I'm currently running a cron job that loads a php script.
I keep getting an error, sh 1 /usr/bin/php: not found.
I tried it two other ways but to no avail.
on a perl script. I tried.
my $x = qx('/usr/bin/php /home/script.here');
This doesn't generate anything and sends me an error message on my mail.
But if I run the line
/usr/bin/php /home/script.here
on my shell, it works.
I also create a script 1.sh and had this.
#!/usr/bin/php -v
I run the script ./1.sh and it shows the result. But as soon as I try to call it via cron or /bin/sh 1.sh, it just fails and can't find the php path even if it was explicitly stated.
Am I missing anything?
I also tried this on php5, but same error.
The problem are the single quotes inside the qx() operator. Remove them:
my $x = qx(/usr/bin/php /home/script.here);
As long as they are there the shell tries to find a command "script.here" in the directory "/usr/bin/php /home" (yes, with the space in the directory name).
Totally forgot about this question.
Found a solution.
I just added
SHELL=/bin/bash in crontab and the scripts worked.
Related
I'm new to linux system and I'm trying to make a PHP script to be ran infinite times. Note that I'm using Debian 7.
So, I'm using a screen to open a window, so far so good, I have the worker.php file already running succsefully, and I need to make shell script which runs the php script infinite times.
So I've come up with this:
#!/bin/sh
for (( ; ; ))
do
/usr/bin/php worker.php
sleep 1
done
The problem is , when trying to run ./worker.sh in the screen , I get this error:
bash: ./worker.sh: /bin/sh^M: bad interpreter: No such file or directory
So I've stripped of the for, and replaced it with a simple echo , which results into the same error, so I've wrote this question because I don't know what's wrong, both sh or bash exist on the server, I'm wondering if the shebang is wrong but.. I have the automysqlbackup script which starts with the same shebang.
Do you have any idea what is wrong ? I'm just a newb.. don't really know much.
If you're wondering why am I running a file every second, it's because this file serves as a commands processor from a queue in a game. And running it with cron every minute is too slow. MySQL triggers are not fitting my needs, so I'm forced doing this.
Regards.
From the message it looks like you have a <cr><lf> at the end of your shebang line (the #! one). As isn't a valid line end on debian unix (it is on windows and some other varieties of unix), it is being taken as part of the filename, and so the o/s can't find the program to run.
Fixing it would require something like this:
tr -d '\015' < worker.sh > worker_nocr.fixed
Also, as you're using bash as your shell, you might wish to change the shebang to use bash as well, or other things might not work which work fine when you type them in at the command prompt
I have tried to use exec() with 'whoami' to check if it works and I got the result of
nt authority\system
Now I need to run a .exe file with parameters from php via exec() function.
I tried this in command prompt and it actually runs the program with given parameters. This is the example command.
NOTE the exe file gets 3 inputs (folder, file_name, report_file_nmae)
> ..\..\some_file.exe folder="C:\path_to_folder" param=1.xml report=2.xml
But when I run this command from php file:
exec('..\..\some_file.exe folder="C:\path_to_folder" param=1.xml report=2.xml');
nothing is happening. This is the first time I am using exec() function, so I am not familiar with its details. What is wrong?
I tried using:
\\ instead of \
escapeshellarg() on the directory
added "" around directory folder names
No luck
Addendum:
echo exec($command) // echos < .... why?
or
exec($command, $output);
print_r($output); // Array()
I even changed the permission on the file to full control to all users.
If I call the program from command prompt, I can see the icon appearing next to clock for a second.
But the same call from php will not even call the program.
Edit
Even exec('notepad.exe'); is not working. Something has to be done with php configurations maybe?
I already said that I was new to exec() function. After doing some more digging, I came upon 2>&1 which needs to be added at the end of command in exec().
Thanks #mattosmat for pointing it out in the comments too. I did not try this at once because you said it is a Linux command, I am on Windows.
So, what I have discovered, the command is actually executing in the back-end. That is why I could not see it actually running, which I was expecting to happen.
For all of you, who had similar problem, my advise is to use that command. It will point out all the errors and also tell you info/details about execution.
exec('some_command 2>&1', $output);
print_r($output); // to see the response to your command
Thanks for all the help guys, I appreciate it ;)
You might also try giving the full path to the binary you're trying to run. That solved my problem when trying to use ImageMagick.
One of my lines of shell command is not executing despite other similar lines working. I am running on a linux machine using a Ubuntu 12.04 based OS. I have tried using exec as well, still doesn't work.
I actually had this working at some point, where I ran into the hanging issue (waiting for command output), which is why I'm redirecting output to /dev/null. So some where in the development something changed. We did create a debian package to install with and I had run that install package so I thought maybe in overwriting a file the permissions got changed so I added read/write/execute to all users/groups/owners but that didn't work either.
The code is here:
if(isset($_POST['activateXML']))
{
if (videoConsistencyCheck())
{
`cp {$fileXML} /apps/video/xml.xml`;
`sudo /apps/video/vsss restart >/dev/null 2>&1 &`;
systemUnvalidate();
header('Location: index.php?app='.$_GET['app']);
die();
}
}
I know that the first line in the if statement gets executed. The line of code works fine in the actually terminal, so that isn't the problem either. I did lots of Googling and all I could find is an unanswered question, any advice would be helpful.
