I have a simple register form where the user can upload a profile picture, if the user doesn't it, it should take the default picture name called person-icon.png.
When I register an user and upload a picture it works but if i leave it blank don't do anything and that column is inserted into the DB empty
if(isset($_FILES['image'])){
$img = $_FILES['image']['name'];
}
else if(empty($_FILES['image']['name'])){
$img = 'person-icon.png';
}
I already have tried these options:
Option 1:
if (empty($_FILES['image'])){
$img = 'person-icon.png';
}
else{
$img = $_FILES['image']['name'];
}
Option 2:
if($_FILES["image"]["error"] == 4)
Option 3:
if($_FILES["image"]["name"] == "")
You could check for $_FILE['image']['name'] not equal "" this work;
See code:
<!DOCTYPE html>
<html>
<body>
<form action="upload.php" method="post" enctype="multipart/form-data">
Select image to upload:
<input type="file" name="image" id="image">
<input type="submit" value="Upload Image" name="submit">
</form>
</body>
</html>
<?php
//var_dump($_FILES);
$default_pic =" pic.png";
if (isset($_FILES['image'])){
if($_FILES['image']['name'] != ""){
echo "has pic";
}
else{
$_FILES['image']['name'] = $default_pic;
echo "has no pic";
}
}
?>
In order to check if a file has been uploaded you have to look for the tmp_name, because that is what contains the actual copy of your file content on the server.
I would do something like this:
$file = $_FILES['file']['tmp_name'];
if (!file_exists($file)){
//no image
}
else{
//image
}
You can also check $_FILES as long you don't upload other files in that form:
if(empty($_FILES)){
//no image
}
else{
//image
}
For further information check the official manual of file uploads.
I hope this helped you :)
Related
I am attempting to create a form which allows the renaming of a selected file within the form, before submitting the upload.
I created the form with a 'text' field named "new_fileName" in addition to the file-picker.
On the upload.php side, I changed the variable to $newname, and tried a few ways to use that to change the name of the uploaded file. Including using it to replace the ['name'] part of the $filename variable. But so far, no success with anything.
FORM
<!DOCTYPE html>
<html>
<head>
<title> Rename and Upload Form </title>
</head>
<body>
<form action="upload.php" method="post" enctype="multipart/form-data" >
<input type="file" name="file" id="file" />
<br><br>
<input type="text" name="new_fileName" placeholder="Rename File"/>
<br><br>
<input type="submit" value="Rename and Upload" />
</form>
</body>
</html>
upload.php
<?php
$newname = $_POST['new_fileName'];
$filename = $_FILES['file']['name'];
$location = "upload/".$filename;
if( move_uploaded_file($_FILES['file']['tmp_name'], $location)){
echo 'File uploaded successfully';
}else{
echo 'Error uploading file';
}
?>
After a bit of tinkering with the 'upload.php' page, this is what ended up working to change the name of the file before submitting the upload form.
This code also adds the file-type extension to the new file name.
(New) upload.php
<?php
$filename = $_POST['new_fileName'];
$name = $_FILES["file"]["name"];
$ext = end((explode(".", $name)));
if($_SERVER["REQUEST_METHOD"] == 'POST') {
if ($_FILES['file']['error'] > 0) { echo 'Error: ' . $_FILES['file']
['error']; }
if (file_exists('upload/' . $_FILES['file']['name'])) { unlink
('upload/' . $_FILES['file']['name']); }
move_uploaded_file($_FILES['file']['tmp_name'], 'upload/' . $_POST =
$filename . "." . $ext);
echo 'File uploaded successfully' ; }
else { echo 'Error uploading file'; }
?>
I would like to display an image stored in my database but I keep getting that error.
The image is stored in my database as longblob.
I upload it using this piece of code in upload.php:
<body>
<form action="upload.php" method="post" enctype="multipart/form-data">
Select image to upload:
<input type="file" name="image" />
<input type="submit" name="submit" value="UPLOAD" />
</form>
<?php
if (isset($_POST["submit"])) {
$check = getimagesize($_FILES["image"]["tmp_name"]);
if ($check !== false) {
$image = $_FILES['image']['tmp_name'];
$imgContent = addslashes(file_get_contents($image));
/*
* Insert image data into database
*/
//Insert image content into database
$insert = $pdo->query("UPDATE users SET image='".$imgContent."'"."WHERE id_user = ".$posts[0]->get_id());
if ($insert) {
echo "File uploaded successfully.";
} else {
echo "File upload failed, please try again.";
}
} else {
echo "Please select an image file to upload.";
}
}
?>
Then I try to display it in getImage.php:
<?php
$id = $_GET['id'];
$query = $pdo->prepare('SELECT * FROM users WHERE username LIKE :us');
$query->bindValue(':us', $_SESSION['login'], PDO::PARAM_STR);
$query->execute();
$user = $query->fetchAll(PDO::FETCH_CLASS, "User");
header ('Content-Type: image/png');
echo $user[0]->get_image();
?>
When I go however to /getImage.php?id=1, I have the error
The image cannot be displayed because it contains errors
What am I doing wrong?
