I'm writing a webpage, and am trying to use php to check a value after a form submits. The php is in the same page, as seen below. The $_POST variable is coming in empty after the submit code comes in though. I've looked at the other posts about this question but none of those answers seem to help.
Thanks for looking
<?php
session_start();
require_once 'assets/PHP/membership.php';
$membership = new Membership();
var_dump($_SESSION);
var_dump($_POST);
if($_POST && !empty($_POST['username']) && !empty($_POST['pwd']))
{
$response = $membership->validate_user($_POST['username'], $_POST['pwd']);
}
?>
<!DOCTYPE html>
<html lang="en">
<head>
</head>
<div id="login">
<form method="post" action = "">
<h2>LOG IN:</h2>
<label>User Name :</label>
<input type="text" name="username" id = "username"/>
<label>Password :</label>
<input type="password" name="pwd" id = "pwd"/>
<input type="submit" value="Login" id="submit" name="submit"/>
</form>
</div>
</html>
I'm very new to HTML and PHP so any help I could get would go a long way.
For anyone who is curious, I solved this by finding this reddit link: https://www.reddit.com/r/PHPhelp/comments/3uxapu/phpstorm_local_php_5616_post_always_empty/
All my superglobals were coming in blank. I'm not even sure why quite yet, I still need to read more about it. The following code snippet got me the results I needed:
$post_data = file_get_contents('php://input');
Post data now contains what I wanted to get from $_POST.
Thanks to everyone who tried to help me here!
If you want print $_post thn use code this....
If(isset($_POST['submit'])){
Print_r($_POST);
}
It's because, if you want to print data from form then you must submit the form first then you'll be able to get data in $_post.....
Related
<!DOCTYPE html>
<html>
<body>
<form action="test.php" method="post">
<input name="test" type="text">
<input type="password" name="data">
<input type="submit">
</form>
</body>
</html>
<?php
if($_SERVER['REQUEST_METHOD'] == 'POST'){
$name = $_POST['test'];
$pass = $_POST['data'];
}
?>
I am trying to make a simple form in PHP that users will use for login. When using this code, nothing ever gets put inside the $_POST. I am debugging using PHPstorm and I can tell that the request method is definitely POST, but no data is getting passed through. What am I doing wrong?
Try adding a slash at the begening of the action parameter of the form tag.
<form action="/test.php" method="post">
Try to remove "action" from form. It worked for me.
Code: http://nimb.ws/6pXjnz
Output:http://nimb.ws/PvuxZs
I'm working on a database-driven quiz that lets users select a series of answers, then submit the results via a form. It was working great, when it suddenly blew up, and I haven't been able to find the problem.
So before I get into the more complex stuff, I'd like to go back to square one and just make something simple work - like passing a hidden value to another page that echoes that value.
Here's the code for my first page # mysite/form.php:
<html>
<head>
</head>
<body>
<!-- g1/form.php -->
<div id="quiz" rel="key">
<form action="form2.php" method="post" id="quiz">
<input type="hidden" name="PreviousURL" id="url" />
<input type="submit" value="Submit Quiz" />
</form>
</div><!-- quiz-container -->
</body>
</html>
And here's the code for the second page:
<html>
<head>
</head>
<body>
<?php ini_set('display_errors', 1);
if ($_SERVER['REQUEST_METHOD'] == 'POST') {
echo $_POST['PreviousURL'];
}
echo 'XXX';
?>
</body>
</html>
I also tried moving the closing bracket, like this:
if ($_SERVER['REQUEST_METHOD'] == 'POST') {
}
echo $_POST['PreviousURL'];
echo 'XXX';
In both cases, when I click the submit button and am forwarded to form2.php, I see "XXX," but there's no value for $_POST['PreviousURL'].
I must have accidentally deleted or modified something, because it seems so simple, and it worked fine before. Can anyone tell me what the problem is?
there isn't a value for the hidden input.
