php mysqli SELECT doesnt return row [closed] - php

Question

Closed. This question needs debugging details. It is not currently accepting answers.
Edit the question to include desired behavior, a specific problem or error, and the shortest code necessary to reproduce the problem. This will help others answer the question.
Closed 7 years ago.
Improve this question
I have this code:
$check_user = "SELECT * FROM privateChats WHERE name = '$category'";
$result = mysqli_query($conn,$check_user);
$row = mysqli_fetch_assoc($result);
if($row["user1"] == $login_session or $row["user2"] == $login_session){
$sql = "SELECT * FROM privateChat WHERE name = '$category' ORDER BY position DESC";
}
// it goes on
It gets stuck at $result = mysqli_query($conn,$check_user); it doesn't give an error either.
There is a table called privateChats and there is a record in it.
My connection code:
$servername = "localhost";
$username = "thewhateverclub";
$password = "password";
$dbname = "my_thewhateverclub";
// Create connection
$conn = mysqli_connect($servername, $username, $password, $dbname);
// Check connection
if (mysqli_connect_error($conn)) {
die("Connection failed: " . mysqli_connect_error($conn));
}

Answer 1

Try this -
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql = "SELECT * FROM privateChats WHERE name = '$category'";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
// output data of each row
while($row = $result->fetch_assoc()) {
echo "Data1 " . $row["column1"]. " - Data2: " . $row["column2"]. "<br>";
}
} else {
echo "0 results";
}
$conn->close();
Also add this line at the start of your php script.
ini_set('display_errors', 1);
ini_set('display_startup_errors', 1);
error_reporting(E_ALL);
However, this doesn't make PHP to show parse errors - the only way to show those errors is to modify your php.ini with this line:
display_errors = on

Answer 2

You need to check mysqli Errors by below way:-
$conn = mysqli_connect("localhost", "my_user", "my_password", "my_db");
//check connection error
if (mysqli_connect_errno()) {
printf("Connect failed: %s\n", mysqli_connect_error());
exit();
}
// check variable is set or not
$category = isset($category) ? $category : 'notSet';
$check_user = "SELECT * FROM privateChats WHERE name = '$category'";
$result = mysqli_query($conn,$check_user);
// Check for query errors
if(!$result){
printf("Error: %s\n", mysqli_error($conn));
}
$row = mysqli_fetch_assoc($result);
Hope it will help you :)