EDIT: so what appeared to be not working was in fact calling the command as intended but in the bash script I was calling the start-stop daemon was not working
EDIT 2: I made a test php file and ran the code from the terminal, fixed the start-stop-daemon error by adding sudo to the commands but it still doesn't work in my code. I am calling this code when a submit button is pressed.
use additional parameters, especially output:
exec($command,$output);
var_dump($output);
to determine what can be wrong with your command. If it doesn't work, please show us your code where you use your exec's.
The issue lay with a call to a binary file in the vsss script that could only be run as root. We did not want to allow access to that binary file to just anyone. The solution we came up with involves calling chmod +s on the vsss script which allows permissions for user and group IDs but keeps its owner permissions. We then added the PHP user, which was www-data, to the sudoers file using the NOPASSWD parameter. In my PHP code I then used the line:
exec('sudo /apps/video/vsss restart >/dev/null 2>&1 &')
The shell_exec()/backticks would not work with this method.
I am attempting to create a php script that can connect thru ssh to my Qnap TS219 server and run a command on it.
My script so far connects fine to the server but when I run the command I get an error message and I can't figure it out.
exec.sh
#!/bin/bash
cp /share/MD0_DATA/Qdownload/rapidshare/admin/script.txt /share/MD0_DATA/Qdownload/rapidshare/admin/script.sh
chmod 755 /share/MD0_DATA/Qdownload/rapidshare/admin/script.sh
nohup sh /share/MD0_DATA/Qdownload/rapidshare/admin/script.sh &
exit 0
script.sh
#!/bin/bash
/opt/bin/plowdown -o /share/MD0_DATA/Qdownload/rapidshare /share/MD0_DATA/Qdownload/rapidshare/admin/down.txt 2>/share/MD0_DATA/Qdownload/rapidshare/admin/output.txt
the command that I am currently running thru ssh after I submit the form:
echo $ssh->exec('sh /share/MD0_DATA/Qdownload/rapidshare/admin/exec.sh');
Right now generates the code below but only after I kill 2 bash processes (the page keeps loading indefinetly and the processor activity is at 100% if I don't kill the 2 bash processes):
/share/MD0_DATA/.qpkg/Optware/share/plowshare/lib.sh: line 261: getopt: command not found start download (rapidshare): http://rapidshare.com/files/312885386/Free_Stuff-Your_Internet_eBay_Business_Free_Startup_Resources.rar /share/MD0_DATA/.qpkg/Optware/share/plowshare/lib.sh: line 261: getopt: command not found /share/MD0_DATA/.qpkg/Optware/share/plowshare/lib.sh: line 46: --insecure: command not found Error: failed inside rapidshare_download()
This script will be used in my local network, no access from outside, so I am not worry about security, I know the code looks very basic, primitive but I have no experience with php, shell script, so if someone can make any sense on this and help me out will be greatly appreciated.
Edit1. I also tried the shell_exec command still no joy and if I run the script thru putty works beautifully.
Edit2. I think we are on to something.
I added the code you suggested and I got the following message.
sh: /share/MD0_DATA/.qpkg/Optware/share/plowshare: is a directory /usr/bin:/bin:/usr/sbin:/sbin
I think at the moment the PATH is usr/bin:/bin:usr/sbin:/sbin and I think it should be /opt/bin /opt/sbin because there are the "executables". Any ideeas?
Thanks,
Chris.
Run this
echo $ssh->exec('pwd');
Does it list your path correctly? If so then your problem is NOT PHP, if it doesn't list or still gives an error then PHP is your problem and we can continue from there.
From the error you've listed, my first guess would be that PATH isn't set, so lib.sh can't find what it's looking for.
Remember you're logging in with a custom shell (PHP ssh), quite often things aren't set as they should be, so your scripts might not find requirements like paths and variables.
Edit:
Since it's giving /root, we at least know it's going through, why not also set the PATH etc...
echo $ssh->exec('PATH=$PATH;/share/MD0_DATA/.qpkg/Optware/share/plowshare; sh /share/MD0_DATA/Qdownload/rapidshare/admin/exec.sh');
Remember you can also use this to see what is and isn't being set.
echo $ssh->exec('ECHO $PATH');
I think I got it:
Following viper_sb logic, I changed the code to:
echo $ssh->exec('PATH=$PATH:/share/MD0_DATA/.qpkg/Optware/bin; sh /share/MD0_DATA/Qdownload/rapidshare/admin/exec.sh');
echo $ssh->exec('echo $PATH');
and magic, it worked ... I'll test it further, when I get home, but I think it worked, a file was downloaded in the /Qdownload/rapidshare folder ... hooray.
I wrote a script to parse some data from a website using cURL and it works fine when I run it in my browser, however when I want to run it in the command line I get the error "call to undefined function curl_init()". Do php scripts run under different settings from the command line?
This is happening because you are simply trying to call a PHP function from bash. If you have curl installed in your linux environment then the command should simply be curl [-options] [url]. The simplest of them being something like:
$ curl http://someurl.com/path/to/xmlfile.xml
You can test for this from the command line by tying "$ which curl" (without the quotes of course). That will give you the path to where it is stored in case you have to use the full path. (e.g. /usr/bin/curl [-options] [url]).
EDIT:
after having re-read your question I realized that I dumbly missed the fact that you said you were trying to run the PHP script from the command line and not curl itself. And now I, too, am stumped by your problem. Sorry!