hi im creating a login page where it would insert data into a php table but it does not seem to insert data into the table i have 2 tables in 1 database
hrms
<?php
$servername = "localhost";
$user = "root";
$dbpassword="";
$dbname = "hrms";
$username=$_POST['username'];
$passphrase=$_POST['passphrase'];
$conn = new mysqli($servername, $user, $dbpassword, $dbname);
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql = "SELECT * FROM user WHERE username='$username' AND passphrase='$passphrase'";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
$sql = "INSERT INTO access (user, status)
VALUES ('John', 'locked')";
header("location: main.php");
} else {
header("location: index.php");
}
$conn->close();
?>
You forgot to execute the query, do like below:
$sql = "INSERT INTO access (user, status) VALUES ('John', 'locked')";
$conn->query($sql);
Related
function inseartinto()
{
$DEL_LOG_REP = $connection->prepare("DELETE FROM test WHERE itemname='111'")$DEL_LOG_REP->execute()$DEL_LOG_REP->close()return $DEL_LOG_REP
}
This is short tutorails on connection in insert query into php...
<?php
$servername = "localhost";
$username = "username";
$password = "password";
$dbname = "myDB";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql = "INSERT INTO MyGuests (firstname, lastname, email)
VALUES ('John', 'Doe', 'john#example.com')";
if ($conn->query($sql) === TRUE) {
echo "New record created successfully";
} else {
echo "Error: " . $sql . "<br>" . $conn->error;
}
$conn->close();
?>
For more better understand..go to http://www.w3schools.com/php/default.asp
What code are you trying to writing man..
This is not a valid code for just not insert but also for connetion..
ya go onto W3School.com as mention by #Sasa.D... it provide you with knowledge from basic to expertise..
the data is not inserting. i think there is something wrong in
$sql = "INSERT INTO `users` (`Username`, `Password`, `FirstName`, `LastName`, `Email`, `ContactNumber`)
VALUES ('".$_POST["Username"]."','".$_POST["Password"]."','".$_POST["FirstName"]."','".$_POST["LastName"]."','".$_POST["Email"]."','".$_POST["ContactNumber"]."')";
When i try to change the statement in "else" with echo "successs"; its working.
please someone can tell me what is wrong.
<?php
error_reporting(E_ALL & ~E_NOTICE);
if(isset($_POST["Register"]))
{
$servername = "localhost";
$username = "root";
$password = "";
$dbname = "dbuseraccounts";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$user = $_POST['Username'];
$pass = $_POST['Password'];
$query = mysqli_query($conn, "SELECT * FROM users WHERE Username= '".$user."'");
if(mysqli_num_rows($query) > 0)
{
echo "email already exists";
}
else
{
$sql = "INSERT INTO users (Username, Password, FirstName, LastName, Email, ContactNumber)
VALUES ('".$_POST["Username"]."','".$_POST["Password"]."','".$_POST["FirstName"]."','".$_POST["LastName"]."','".$_POST["Email"]."','".$_POST["ContactNumber"]."')";
}
$conn->close();
}
?>
Your data is not inserting because you haven't even executed your query.
if (mysqli_num_rows($query) > 0) {
echo "Username already exists";
} else {
$sql = "INSERT INTO users (Username, Password, FirstName, LastName, Email, ContactNumber) VALUES ('".$_POST["Username"]."','".$_POST["Password"]."','".$_POST["FirstName"]."','".$_POST["LastName"]."','".$_POST["Email"]."','".$_POST["ContactNumber"]."')";
/* Run your query and check for errors */
$query = mysqli_query($conn, $sql) or die(mysqli_error($conn));
}
Please Execute query using
mysqli_query($conn, your query);
I'm quite new to this php/mysql deal and I'm having a hard time figuring out this situation particularily.
I have two tables, one of them is "dog" table and the other one is the "date" table. In order to insert a record in the "dog" table I MUST first insert a date in the "table" date and get the autoincrement id from that date.
Problem is that I've tried reading several posts on how to get the last insert id from a table you just inserted a record on and I can't seem to make it work.
$sql1="INSERT INTO FECHAS (fecha) VALUES (NOW())";
mysql_query($sql1);
echo $sql1;
$sql3="SELECT LAST_INSERT_ID()";
mysql_query($sql3);
echo $sql3;
$sql2="INSERT INTO PERRO (nombre_perro,FECHAS_id_fecha) VALUES ('$nombre_perro_var', '$last_id')";
echo $sql2;
if (!$mysqli->query($sql2)) {
echo 'Error: ', $mysqli->error;
}
$result2 = mysql_query($sql2);
Please forgive this code, I'm new and learning.
Thanks!