Solved: I added ob_end_clean(); before the header and it worked.
Hi I'm new to php and keep getting this error: "Warning: Invalid argument supplied for foreach() in /home/site/folder/upload.php on line 61."
I'm trying to build a form in which users can upload one or more photos automatically to a directory to then be displayed else where.
Whenever I use this form I created it functions properly on my website but unfortunately it keeps printing that error out and would like it to go away. Here is my code I'm working with:
<div>
<form action="upload.php" enctype="multipart/form-data" method="POST">
<input type="file" name="images[]" multiple="multiple"/>
<input type="submit" name="submit" value="upload images"/>
<form/>
<?php
// check if uploads directory exists
$dir = "images/";
if(!is_dir($dir))
{
echo "Directory not found, let's create the folder.";
mkdir($dir,"0777", true);
}
$countimg = 0;
$allimg = 0;
foreach($_FILES["images"]["name"] as $k=>$name)
{
$allimg++;
$imgname = $_FILES["images"]["name"][$k];
$sizeimg = $_FILES["images"]["size"][$k];
$tmpname = $_FILES["images"]["tmp_name"][$k];
//2.
$extension = strtolower(pathinfo($dir.$imgname, PATHINFO_EXTENSION));
if($extension=='png' || $extension=='jpg' ||$extension=='jpeg' ||$extension=='gif')
{
if($sizeimg < 2097152){
if(!file_exists($dir.$imgname)){
//1.
if(move_uploaded_file($tmpname,$dir.$imgname))
{
$countimg++;
}
}
}
}
}
echo "You are trying to upload $allimg images".'<br>';
echo "From $allimg image(s) - $countimg was/were uploaded with success".'<br>';
$z = $allimg - $countimg;
echo "$z image(s) were not uploaded: Not an image, over 2MB, or already uploaded.";
?>
</div>
Try
if (count($_FILES)) {
foreach($_FILES["images"]["name"] as $k=>$name) {
....
}
}
I tested your script, it works fine. The error message appears because you are not checking that a file got uploaded before starting the foreach. If I land on the page, the PHP code will still be triggered. To fix this, you may use the below:
<div>
<form action="upload.php" enctype="multipart/form-data" method="POST">
<input type="file" name="images[]" multiple="multiple"/>
<input type="submit" name="submit" value="upload images"/>
<form/>
<?php
if( $_POST['submit'] ) {
$dir = "images/";
if(!is_dir($dir))
{
echo "Directory not found, let's create the folder.";
mkdir($dir,"0777", true);
}
$countimg = 0;
$allimg = 0;
foreach($_FILES["images"]["name"] as $k=>$name)
{
$allimg++;
$imgname = $_FILES["images"]["name"][$k];
$sizeimg = $_FILES["images"]["size"][$k];
$tmpname = $_FILES["images"]["tmp_name"][$k];
//2.
$extension = strtolower(pathinfo($dir.$imgname, PATHINFO_EXTENSION));
if($extension=='png' || $extension=='jpg' ||$extension=='jpeg' ||$extension=='gif')
{
if($sizeimg < 2097152){
if(!file_exists($dir.$imgname)){
//1.
if(move_uploaded_file($tmpname,$dir.$imgname))
{
$countimg++;
}
}
}
}
}
echo "You are trying to upload $allimg images".'<br>';
echo "From $allimg image(s) - $countimg was/were uploaded with success".'<br>';
$z = $allimg - $countimg;
echo "$z image(s) were not uploaded: Not an image, over 2MB, or already uploaded.";
}
?>
</div>
if( $_POST['submit'] ) will ensure that the form is submitted prior to running the rest of the PHP code.
I want my users to be able to upload images to their account (my MySQL database). However, when I try to encode it and upload it, it appears that the file was never uploaded and is empty. I have checked the maximum upload size etc. in my PHP settings. Thanks in advance!!