In your form script you have missed out the value="" from the hidden input. This is the reason why nothing is displaying on the second page.
I'll preface this with I'm not a coder nor aspiring to become one.
I just want to play around with something simple.
Please don't feel bad about spoon-feeding me here haha.
All I want is when I hit a my submit button the text entered in the text field is saved to a file called log.text
I want it to overwrite each time.
Once data has been written I want it to redirect to another page.
Tried this but it doesn't create the file nor write to it even if I create it manually. The redirect also doesn't work because I'm an idiot.
Any help guys? :(
<?php
$email = $_REQUEST['email'];
$file = fopen("log.txt","a+");
fwrite($file,$email);
print_r(error_get_last());
header("Location: http://www.example.com/");
?>
<form action= "" method="post" name="form">
<input type="text" name="email">
<br>
<br>
<input type="submit" name="submit" value="submit"><br>
</form>
It is because the action element of the form is empty.
It should be \n
<form action="action.php(or any other php file that is handling the form)" method="post" name="form">
This guide offered me the solution I was after.
Thanks anyway guys!
http://www.howtoplaza.com/save-web-form-data-text-file
Because you dint checked whether the form is submitted or not. if submited create log. code given below
<?php
if(isset($_REQUEST['submit']))// if to check whether submit name is passed or not
{
$email = $_REQUEST['email'];
$file = fopen("log.txt","a+");
fwrite($file,$email);
print_r(error_get_last());
header("Location: http://www.example.com/");
}
?>
<html>
<form action= "" method="post" name="form">
<input type="text" name="email">
<br>
<br>
<input type="submit" name="submit" value="submit"><br>
</form>
</html>
Sorry if this is a duplicate, but I really cant find anything that could solve my problem. I can pass numbers and strings like $_SESSION['blabla']="123'; but I can't pass this $_POST value from the textfield and submit button.
Page 1 (sessions.php)
<?php session_start(); ?>
!doctype stuff here
<body>
<form id="form1" name="form1" method="post" action="sessions2.php">
<label>
<input type="text" name="damn" id="damn" />
<input type="submit" name="submit" id="submit" value="Submit" />
</label>
</form>
<?php
$omg = $_POST['damn'];
$_SESSION['damn'] = $omg;
echo $_SESSION['damn'] ;
?>
Page 2 (sessions2.php)
<?php
session_start();
$fires = $_SESSION['damn'];
echo "wth";
echo $_SESSION['damn'];
?>
PS. Sorry for the names.. I'm truly stumped.
You need to put the code that reads from $_POST in the file that you submit the form to.
Currently your process is:
Get request for sessions.php
Send form to browser
Assign $_POST['damn'] (which is undefined) to the session.
User submits form
Get request for sessions2.php
Ignore $_POST (which is now populated)
Read from the session (where the variable is still undefined).
damn is populated in the form submission request (step 4/5) not the request where you are trying to read it (step 1).
In sessions2.php
// you POST "damn" variable via form, using post method, so:
$fires = $_POST['damn'];
// and:
$_SESSION['damn'] = $fier;
// or
$_SESSION['damn'] = $_POST['damn'];
PHP code in file sessions.php doesn't work, because in form action you have session2.php.
I have a PHP form that is located on file contact.html.
The form is processed from file processForm.php.
When a user fills out the form and clicks on submit,
processForm.php sends the email and direct the user to - processForm.php
with a message on that page "Success! Your message has been sent."
I do not know much about PHP, but I know that the action that is calling for this is:
// Die with a success message
die("<span class='success'>Success! Your message has been sent.</span>");
How can I keep the message inside the form div without redirecting to the
processForm.php page?
I can post the entire processForm.php if needed, but it is long.
In order to stay on the same page on submit you can leave action empty (action="") into the form tag, or leave it out altogether.
For the message, create a variable ($message = "Success! You entered: ".$input;") and then echo the variable at the place in the page where you want the message to appear with <?php echo $message; ?>.
