Make a json object properly by retrieving data by MYSQL - php

Question

I am making a php project and I am currently hosted it in my local xammp server.
I need to connect this to an android application using volley library.
So I need to make a json object.In orders I have stored picture of the product and orders.php page that I retrieve it via orderno.
In orders.php page I can see all my orders with images.
When trying to make the json object I need get this image url.I try to get it via order no but all the times i can't get the correct url.
Can anyone tell me how to solve this?
This is for making that json object.
This is the link to the image current json which I got
I want to make my image URL like below image:

Answer 1

There were multiple issues with your PHP code. However, I tried the resolve most of them. Still if you see any issues let me know, I will try to help you. I will highlight the changes I did to the code, for you to understand.
Here goes the PHP code to retrieve values:
<?php
// array for JSON response
$response = array();
include("config.php");
$con = mysqli_connect(DB_SERVER,DB_USER,DB_PASSWORD) or die(mysqli_error());
$db = mysqli_select_db($con,DB_DATABASE) or die(mysqli_error());
$result = mysqli_query($con,"SELECT * FROM ORDERS");
if (!empty($result)) {
// check for empty result
if (mysqli_num_rows($result) > 0) {
// user node
$response["orderdata"] = array();
while($row = mysqli_fetch_array($result))
{
$orderdata = array();
$i = $row["ITEM_ID"];
$url = "http://localhost/Online_shopping/admin/'$i'.jpg";
$orderdata["url"] = $url;
$orderdata["item_id"] = $row["ITEM_ID"];
$orderdata["price"] = $row["PRICE"];
$orderdata["size"] = $row["SIZE"];
array_push($response["orderdata"], $orderdata);
}
// success
$response["response_code"] = 200;
// echoing JSON response
echo json_encode($response);
} else {
// no product found
$response["response_code"] = 999;
// echo no users JSON
echo json_encode($response);
}
} else {
// no product found
$response["response_code"] = 999;
// echo no users JSON
echo json_encode($response);
}
?>
You need to first setup a connection with your database which is located in a particular server.
Using that connection, you need to query in your table to get the data.
mysql_query, mysql_fetch_array is deprecated. You have to use mysqli instead of mysql.
Lastly, you can go through this post to learn simple basic operations using PHP.