I have 3 tables: orders, codes, events
I want to be able to pull all events that an order has, but there's an intermediary table that acts as a pivot table. I've been trying to use hasManyThrough and belongsToMany (along with withPivot) without any luck.
Examples:
public function events()
{
return $this->belongsToMany('events'); // tried this, fails
return $this->hasManyThrough('events', 'codes'); // tried this, fails
return $this->hasManyThrough('events', 'codes', 'event_id', 'id'); // tried this, fails
}
Any pointers would be great!
That's a belongsToMany setup. First, the first parameter is the name of the related class. Second, since your pivot table doesn't follow the Laravel naming conventions, you need to specify the name of the pivot table in your relationship definition:
public function events()
{
// first parameter is the name of the related class
// second parameter is pivot table name
return $this->belongsToMany(Event::class, 'codes');
}
With this setup, you can do:
// get an order
$order = Order::first();
// has all the events related to an order
$events = $order->events;
There are many ways to do this. I will show a one you can get it done.
In Order.php model
public function codes(){
return $this->has('App\Http\Code');
}
In Code.php model
public function orders(){
return $this->belongsTo('App\Http\Order');
}
public function events(){
return $this->hasMany('App\Http\Event');
}
In Event.php model
public function codes(){
return $this->belongsTo('App\Http\Code');
}
Then in you Controller, call them to get required data.
In your case you can do it like below:
$orders = Order::with(['codes' => function($q){
$q->with('events');
})->get();
May be you can get them with nested manner(not sure about this because i didn't tried before posting):
$orders = Order::with('codes.events')->get();
put return $orders; in your controller to see the query.
Enjoy!
Related
I'm new to laravel, and I've picked up the basic workflow of creating, updating and deleting database entries using migrations, models and controllers. But now I'm trying to do the same with a subscriptions table that has a subscriberId and a followeeId in it. Both of these fields reference different ids of the same table (users). This kind of task seem to require some finetuning. And I'm stuck.
Here's my code with some comments.
Subscriptions Table
Schema::create('subscriptions', function (Blueprint $table) {
$table->id();
$table->unsignedBigInteger('subscriberId');
$table->unsignedBigInteger('followeeId');
$table->foreign('subscriberId')->references('id')->on('users');
$table->foreign('followeeId')->references('id')->on('users');
});
Previously, I've used another approach to foreign ids, namely the one with the $table->foreignId('user_id')->constrained() pattern, but in this particular case I need to make sure that the two foreign ids reference different users, so I went for a more verbose option.
User Model
public function subscriptions()
{
return $this->hasMany(Subscription::class, 'subscriberId');
}
Here I've added the second parameter. This seems to work.
Subscription Model
class Subscription extends Model
{
use HasFactory;
protected $fillable = [
'subscriberId',
'followeeId'
];
public function subscriberId()
{
return $this->belongsTo(User::class, 'id', 'subscriberId');
}
public function followeeId()
{
return $this->belongsTo(User::class, 'id', 'followeeId');
}
}
Here I pass additional parameters, too, although in this case I'm not so sure if these are the correct ones. But this is my best guess. If I'm not mistaken, the second parameter of the belongsTo relation is inferred from the model that is being passed in, not the model of the parent class as is the case with the hasMany relation. So in this case that would be 'id' of the users table, which would be the default here anyway, but I need the third parameter, so I explicitly state the second parameter as well. Again, I'm not sure about this combination, but that's what I was able to make of the docs. I've also used other combinations of additional parameters, and even tried getting rid of these two public functions altogether, but that won't work either.
Now, here's the controller. If I do this:
$user->subscriptions()->get();
I do get the subscriptions I want. But if I do this instead:
$user->subscriptions()->create([
'subscriberId' => 1,
'followeeId' => 2
]);
I get the 500 error. I've also tried another approach:
$newSub = new Subscription;
$newSub->subscriberId = 1;
$newSub->followeeId = 2;
$newSub->save();
return $newSub;
But still no success. I still get the 500 error when I try to save()
Please help me out.
Solution
I should have used
public $timestamps = false
in the Subscription model, and I also misunderstood the docs. The correct combo is
User Model
public function subscriptions()
{
return $this->hasMany(Subscription::class, 'subscriberId');
}
and
Subscription Model
public function subscriberId()
{
return $this->belongsTo(User::class, 'subscriberId');
}
public function followeeId()
{
return $this->belongsTo(User::class, 'followeeId');
}
I am struggling with an eloquent request. Let me explain what I want to do:
I have two models: User and Item
One User can have many Item and one Item belongs to One user.
