I have some php code. I wish to unset topic and unlink $outputfile once I have finished printing it.
$file = "files/textfile.txt" ;
$processed = "processed.txt" ;
$outputfile = "files/outputfile.txt" ;
if(!empty($_POST)){
writetofile($file, $text, "w");
preproc($file);
execpython($processed);
$topic = getoutput($outputfile);
}
So, I am printing it somewhere at the bottom:
echo '<span style="color:red;">' . $topic . '</span>';
I am not sure how should I place unlink and unset because they seem to be deleting the outputfile in advance and I don't receive any output then. I need to delete it because it is being over-written and producing the same output sometimes.
You can delete the file after you read from it with getoutput(), and you can unset the variable after you're finished printing it.
$file = "files/textfile.txt" ;
$processed = "processed.txt" ;
$outputfile = "files/outputfile.txt" ;
if(!empty($_POST)){
writetofile($file, $text, "w");
preproc($file);
execpython($processed);
$topic = getoutput($outputfile);
unlink($outputfile);
}
echo '<span style="color:red;">' . $topic . '</span>';
unset($topic);
Related
I have got this code to open each file in a folder, decrease a value by 5 and then overwrite the existing content.
<?php
foreach (glob("users/*.php") as $filename) {
$array = file($filename);
$wallet = $array[0];
$time = $array[1];
$status = $array[2];
$steamid = $array[3];
$process = fopen($filename, "w") or die("Unable to open file!");
$time = $time - 5;
$newdata = $wallet . "\n" . $time . "\n" . $status . "\n" . $steamid;
fwrite($process, $newdata);
fclose($process);
}
?>
Before I execute the script, the files that are opened look like this:
680
310
0
74892748232
After the script was executed, the file looks like this:
680
305
0
74892748232
If the script is executed again, it adds more lines and just breaks the files even more.
The string for the file is created here:
$newdata = $wallet . "\n" . $time . "\n" . $status . "\n" . $steamid;
Why does it add an empty line after $wallet and $status, but not after $time? How can I avoid this and instead write down:
$wallet
$time
$status
$steamid
Thanks a lot in advance.:)
Try with this solution
You can also use file_put_contents():
file_put_contents($filename, implode("\n", $array) . "\n", FILE_APPEND);
from this SO question
https://stackoverflow.com/a/3066811/1301180
I am trying to configure the Eclipse PHP formatter to keep the opening and closing php tags on 1 line if there is only 1 line of code between them (while keeping the default new line formatting if there are more lines of code).
Example:
<td class="main"><?php
echo drm_draw_input_field('fax') . ' ' . (drm_not_null(ENTRY_FAX_NUMBER_TEXT) ? '<span class="inputRequirement">' . ENTRY_FAX_NUMBER_TEXT . '</span>' : '');
?></td>
Should be formatted to:
<td class="main"><?php echo drm_draw_input_field('fax') . ' ' . (drm_not_null(ENTRY_FAX_NUMBER_TEXT) ? '<span class="inputRequirement">' . ENTRY_FAX_NUMBER_TEXT . '</span>': ''); ?></td>
Is there any way to achieve this with Eclipse? Or another suggestion/formatter?
EDIT:
It seems Eclipse does not have such a formatting option, as explained in the comments below. Any existing alternatives that can do this?
As i already mentioned under question comment "As i know you can't do such thing in eclipse as eclipse has only options to format code part i mean the text part inside php tags <?php ...code text... ?>"
But you can achieve it with this php script
Very important before start: Backup your php project which you are going to mention in dirToArray() function
// Recursive function to read directory and sub directories
// it build based on php's scandir - http://php.net/manual/en/function.scandir.php
function dirToArray($dir) {
$result = array();
$cdir = scandir($dir);
foreach ($cdir as $key => $value){
if (!in_array($value,array(".",".."))){
if (is_dir($dir . DIRECTORY_SEPARATOR . $value)){
$result = array_merge(
$result,
dirToArray($dir . DIRECTORY_SEPARATOR . $value)
);
}else{
$result[] = $dir . DIRECTORY_SEPARATOR . $value;
}
}
}
return $result;
}
// Scanning project files
$files = dirToArray("/home/project"); // or C:/project... for windows
// Reading and converting to single line php blocks which contain 3 or less lines
foreach ($files as $file){
// Reading file content
$content = file_get_contents($file);
// RegExp will return 2 arrays
// first will contain all php code with php tags
// second one will contain only php code
// UPDATED based on Michael's provided regexp in this answer comments
preg_match_all( '/<\?php\s*\r?\n?(.*?)\r?\n?\s*\?>/i', $content, $blocks );
$codeWithTags = $blocks[0];
$code = $blocks[1];
// Loop over matches and formatting code
foreach ($codeWithTags as $k => $block){
$content = str_replace($block, '<?php '.trim($code[$k]).' ?>', $content );
}
// Overwriting file content with formatted one
file_put_contents($file, $content);
}
NOTE: This is just simple example and of course this script can be improved
// Result will be that this
text text text<?php
echo "11111";
?>
text text text<?php
echo "22222"; ?>
text text text<?php echo "33333";
?>
<?php
echo "44444";
echo "44444";
?>
// will be formated to this
text text text<?php echo "11111"; ?>
text text text<?php echo "22222"; ?>
text text text<?php echo "33333"; ?>
<?php
echo "44444";
echo "44444";
?>
In sublimetext, the manual command is ctrl + J.
