting when clicking the button
(1/1) ErrorException
Missing argument 1 for App\Http\Controllers\AbstractsController::publish()
Also, the code above will show more than one button, any suggestions to make one button change all of them ?
A: If you want to have a button for each ABSTRACTS just change your route to :
Route::put( '/projects/{A_ID}', 'AbstractsController#publish');
B: If you want to have only one button that change all , you can echo their ID in hidden input then send form
so your view would be:
#if (count ($abstracts)> 0)
{!! Form::open(['action' => ['AbstractsController#publish'], 'method' => 'post' ]) !!}
{{ csrf_field() }}
{{Form::hidden('_method', 'PUT') }}
#foreach ($abstracts as $abstract)
#if($abstract->Abstract_Status_ID == 2)
{{Form::hidden('abstract_ids[]', $abstract->A_ID) }}
#endif
#endforeach
{{Form::Submit('Submit Changes',['class' => 'btn btn-primary'])}}
{!! Form::close() !!}
And Your Controller :
public function publish()
{
foreach(request('abstract_ids') as $A_ID){
$abstracts = Project::find($A_ID);
$abstracts->Abstract_Status_ID= 3;
$abstracts->save();
}
return redirect('/AdvertisedProjects')->with ('success', 'Abstracts Published' );
}
You are using form method="POST". I think it should be method="PUT".
The main problem in your code is the definition of your routes, You are passing an argument ($A_ID) to the controllers publish method,
But in your routes, you did never mention that you are passing any argument through your route. So for passing the argument, you can use {$A_ID} in your route URL.
One thing you should always remember is that you should always give your route a name and call it by using its name and route() Laravel helper method.
The benefit of using route name is that if you decide to change the URL-Structure of your route later in the development process, you'll never have to change it everywhere in your application because you did not call it by its URL.
And route name is less error prone
In total, You should define your routes like this
Route::put('projects/{A_ID}/update', 'AbstractsController#publish')->name('projects.update');
Route::post('projects/{A_ID}/post', 'AbstractsController#publish')->name('projects.store');
Then in you blade files now you can call it like
{!! Form::open(['action' => route('projects.store', $abstract->A_ID), 'method' => 'post' ]) !!}
Hope this will clarify and resolve your problem.
I got a weird behaviour with the 'old value' feature from FormBuilder in Laravel 5.1.
On my blade template I use a simple text input:
{!! Form::open([ 'url' => route('album-photo'), 'method' => 'POST' ]) !!}
{!! Form::text('album_id', $album_id) !!}
{!! Form::close() !!}
On my controller I show the view:
$album_id = 1;
return view( $name_view, compact( 'album_id' ) );
The problem is that, even though I change the album_id value on my controller, the form builder on my view will keep printing the first value.
While if I use the normal html tag:
<input type="text" name="album_id" value="{{ $album_id }}" />
it will print the updated value.
So it looks like the FormBuilder class is getting the value from the old session and it can't manage the refreshing of the value.
Is there a way to fix it and keep using the FormBuilder methods instead of plain html?
I have seen similar questions asked before, but was unable to find a solution to my problem. So I have a ClientController and within it this function
public function edit(Client $client)
{
return view('clients.edit', compact('client'));
}
So that passes the client object to my edit view. This view is pretty much the following
{!! Form::model($client, ['method' => 'PATCH', 'route' => ['clients.update', $client->slug]]) !!}
#include('clients/partials/_form', ['submit_text' => 'Edit Client'])
{!! Form::close() !!}
So it is using a partial for the form. At the moment, the partial looks like so
<div class="form-group">
{!! Form::label('clientName', 'Client Name:') !!}
{!! Form::text('clientName') !!}
</div>
<div class="form-group">
{!! Form::label('clientStatus', 'Client Status:') !!}
{!! Form::select('clientStatus') !!}
</div>
When I visit the edit page for a client, I can see the form. The clientName is populated with the clientName value. The clientStatus is populated if I put it as a text input, but I cant get it to populate within a select as shown above. Furthermore, clientStatus can either be New or Existing. I need the select box to be pre-populated with the status of the client that is being edited, but I need the other option available within the select as well. So if the clientStatus is New, New should be pre-selected within the select box and if I open the select, Existing should be the other option.
What would be the best way to achieve this?
Thanks
Modify your select to include an array of the possible values.
Basic Select - Label is value
{!! Form::select('clientStatus',['New','Existing']) !!}
Key Value Select - Key is value
{!! Form::select('clientStatus',[ 1 => 'New', 2 => 'Existing']) !!}
Form model will then set the value in the select to the one in the model.