I wrote the two method for this relation in my models as followed:
class Item extends Model
{
public function user() {
return $this->belongsTo(User::class);
}
}
class User extends Model {
public function items() {
return $this->hasMany(Item::class, 'items', 'user_id', 'user_people_id');
}
}
I try to access to the items from my controller its user's relation with:
public function index()
{
$items = Item::with('user')->get();
dd($items);
FYI: I seeded my items table with 10 items and my user table with 4 users:
items table:
users table:
My problem is that in the when I check my query with dd() here is what I get: Only the 4 first items get the relation, the others 6 return a null value
Relation working:
Relation returning null:
Thank you for helping me!
According to Laravel doc, hasMany relationship parameters are the following:
return $this->hasMany(Myclass::class, 'foreign_key', 'local_key');
So try to change your relationship in your User class like that
// change this
return $this->hasMany(Item::class, 'items', 'user_id', 'user_people_id');
// to this
return $this->hasMany(Item::class, 'user_people_id', 'id');
The easiest solution would be to rename your foreign key to user_id. That is what Laravel expects, so you won't need to deal with extra arguments in your hasMany() functions.
If you can't do that I think this'll work: return $this->hasMany(Item::class, 'user_people_id');.
Please try to add all in your query to see if it will work:
Update
public function index()
{
$items = Item::all();
dd($items);
}
SQL scheme:
bulletins
id increment
deals
id increment
seller_id
buyer_id
deals_items - items = bulletins
id increment
title
desc
bulletin_id
deal_id
How can I get deal row by bulletin id? In raw SQL it looks like:
select `deals`.* from `deals` inner join `deals_items` on `deals_items`.`deal_id` = `deals`.`id` where `deals_items`.`bulletin_id` = 10572
I tried:
public function deals()
{
return $this->hasManyThrough(DealItem::class,Deal::class, 'bulletin_id','dealid','id');
}
But it seems a wrong way. Can't find right way in laravel doc about relation.
#HCK shows right way.
but when I doing $bulletin->deals() in blade template I got empty collection of deals.
When just $bulletin->deal - all is fine, we have collection of deals.
I using protected $with = ['deals'] in my bulletin model, but what is different call method or property? Why with method empty result?
#Amarnasan was close, but the order of the foreign keys was wrong. Try this:
Deal.php
public function bulletins()
{
return $this
->belongsToMany(Bulletin::class, 'deals_items', 'deal_id', 'bulletin_id')
->withPivot('title','desc');
}
Bulletin.php
public function deals()
{
return $this
->belongsToMany(Deal::class, 'deals_items', 'bulletin_id', 'deal_id')
->withPivot('title','desc');
}
From the docs:
As mentioned previously, to determine the table name of the
relationship's joining table, Eloquent will join the two related model
names in alphabetical order. However, you are free to override this
convention. You may do so by passing a second argument to the
belongsToMany method:
return $this->belongsToMany('App\Role', 'role_user');
In addition to customizing the name of the joining table, you may also
customize the column names of the keys on the table by passing
additional arguments to the belongsToMany method. The third argument
is the foreign key name of the model on which you are defining the
relationship, while the fourth argument is the foreign key name of the
model that you are joining to:
return $this->belongsToMany('App\Role', 'role_user', 'user_id', 'role_id');
Update
When you access the relationship as a method: $bulletin->deals() you are accessing the relationship itself. This will return an instance of \Illuminate\Database\Eloquent\Relations\BelongsToMany (in your case). Here the query is not executed yet, so you could keep adding constrains to your query, for example:
$bulletin
->deals()
->where('seller_id', 45) // <---
->skip(5) // <---
-> ... (And so on)
When you access it as a dynamic property, you are already executing the query, so this will return a Collection instance. Is the same as calling the relationship as a method and then attach the ->get() at the end, so this two are equivalent:
$bulletin->deals()->get()
// equals to:
$bulletin->deals
Check this other answer, it answers your question.
