ForEach loop data insert into two database table - php

Question

$imagesarray[]=explode('&',$data[5]);
$imag_temp = 0;
foreach($imagesarray as $image){
if($imag_temp == 0 )
{
$this->db->query("UPDATE " . DB_PREFIX . "product SET image = 'media/" . $image[0] . "' WHERE product_id = '" . (int)$product_id . "'");
}else{
foreach($image as $img){
$this->db->query("INSERT INTO " . DB_PREFIX . "product_image SET image = 'media/" . $img . "' , product_id = '" . (int)$product_id . "'");
}
}
$imag_temp++;
}
This is my $data[5]=Arizona Diamondbacks.png&arizona-cardinals.png&Atlanta Braves.jpg&...&...&...n number can have..
I have writend query for each for where..in that every first image should insert to one table and remaining all other images should insert to another table..now for every loop first image conidering as first /.

Answer 1

You don't need $imagesarray[] if this is for a single product.
Say
$data[5] = "Arizona Diamondbacks.png&arizona-cardinals.png&Atlanta Braves.jpg";
$imagesarray = explode('&',$data[5]);
Will create an array like
Array
(
[0] => Arizona Diamondbacks.png
[1] => arizona-cardinals.png
[2] => Atlanta Braves.jpg
)
Then using single variable assign the query to perform
foreach($imagesarray as $key => $image){
if($key == 0 )
{
$query = "UPDATE " . DB_PREFIX . "product SET image = 'media/" . $image . "' WHERE product_id = '" . (int)$product_id . "'";
} else {
$query = "INSERT INTO " . DB_PREFIX . "product_image SET image = 'media/" . $image . "' , product_id = '" . (int)$product_id . "'";
}
$this->db->query($query);
}

Answer 2

what is the error you are getting.. your insert query is not correct.
and other thing you have to notice is what type of array you are getting ...
You can edit this as required
this code is working you can modify with your insert and update query..
<?php
$data[5]='Arizona Diamondbacks.png&arizona-cardinals.png&Atlanta Braves.jpg';
$imagesarray[]=explode('&',$data[5]);
foreach ($imagesarray[0] as $key => $value) {
if($key==0){
echo "hello"; // here is your update query
}
else{
echo "sorry"; // here is your insert query
}
}

Answer 3

I don't know what you want, but you have some basic errors. You should learn more about php and sql before try to code something.
You don't need to add [] to the $imagesarray when explode the $data[5]
In the foreach loop the $image variable is a string, not an array
your INSERT query is incorrect, you should take a look to the documentation http://dev.mysql.com/doc/refman/5.7/en/insert.html
Your code should be something like this
$imagesarray = explode('&',$data[5]);
$imag_temp = 0;
foreach($imagesarray as $image){
if($imag_temp == 0 )
{
$this->db->query("UPDATE " . DB_PREFIX . "product SET image = 'media/$image' WHERE product_id = '$product_id'");
}else{
foreach($image as $img){
$this->db->query("INSERT INTO " . DB_PREFIX . "product_image (image, product_id) VALUES ('media/$image', '$product_id')");
}
}
$imag_temp++;
}
Make some research to learn how sql and php work, and make some debug because your code can have more bugs