PHP from JSON array [closed] - php

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I have this JSON:
{
"cache": true,
"data": [
{
"unique_id": "914239",
"description": "New Zealand 370/10 & 335/10 v Australia 70/1 & 505/10 *",
"title": "New Zealand 370/10 & 335/10 v Australia 70/1 & 505/10 *"
},
{
"unique_id": "973833",
"description": "Helmand Province Under-17s 135/10 * v Khost Province Under-17s 286/9 ",
"title": "Helmand Province Under-17s 135/10 * v Khost Province Under-17s 286/9 "
},
{
"unique_id": "935949",
"description": "Mid West Rhinos v Mashonaland Eagles 264/2 *",
"title": "Mid West Rhinos v Mashonaland Eagles 264/2 *"
},
{
"unique_id": "973379",
"description": "Mountaineers 136/10 v Matabeleland Tuskers 42 *",
"title": "Mountaineers 136/10 v Matabeleland Tuskers 42 *"
},
{
"unique_id": "959221",
"description": "Islamabad United v Quetta Gladiators",
"title": "Islamabad United v Quetta Gladiators"
}
],
"provider": {
"pubDate": "2016-02-23T14:01:01.467Z",
"source": "http://www.cricinfo.com/",
"url": "http://crm.wherrelz.com/"
}
}
and I need to display title and data in my PHP website.

Quite simple :
$raw_json = file_get_contents('data.json');
$array = json_decode($raw_json);
foreach ($array->data AS $data) {
echo $data->title;
echo '<br />';
echo $data->description;
echo '<br />';
}
Where of course the file data.json contains your json.

You can decode the data with json_decode you can find the full docs here: http://php.net/manual/en/function.json-decode.php
In terms of an example piece of code, you could do something like the following:
$decoded = json_decode($json);
if (json_last_error() !== JSON_ERROR_NONE) {
// Do something when you don't have valid json.
}
foreach ($decoded->data as $data) {
echo $data->unique_id;
echo $data->title;
}
json_last_error() will allow you to catch any invalid JSON or any other potential errors that json_decode() may come across, so I'd definitely reccomend using it and ensuring you have decoded valid json before doing anything with it.

Related

json - how to get data from json where user's input will come on %s [duplicate]

This question already has answers here:
PHP replace wildcards (%s, %d) in string with vars
(2 answers)
Closed 3 years ago.
I've got a JSON file which looks like this
{
"facebook": {
"icon": "fab fa-facebook",
"title": "Facebook",
"url": "https://facebook.com/%s"
},
"instagram": {
"icon": "fab fa-instagram",
"title": "Instagram",
"url": "https://instagram.com/%s"
}
}
So I'm getting users social links from a form, but only the user's ID of social link eg.https://facebook.com/ID. I'm storing the users ID in JSON file in database. I'm using PHP. How do I add the users ID in that '%s' and display the link.
To put together the information using the JSON data you have, you would use either sprintf() or printf() (the only difference being the printf() directly outputs the data sprintf() returns a string). The information on the manual pages shows how things like %s works.
So the code would look something like...
$id = 123;
$userName = "User name";
$json = '{
"facebook": {
"icon": "fab fa-facebook",
"title": "Facebook",
"url": "https://facebook.com/%s"
},
"instagram": {
"icon": "fab fa-instagram",
"title": "Instagram",
"url": "https://instagram.com/%s"
}
}';
$socialMedia = json_decode( $json, true );
echo echo '<a href="'.sprintf($socialMedia["facebook"]["url"], $id).'">'.
$userName.'</a>';
Which outputs...
User name

Iterating through this JSON string in PHP

This is my file, titled parks.JSON:
{
"state": [
{
"name": "Alabama",
"park1": "Bladon Springs State Park",
"park1Link": "http://www.stateparks.com/bladon_springs_state_park_in_alabama.html",
"park2": "Florala State Park",
"park2Link": "http://www.stateparks.com/florala_state_park_in_alabama.html"
},
{
"name": "Alaska",
"park1": "Chugach State Park",
"park1Link": "http://www.stateparks.com/chugach_state_park_in_alaska.html",
"park2": "Kachemak Bay State Park",
"park2Link": "http://www.stateparks.com/kachemak_bay_state_park_in_alaska.html"
}
]
}
And this is my php embedded in an html file to call it:
$json_url = "../data/parks.JSON";
$parksJSON = file_get_contents($json_url);
$parksData = json_decode($parksJSON, TRUE);
I am not sure how to go about iterating through my array. I, of course, will have all 50 states entered here in theory.
I have read other posts asking this and their methods don't work because my JSON format is always different from theirs it seems!
I would have thought a pretty simple loop would do it
foreach ($parksData["state"] as $state)
{
echo $state["name"];
}

PHP - What are these and how do I echo certain values? [duplicate]

