php update record repeat region [closed] - php

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As previously stated in my last question on WHAT a cron job is, I'm now trying to write one but seem to get a problem. This is the closest I've gotten. I want to update every record in the database by one more than what it already has.
Example if the field is 30, then when this script is run then it will become 31. But I have MULTIPLE fields and I want all of them to increment by one.
This is what I've currently wrote, but it doesn't work, but I DO get an echo of "Record Updated Successfully" but nothing changes. If I change it so that $Age = $Test and then I plug in a random number for the ID it will end up equaling Test. If I have it say $Age = $NewAge and the random ID, it changes the variable in my database to be 302. I have NO clue where it's pulling that random 302.
Any suggestions?
This is my code below:
<?php
$servername = "localhost";
$username = "root";
$password = "root";
$dbname = "RR";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sqlSelect = "SELECT id, Age FROM Horse";
$result = $conn->query($sqlSelect);
do{
$id = $row['id'];
$Age = $row['Age'];
$NewAge = $Age + 1;
$Test = 200;
echo $id, ' ', $Age, ' ', $NewAge; ?> <br/>
<?php
$sqlUpdate = "UPDATE Horse SET Age='$NewAge' WHERE id='$id'";
}
while($row = $result->fetch_assoc());
if ($conn->query($sqlUpdate) === TRUE) {
echo "Record updated successfully";
} else {
echo "Error updating record: " . $conn->error;
}
$conn->close();
?>

Answer 1

The question is very vague and hard to understand, but as #rjdown said, this will update ALL rows in the database and increment Age by 1.
Note: there is no need for fetching the records from database, nor looping over them. Just one line of SQL will update ALL rows.
<?php
$servername = "localhost";
$username = "root";
$password = "root";
$dbname = "RR";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sqlUpdate = "UPDATE Horse SET Age = Age + 1";
if ($conn->query($sqlUpdate) === TRUE) {
echo "All records updated successfully";
} else {
echo "Error updating record: " . $conn->error;
}