Automagically, might i suggest you take a look at this:
https://github.com/heroheman/Singleline
I have a txt file with lines in this format
this is a name|this is a type|this is a description
this is a name|this is a type|this is a description
this is a name|this is a type|this is a description
I need to access those lines and echo them like this:
<li type="this is a type" description="this is a description">this is a name</li>
I have no idea how to approach this.
Thanks in advance
Normally I wouldn't write code for you without you having provided an example of what you've tried, but in this case it's pretty basic.
Use PHP's file function to read a file into an array (line by line), then use explode to break that line up:
<?php
$contents = file('yourfile.txt');
foreach($contents as $eachline) {
list($name, $type, $description) = explode("|", $eachline);
echo '<li type="' . $type . '" description="' . $description . '">' . $name . '</li>';
}
?>
PHP manual: http://us2.php.net/manual/en/function.file.php
The first step is to read every line of the file.
How to read a file line by line in php
After that explode the string by the pipe symbol $out = explode("|", $string);
after that you have an array and you can access the values with $out[0]; for example.
This is easypeasy:
$parts = explode("|", $line);
$out = "<li type='$parts[1]' description='$parts[2]'>$parts[0]</li>"
Ok sorry if its a stupid question im a begginer.
Im making a small shoutbox just for practise.
It inserts the shout infos in a txt file.
My problem is that, it lists the text from top to bottom, and i would like to do this reversed.
if(isset($_POST['submit'])) {
$text = $_POST['text'];
if(!empty($text)) {
$text = $_POST['text'];
$name = $_POST['name'];
$time = date("H:i");
$content =
"<div class='text'><em>" . $time . "</em>
<span class='c11'><b>" . "<a href='userinfo_php_willbe_here.php' target='_blank'>" . htmlspecialchars($name) . "</a>" . ":</span></b>
" . htmlspecialchars($text) . "
</div>\n";
file_put_contents($file, $content, FILE_APPEND | LOCK_EX);
}
}
here is my code.
i was googleing around with not much luck maybe i wasnt looking hard enough.
could please someone give me a hint?
thank you
No way to do so with one function call. You need to read the content from your target file, prepend the data in php and rewrite the whole file (see file_get_contents).
$fileContent = file_get_contents($file);
$fileContent = $content . $fileContent;
file_put_contents($file, $fileContent, LOCK_EX);
You can also use the array_reverse like so:
// Data in file separated by new-line
$data = explode("\n",file_get_contents("filename.txt"));
foreach(array_reverse($data) as $value) {
echo $value."\n";
}
You can only prepend to a file by means of reading it and writing afterwards.
file_put_contents($file, $content . file_get_contents($file), LOCK_EX);
I want to dump request variables to a file for debugging. How's this possible?
<?php
$req_dump = print_r($_REQUEST, TRUE);
$fp = fopen('request.log', 'a');
fwrite($fp, $req_dump);
fclose($fp);
Untested but should do the job, just change request.log to the file you want to write to.
I think nowadays this method is easier and faster:
$req_dump = print_r($_REQUEST, true);
$fp = file_put_contents('request.log', $req_dump, FILE_APPEND);
Use serialize() function for dumping. Dump $_SERVER, $_COOKIE, $_POST and $_GET separately (may go to the same file). If you're planning on debugging with the data it helps to know if the data was part of a POST request or a GET request.
Dumping everything is good for debugging in development, but not so in production. If your application does not have many users, it can work in production too. If you anticipate many users, consider dumping just the $_POST data, or limit server variables to those starting with HTTP_.
/* may be late but he can help others.
it's not my code, I get it from :
https://gist.github.com/magnetikonline/650e30e485c0f91f2f40
*/
class DumpHTTPRequestToFile {
public function execute($targetFile) {
$data = sprintf(
"%s %s %s\n\nHTTP headers:\n",
$_SERVER['REQUEST_METHOD'],
$_SERVER['REQUEST_URI'],
$_SERVER['SERVER_PROTOCOL']
);
foreach ($this->getHeaderList() as $name => $value) {
$data .= $name . ': ' . $value . "\n";
}
$data .= "\nRequest body:\n";
file_put_contents(
$targetFile,
$data . file_get_contents('php://input') . "\n"
);
echo("Done!\n\n");
}
private function getHeaderList() {
$headerList = [];
foreach ($_SERVER as $name => $value) {
if (preg_match('/^HTTP_/',$name)) {
// convert HTTP_HEADER_NAME to Header-Name
$name = strtr(substr($name,5),'_',' ');
$name = ucwords(strtolower($name));
$name = strtr($name,' ','-');
// add to list
$headerList[$name] = $value;
}
}
return $headerList;
}
}
(new DumpHTTPRequestToFile)->execute('./dumprequest.txt');
// add this line at the end to create a file for each request with timestamp
$date = new DateTime();
rename("dumprequest.txt", "dumprequest" . $date->format('Y-m-d H:i:sP') . ".txt");
<?php //log
$razdelitel = '--------------------------------------------'.PHP_EOL . date("Y-m-d H:i:s") .PHP_EOL.PHP_EOL;
$data_REQUEST = '$_REQUEST: ' . print_r($_REQUEST, true).PHP_EOL;
$data_POST = '$_POST: ' . print_r($_POST, true).PHP_EOL;
$data_GET = '$_GET: ' . print_r($_GET, true).PHP_EOL;
$data_all = $razdelitel . $data_REQUEST . $data_POST . $data_GET;
$name_txt = __DIR__ . '/log_' . date('m.Y') . '.txt'; //log_12.2021.txt
$chmod = '0244';
chmod($name_txt, $chmod);
file_put_contents($name_txt, $data_all, FILE_APPEND);
//var_dump($name_txt, $chmod); ?>