DealClass:
public function bulletins()
return $this->belongsToMany('App\Bulletin', 'deals_items ', 'bulletin_id', 'deal_id')->withPivot('title','desc');
}
BulletinClass:
public function deals()
return $this->belongsToMany('App\Deal', 'deals_items ', 'deal_id', 'bulletin_id')->withPivot('title','desc');
}
deals model -
public function bulletins()
return $this->belongsToMany(Bulletin::class, 'deals_items ', 'bulletin_id', 'deal_id');
}
bulletin model:-
public function deals()
{
return $this
->belongsToMany(Deal::class, 'deals_items', 'deal_id', 'bulletin_id',);
}
Database
I'm kind of new to databases and I made this small database, but I have problems fetching data from it.
Im trying to get all the racers from the logged in user, and it works properly, but if I enter $pigeons = $user->racer I only get back the racer table. I would like to know the attributes of the racers from the pigeons table aswell. I've made it work with query builder left joining the tables but I'm not sure why I set up this relationship if I can't use Laravel inner method.
In the User model I have these relationships:
public function pigeons(){
return $this->hasMany('App\Pigeon');
}
public function racers(){
return $this->hasManyThrough('App\Racer', 'App\Pigeon');
}
This is the Pigeon model:
public function user(){
return $this->belongsTo('App\User');
}
public function racer(){
return $this->hasMany('App\Racer');
}
}
And this is the Event model:
public function race(){
return $this->hasOne('App\Race');
}
public function racers(){
return $this->hasMany('App\Racer');
}
And this is what my EventsController looks like with the working alternative method and the commented not working.
public function upcoming(){
$id = auth()->user()->id;
$user = User::find($id);
$pigeons = DB::table('racers')->leftJoin('pigeons', 'racers.pigeon_id', '=', 'pigeons.id')->where('pigeons.user_id', '=', $id)->get();
//$pigeons = $user->racers;
return view('events.upcoming')->with('pigeons', $pigeons);
}
This is what I get with $user->racers or $user->racers()->get():
[{"id":1,"pigeon_id":14,"user_id":4,"event_id":1,"position":0,"created_at":null,"updated_at":null},{"id":2,"pigeon_id":15,"user_id":4,"event_id":1,"position":0,"created_at":null,"updated_at":null},{"id":3,"pigeon_id":16,"user_id":4,"event_id":1,"position":0,"created_at":null,"updated_at":null}]
And this is what I want to get, its not correct either since I should get id:1 but I want to pass to view these additional datas aswell like gender, color, ability (but they are in pigeons table not in racers).
[{"id":14,"pigeon_id":14,"user_id":4,"event_id":1,"position":0,"created_at":"2018-09-27 10:01:04","updated_at":"2018-09-27
10:01:04","gender":"hen","color":"blue","ability":38},{"id":15,"pigeon_id":15,"user_id":4,"event_id":1,"position":0,"created_at":"2018-09-27 10:01:04","updated_at":"2018-09-27
10:01:04","gender":"hen","color":"blue","ability":48},{"id":16,"pigeon_id":16,"user_id":4,"event_id":1,"position":0,"created_at":"2018-09-27 10:01:04","updated_at":"2018-09-27
10:01:04","gender":"cock","color":"blue","ability":11}]
To get the pigeons, what you would have to do is $pigeons = $user->racers()->get();. You can see an example of this in Laravel's official documentation https://laravel.com/docs/5.5/eloquent-relationships#introduction.
I need to get all appeals, that have appeal_stage.expiration_date less than NOW().
Now I have following solution:
public function scopeExpired($query) {
$query->join('appeal_stage', 'appeals.id', 'appeal_stage.appeal_id')
->where('appeal_stage.expiration_date', '<=', new Expression('NOW()'));
}
but resulted model dump shows that joined table is recognized as pivot table:
So, I want to ask - Is there some more convenient way to perform this request?
My suggestions is use Illuminate\Database\Eloquent\Relations\Pivot somehow, bu I do not quiet understand, how Pivot can be used here.
UPD 1
Models has next relations:
public function stages()
{
return $this->belongsToMany(Stage::class)->withPivot('prolongated_count', 'expiration_date')->withTimestamps();
}
public function appeals() {
return $this->belongsToMany(Appeal::class);
}
You should be able to do something like this:
$appeal->stages()->wherePivot('expiration_date', '<', $now)->get()
You should create relationship in appeal model
public function stages()
{
return $this->belongsToMany(Stage::class,'appeal_stage','appeal_id','stage_id')->wherePivot('expiration_date','<',Carbon::now())->withTimestamps();
}
In belongs To Many relationship second argument is your Pivot table name