More information see the docs.
I want to create a two buttons buyer and seller in the home page, and on click of these buttons, I want the guest to get directed register page with a ~hidden input~ placed in the form depending on the value of the button pressed.
I am using Laravel 5.1
For what I am trying to achieve, do I need to register a new route and a new function?
First, do I need to use a {!! link_to !!} or {!! Form submit !!}. I thought form submit would work:
{!! Form::open(array('url' => '/auth/register', 'profession' => 'seller')) !!}
{!! Form::submit('Seller', array('class' => 'btn btn-warning')) !!}
{!! Form::close() !!}
My routes are:
Route::get('auth/register', 'Auth\AuthController#getRegister');
Route::post('auth/register', 'Auth\AuthController#postRegister');
auth/register and AuthController is the one that comes with Laravel default. I also didn't register a new public function. Is this the reason? Do I need to send the data from view to controller and then other view (view->controller->view). I am really confused on this one.
This is how it seems in the view-source:
<form method="POST" action="http://app.com/auth/register" accept-charset="UTF-8" profession="seller"><input name="_token" type="hidden" value="Cw4Het1A1M6020oQL45Cy2Q0ct46TSe6ba2g4r4C">
<input class="btn btn-warning" type="submit" value="Seller">
</form>
Edit:
I think I can't send variables between views. So do I need to register a completely new route and a controller, and two methods in it? I am really confused on this stage.
Check out my answer to your previous similar question for details on the implementation:
Laravel Passing Data From One View to Another View
To answer the questions you are posing
You can use two forms one for buyer and one for seller
{!! Form::open(['route' => ['type_path']]) !!}
{!! Form::hidden('type', 'buyer') !!}
{!! Form::submit('Buyer', array('class' => 'btn btn-warning')) !!}
{!! Form::close() !!
{!! Form::open(['route' => ['type_path']]) !!}
{!! Form::hidden('type', 'seller') !!}
{!! Form::submit('Seller', array('class' => 'btn btn-warning')) !!}
{!! Form::close() !!
on your landing page and then have both of this forms direct to a same named route (in this case 'type_path')
Then in your routes.php file you would reference only one controller and one method and handle the logic in that method. Again see the link to my answer to see a full implementation of this for the example of writer and reader.
Essentially as you say, you'd be sending as the hidden inputs from the view to the controller to the second view.
You could register a new route like:
Route::get('auth/{TYPE}/register', 'Auth\AuthController#getRegisterType')
Your home page would have something like this:
seller
Your controller method would be something like this:
public function getRegisterType($type)
{
Session::put('registerType', $type);
return redirect('/auth/register');
}
Then you can access you set session variable from the controller methods getRegister & postRegister
Have you two buttons direct to the register page with a query string parameter:
Buyer
Seller
And then just check for the query string parameter in your register.blade.php view:
{!! Form::hidden('account_type', Request::query('type')) !!}
If you need to validate one of the two is present, then you could create a middleware class you apply to the login route only:
public function handle($request, Closure $next)
{
if (! in_array($request->query('type'), ['buyer', 'seller'])) {
// Error
}
return $next($request);
}
I use laravel presenters from laracasts video. Basically it doesn't matter that much. What I want is to format output data when I use Form::model. So, for example, I have a phone number input:
<div class="form-group">
{!! Form::label('phone', 'Phone' ) !!}
{!! Form::text('phone', null, ['class' => 'form-control', 'id' => 'phone']) !!}
</div>
In the DB I store phones in e.164 format, but when I output them I want to display them in more readable format. But data-accessors from Laravel won't help me because inside my application I want to use e.164. If I set accessor for phone attribute than I won't be able to get e.164 inside my classes. So, instead of accessors I user presenters, but it doesn't matter that much. Let's say I want to use php number_format function when outputting model attributes inside Form::text. How can I do that?
There's nothing forcing you to have a one to one accessor to field relationship. So you can create a formatted phone attribute to use in the form, and use the phone attribute directly from within your classes.
public function getFormattedPhoneAttribute()
{
return // formatted $this->phone
}
If you already have the presenters set up then you can use them in your form instead of using Form::model.
<div class="form-group">
{!! Form::label('phone', 'Phone' ) !!}
{!! Form::text('phone', $user->present()->phone, ['class' => 'form-control', 'id' => 'phone']) !!}
</div>
Either one of these should work for you, but I would recommend you choose one: Accessors or Presenters, not both.