Like this:
<?php
$message = "";
if(isset($_POST['SubmitButton'])){ //check if form was submitted
$input = $_POST['inputText']; //get input text
$message = "Success! You entered: ".$input;
}
?>
<html>
<body>
<form action="" method="post">
<?php echo $message; ?>
<input type="text" name="inputText"/>
<input type="submit" name="SubmitButton"/>
</form>
</body>
</html>
The best way to stay on the same page is to post to the same page:
<form method="post" action="<?=$_SERVER['PHP_SELF'];?>">
There are two ways of doing it:
Submit the form to the same page: Handle the submitted form using PHP script. (This can be done by setting the form action to the current page URL.)
if(isset($_POST['submit'])) {
// Enter the code you want to execute after the form has been submitted
// Display Success or Failure message (if any)
} else {
// Display the Form and the Submit Button
}
Using AJAX Form Submission which is a little more difficult for a beginner than method #1.
You can use the # action in a form action:
<?php
if(isset($_POST['SubmitButton'])){ // Check if form was submitted
$input = $_POST['inputText']; // Get input text
$message = "Success! You entered: " . $input;
}
?>
<html>
<body>
<form action="#" method="post">
<?php echo $message; ?>
<input type="text" name="inputText"/>
<input type="submit" name="SubmitButton"/>
</form>
</body>
</html>
Friend. Use this way, There will be no "Undefined variable message" and it will work fine.
<?php
if(isset($_POST['SubmitButton'])){
$price = $_POST["price"];
$qty = $_POST["qty"];
$message = $price*$qty;
}
?>
<!DOCTYPE html>
<html>
<head>
<title></title>
</head>
<body>
<form action="#" method="post">
<input type="number" name="price"> <br>
<input type="number" name="qty"><br>
<input type="submit" name="SubmitButton">
</form>
<?php echo "The Answer is" .$message; ?>
</body>
</html>
You have to use code similar to this:
echo "<div id='divwithform'>";
if(isset($_POST['submit'])) // if form was submitted (if you came here with form data)
{
echo "Success";
}
else // if form was not submitted (if you came here without form data)
{
echo "<form> ... </form>";
}
echo "</div>";
Code with if like this is typical for many pages, however this is very simplified.
Normally, you have to validate some data in first "if" (check if form fields were not empty etc).
Please visit www.thenewboston.org or phpacademy.org. There are very good PHP video tutorials, including forms.
You can see the following example for the Form action on the same page
<form action="" method="post">
<table border="1px">
<tr><td>Name: <input type="text" name="user_name" ></td></tr>
<tr><td align="right"> <input type="submit" value="submit" name="btn">
</td></tr>
</table>
</form>
<?php
if(isset($_POST['btn'])){
$name=$_POST['user_name'];
echo 'Welcome '. $name;
}
?>
simple just ignore the action attribute and use !empty (not empty) in php.
<form method="post">
<input type="name" name="name">
<input type="submit">
</form>
<?PHP
if(!empty($_POST['name']))
{
echo $_POST['name'];
}
?>
Try this... worked for me
<form action="submit.php" method="post">
<input type="text" name="input">
<input type="submit">
</form>
------ submit.php ------
<?php header("Location: ../index.php"); ?>
I know this is an old question but since it came up as the top answer on Google, it is worth an update.
You do not need to use jQuery or JavaScript to stay on the same page after form submission.
All you need to do is get PHP to return just a status code of 204 (No Content).
That tells the page to stay where it is. Of course, you will probably then want some JavaScript to empty the selected filename.
What I do is I want the page to stay after submit when there are errors...So I want the page to be reloaded :
($_SERVER["PHP_SELF"])
While I include the sript from a seperate file e.g
include_once "test.php";
I also read somewhere that
if(isset($_POST['submit']))
Is a beginners old fasion way of posting a form, and
if ($_SERVER['REQUEST_METHOD'] == 'POST')
Should be used (Not my words, read it somewhere)