Use mysqli instead of mysql_
Connecting with mysqli:
$connection = mysqli_connect($hostname, $username, $password, $database_name);
Inserting into a table:
mysqli_query($connection, $sql);
Retrieving last inserted id:
$id = mysqli_insert_id($connection);
**Database**
CREATE TABLE MyGuests (
id INT(6) UNSIGNED AUTO_INCREMENT PRIMARY KEY,
firstname VARCHAR(30) NOT NULL,
lastname VARCHAR(30) NOT NULL,
email VARCHAR(50),
reg_date TIMESTAMP
)
**Example (MySQLi Object-oriented)**
<?php
$servername = "localhost";
$username = "username";
$password = "password";
$dbname = "myDB";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql = "INSERT INTO MyGuests (firstname, lastname, email)
VALUES ('John', 'Doe', 'john#example.com')";
if ($conn->query($sql) === TRUE) {
***$last_id = $conn->insert_id;***
echo "New record created successfully. Last inserted ID is: " . $last_id;
} else {
echo "Error: " . $sql . "<br>" . $conn->error;
}
$conn->close();
?>
**Example (MySQLi Procedural)**
<?php
$servername = "localhost";
$username = "username";
$password = "password";
$dbname = "myDB";
// Create connection
$conn = mysqli_connect($servername, $username, $password, $dbname);
// Check connection
if (!$conn) {
die("Connection failed: " . mysqli_connect_error());
}
$sql = "INSERT INTO MyGuests (firstname, lastname, email)
VALUES ('John', 'Doe', 'john#example.com')";
if (mysqli_query($conn, $sql)) {
***$last_id = mysqli_insert_id($conn);***
echo "New record created successfully. Last inserted ID is: " . $last_id;
} else {
echo "Error: " . $sql . "<br>" . mysqli_error($conn);
}
mysqli_close($conn);
?>
**Example (PDO)**
<?php
$servername = "localhost";
$username = "username";
$password = "password";
$dbname = "myDBPDO";
try {
$conn = new PDO("mysql:host=$servername;dbname=$dbname", $username, $password);
// set the PDO error mode to exception
$conn->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
$sql = "INSERT INTO MyGuests (firstname, lastname, email)
VALUES ('John', 'Doe', 'john#example.com')";
// use exec() because no results are returned
$conn->exec($sql);
***$last_id = $conn->lastInsertId();***
echo "New record created successfully. Last inserted ID is: " . $last_id;
}
catch(PDOException $e)
{
echo $sql . "<br>" . $e->getMessage();
}
$conn = null;
?>
A procedural solution (although it might be slightly wrong - I'm terrible at PHP)...
<?php
include('path/to/connection/stateme.nts');
$query = "
INSERT INTO fecha (fecha) VALUES (NOW());
";
mysqli_query($db,$query);
$query = "
INSERT INTO perro (nombre_perro,id_fecha) VALUES (?,?);
";
$nombre_perro = 'rover';
$id_fecha = mysqli_insert_id($db);
$stmt = mysqli_prepare($db,$query);
mysqli_stmt_bind_param($stmt, 'si', $nombre_perro,$id_fecha);
mysqli_stmt_execute($stmt);
?>
You might consider binding both queries into a transaction, so that in the event that the second query fails for some reason, then the first query fails too.
I am trying to do a simple SELECT to return rows of data from my database. I have a valid connection from my database so I know the issue is not there. I have ensured the names of each column are correct but it just returns 0 results.
My table inside the db is called 'user' and here is the members.php file:
<?php include 'header.php'; ?> <- this is where the db conect file is pulled in.
<?php
$sql = "SELECT id, username, email_address FROM user";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
// output data of each row
while($row = $result->fetch_assoc()) {
echo
$row["id"];
}
} else {
echo "0 Members";
}
$conn->close();
?>
Just for ref here is my DB connection (Not the most secure i am just testing):
<?php
$servername = "localhost";
$username = "***********";
$password = "**********";
// Create connection
$conn = new mysqli($servername, $username, $password);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
echo "Connected successfully<br><br>";
?>
you didnt select your database
$conn=new mysqli($servername, $username, $password);
this require another parameter which is your d.b name
$conn=new mysqli($servername, $username, $password,$db_name);
i do not know why the following code will not work for inserting data into mysql.
if (!$link = mysql_connect('server', 'user', 'password')) {
echo '700';
exit;
}
if (!mysql_select_db('vendors', $link)) {
echo '701';
exit;
}
$sql2 = "INSERT INTO transactions (TransID, payment_status, last_name, first_name, payer_email, address_name, address_state, address_zip, address_country, verify_sign, payment_gross, ipn_track_id, business, reciver_email) VALUES ('kris', 'kris', 'kris', 'kris', 'kris','kris', 'kris', 'kris', 'kris', 'kris', 'kris', 'kris', 'kris', 'kris')";
$result2 = mysql_query($sql2, $link);
What is wrong with the code?
php is giving no errors.
Please try not to use mysql_connect instead use mysqli_connect or PDO_MySQL read this
Also use die to find if there is any errors in your code
$link = mysql_connect('localhost', 'mysql_user', 'mysql_password');
if (!$link) {
die('Could not connect: ' . mysql_error());
}
Otherwise(recommended way)-
Procedural style
$servername = "localhost";
$username = "username";
$password = "password";
$dbname = "myDB";
// Create connection
$conn = mysqli_connect($servername, $username, $password, $dbname);
// Check connection
if (!$conn) {
die("Connection failed: " . mysqli_connect_error());
}
$sql = "INSERT INTO Persons (firstname, lastname, email)
VALUES ('Happy', 'John', 'john#example.com')";
if (mysqli_query($conn, $sql)) {
echo "New Person created successfully";
} else {
echo "Error: " . $sql . "<br>" . mysqli_error($conn);
}
mysqli_close($conn);
MySQLi Object-oriented style
$servername = "localhost";
$username = "username";
$password = "password";
$dbname = "myDB";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql = "INSERT INTO Persons (firstname, lastname, email)
VALUES ('Happy', 'John', 'john#example.com')";
if ($conn->query($sql) === TRUE) {
echo "New Person created successfully";
} else {
echo "Error: " . $sql . "<br>" . $conn->error;
}
$conn->close();
Try changing this
$result2 = mysql_query($sql2, $link);
Into this
$result2 = mysql_query($sql2, $link)or die(mysql_error());
You have to write the code like below to get the errors in your code
$result = mysql_query($sql2,$link) or die(mysql_error());
this or die(mysql_error()) will give you errors in query