$data = "";
if(isset($_FILES["up"])) {
$data = file_get_contents($_FILES['up']['tmp_name']);
$data = base64_encode($data);
$data = $connection->real_escape_string($data);
} else {
echo '<div style="position:absolute;height:100px;top:0px;left:0px;
border-top-right-radius:20px;border-top-left-radius:20px;
width:100%;background:white;z-index:100;"
>
<font style="color:#BB0000;font-size:2.2vw;">'.$_FILES['up']['error'].'</font>
</div>';
die('');
}
My HTML is: (And the form submits correctly)
<input type="file" accept=".jpg,.png,.jpeg" name="up" id="up"/>
Suggestion: store the images in a directory.
why not DB you ask?
read/write to a DB is always slower than a filesystem
your DB backups will become more time consuming
so, here is my solution.
STEP 1: create a directory userPhotos
STEP 2: create a form
<form action="upload.php" method="post" enctype="multipart/form-data">
Select your profile picture:
<input type="file" name="fileToUpload" id="fileToUpload">
<input type="Upload" value="Upload Image" name="submit">
</form>
STEP 3: create a file called upload.php which handles file uploads.
<?php
$target_dir = "userPhotos/";
$target_file = $target_dir . basename($_FILES["fileToUpload"]["name"]);
$uploadOk = 1;
$newfilename = ;//assign unique user ID
$imageFileType = pathinfo($target_file,PATHINFO_EXTENSION);
// Check if image file is a actual image or fake image
if(isset($_POST["submit"])) {
$check = getimagesize($_FILES["fileToUpload"]["tmp_name"]);
if($check !== false) {
echo "File is an image - " . $check["mime"] . ".";
if (move_uploaded_file($_FILES["fileToUpload"][$newfilename.$imageFileType], $target_file)) {
echo "The file ". basename( $_FILES["fileToUpload"]["name"]). " has been uploaded.";$uploadOk = 1;
}
} else {
echo "File is not an image.";
$uploadOk = 0;
}
}
if($uploadOK==1){
store the path of image in DB as "/userPhotos/".$newfilename
echo "uploaded photo : <img src='userphotos/".$newfilename."'">
}
//to display the image fetch the path using user ID as put it in src of img tag.
?>
Let me know if anyone has a better solution. thanks and Good luck.
PHP Code
$data = "";
if(isset($_FILES["up"])) {
$data = file_get_contents($_FILES['up']['tmp_name']);
$data = base64_encode($data);
$data = $connection->real_escape_string($data);
} else {
echo '<div style="position:absolute;height:100px;top:0px;left:0px;
border-top-right-radius:20px;border-top-left-radius:20px;
width:100%;background:white;z-index:100;"
>
<font style="color:#BB0000;font-size:2.2vw;">'.$_FILES['up']['error'].'</font>
</div>';
die('');
}
HTML Code
<form method="POST" enctype="multipart/form-data">
<input type="file" accept=".jpg,.png,.jpeg" name="up" id="up"/>
</form>
How can I save an image safely from a file input field using PHP & MySQL?
Here is the input file field.
<input type="file" name="pic" id="pic" size="25" />
This is a simple example, it should work.
Although you probably want to add checking for image types, file sizes, etc.
<?php
$image = $_POST['pic'];
//Stores the filename as it was on the client computer.
$imagename = $_FILES['pic']['name'];
//Stores the filetype e.g image/jpeg
$imagetype = $_FILES['pic']['type'];
//Stores any error codes from the upload.
$imageerror = $_FILES['pic']['error'];
//Stores the tempname as it is given by the host when uploaded.
$imagetemp = $_FILES['pic']['tmp_name'];
//The path you wish to upload the image to
$imagePath = "images/";
if(is_uploaded_file($imagetemp)) {
if(move_uploaded_file($imagetemp, $imagePath . $imagename)) {
echo "Sussecfully uploaded your image.";
}
else {
echo "Failed to move your image.";
}
}
else {
echo "Failed to upload your image.";
}
?>
http://php.net/file_upload covers just about everything you need to know.
<?php
if ($_SERVER['REQUEST_METHOD'] == 'POST') {
$tmpFile = $_FILES['pic']['tmp_name'];
$newFile = '/new_location/to/file/'.$_FILES['pic']['name'];
$result = move_uploaded_file($tmpFile, $newFile);
echo $_FILES['pic']['name'];
if ($result) {
echo ' was uploaded<br />';
} else {
echo ' failed to upload<br />';
}
}
?>
<form action="" enctype="multipart/form-data" method="POST>
<input type="file" name="pic" />
<input type="submit" value="Upload" />
</form>