This question already has an answer here:
How to extract and access data from JSON with PHP?
(1 answer)
Closed 6 years ago.
I'm looking to create a basic IP tracker, I'm trying to figure out how to echo certain aspects of this variable, cheers:
{"ip":"MY IP","country_code":"GB","country_name":"United Kingdom","region_code":"ENG","region_name":"England","city":"MY CITY","zip_code":"MY CODE","time_zone":"Europe/London","latitude":----,"longitude":-----,"metro_code":-}
This is the code which I was reading up on:
$location = file_get_contents('http://freegeoip.net/json/'.$_SERVER['REMOTE_ADDR']);
print_r($location);
{
"ip": "77.99.179.98",
"country_code": "GB",
"country_name": "United Kingdom",
"region_code": "H9",
"region_name": "London, City of",
"city": "London",
"zipcode": "",
"latitude": 51.5142,
"longitude": -0.0931,
"metro_code": "",
"areacode": ""
}
Cheers!
To echo something do
//Example
$locationObject = json_decode($location);
echo $locationObject->ip;
//Prints out: 77.99.179.98
More info
http://www.dyn-web.com/tutorials/php-js/json/decode.php

It is possible to set fields which i want to get in overpass api&

For example. I want to get coordinates of all node buildings in bbox.
PHP
$queryBuildings="[out:json];node['building']({$y1},{$x1},{$y2},{$x2});out;";
$data = file_get_contents("http://overpass-api.de/api/interpreter?data={$queryBuildings}")
One element from result:
{
"type": "node",
"id": 29537155,
"lat": 54.6744568,
"lon": -2.1421066,
"tags": {
"building": "house",
"description": "Abandoned (2007). Associate with lead mine workings above it?",
"name": "Flushiemere House"
}
}
I want to get only lon and lat fields it's possible?
You can use skeleton print mode (out skel) which omits all tags, thus being slightly shorter. So your request should become: [out:json];node['building']({$y1},{$x1},{$y2},{$x2});out skel;
Currently csv output mode ([out:csv]) is the only mode where you can select the fields to be shown.
<?php
$data = '{
"type": "node",
"id": 29537155,
"lat": 54.6744568,
"lon": -2.1421066,
"tags": {
"building": "house",
"description": "Abandoned (2007). Associate with lead mine workings above it?",
"name": "Flushiemere House"
}
}';
$test = json_decode($data);
var_dump($test->lon);
First use json_decode to parse the response body:
$parsed_data = json_decode($data);
Then you can access the various fields like so:
$lat = $parsed_data->lat;
$lon = $parsed_data->lon;

Finding a string inside another string [php] -- matching all for some reason?

I'm trying to match a form supplied UTC time and form supplied event name string with an array read in from a file. The problem is that it seems to always match even when it shouldn't. The format of the file will always be constant, so I know I'll be looking for a value within double quotes, so after failing to get results with strpos(), I tried preg_match...and now match everything. Code and example output follow ($utc and $event_name)are already set and correct when we get here):
$match1 = "/\"{$utc}\"/";
$match2 = "/\"{$event_name}\"/";
print "Match Values: $match1, $match2<p>";
foreach($line_array as $key => $value) {
print "Value = $value<p>";
if ((preg_match($match1,$value) == 1) and (preg_match($match2,$value) == 1))
{
print "Case 1 - False<p>";
} else {
print "Contains targets: $value<p>";
//code to act on hit will go here
}
}
And here's what comes back:
Match Values: /"1371033000000"/, /"Another test - MkII "/
Value = { "date": "1357999200000", "type": "meeting", "title": "Plant and Animal Genome Conference, San Diego, CA", "description": "NCGAS to present at Plant and Animal Genome Conference, San Diego, CA", "url": "http://www.event1.com/" }
Contains targets: { "date": "1357999200000", "type": "meeting", "title": "Plant and Animal Genome Conference, San Diego, CA", "description": "NCGAS to present at Plant and Animal Genome Conference, San Diego, CA", "url": "http://www.event1.com/" }
Value = { "date": "1357693200000", "type": "meeting", "title": "Testing Addition", "description": "This is a fake event.", "url": "http://pti.iu.edu" }
Contains targets: { "date": "1357693200000", "type": "meeting", "title": "Testing Addition", "description": "This is a fake event.", "url": "http://pti.iu.edu" }
Value = { "date": "1371033000000", "type": "meeting", "title": "Another test - MkII", "description": "This is a fake event.", "url": "http://pti.iu.edu" }
Contains targets: { "date": "1371033000000", "type": "meeting", "title": "Another test - MkII", "description": "This is a fake event.", "url": "http://pti.iu.edu" }
I should only be matching the last one, but they all match. I've been playing with the regex and can't seem to find the right magic.
Simplified it and got what I was after:
foreach($line_array as $key => $value) {
print "Value = $value<p>";
if (preg_match("/$utc/",$value) and preg_match("/$event_time/",$value))
{
print "Contains targets: $value<p>";
} else {
print "Case 1 - False<p>";
//code to act on hit will go here
}
}
But answer 2 got me in the right direction. Thanks, Ian!
You don't need to do anything weird inside a double-quoted string, just drop your variable in as is...
$match1 = "/$utc/";
$match2 = "/$event_name/";
I suspect your regexes are looking for zero-length strings.
Also, this line doesn't need so many parentheses...
if (preg_match($match1,$value) == 1 and preg_match($match2,$value) == 1) {
[...]
}

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