I'm trying to fetch events from database to calendar but at this stage it just outputs the first event it gets from the database and the json when i echo it it returns just the first event
<?php
include("dbcon.php");
$events1 = array();
$sql345="select * from takimet";
$result = mysql_query($sql345)or die(mysql_error());
while ($row=mysql_fetch_array($result)){
$id = $row['agent_id'];
$title = $row['ezitimi'];
$start = $row['datestamp'];
$events1 = array(
'id' => "$id",
'title' => "$title",
'start' => "$start"
);
}
echo json_encode($events1);
?>
You are over writing the same array occurance each time round you loop.
Instead
$events1 = array();
while ($row=mysql_fetch_array($result)){
$events1[] = array( //<--- changed
'id' => $row['agent_id'],
'title' => $row['ezitimi'],
'start' => $row['datestamp']
);
}
Related
I making a script to monitorize data from some VPSs, which is being stored in a MySQL database.
$result = mysql_query("SELECT * FROM data");
$data = array();
while ($row = mysql_fetch_array($result)) {
$data[] = array(
'id' => $row['id'],
'hostname' => $row['hostname'],
'loadavrg' => $row['load average']
);
}
I would like to separase data by hostnames so I can read it like the following example:
foreach($data['sitename.com'] as $d)
echo $d['loadavrg'];
I already tried with the following code (just for testing), but didn't work:
$result = mysql_query("SELECT * FROM data WHERE hostname='sitename.com'");
$data = array();
while ($row = mysql_fetch_array($result)) {
$data[] = array(
'sitename.com' => array(
'id' => $row['id'],
'loadavrg' => $row['load average']
)
);
}
I'm just missing the right way and syntax to achieve it :X
Every element should be added as subarray of 'sitename.com':
while ($row = mysql_fetch_array($result)) {
$data['sitename.com'][] = array(
'id' => $row['id'],
'loadavrg' => $row['load average']
);
}
Try this,
while ($row = mysql_fetch_array($result)) {
$hostname = $row['hostname'];
$data[$hostname][] = array(
'id' => $row['id'],
'loadavrg' => $row['load average']
);
}
I am trying to extract data from mysql database into a datatable using ajax, and php.
The code for my response.php file is below:
<?php
$result = mysql_query("select * from orders");
while ($row = mysql_fetch_array($result)) {
$data = array(
array(
'Name' => $row['jobnumber'],
'Empid' => $row['ID'],
'Salary' => $row['product']
)
);
}
$results = array(
"sEcho" => 1,
"iTotalRecords" => count($data),
"iTotalDisplayRecords" => count($data),
"aaData" => $data
);
/*while($row = $result->fetch_array(MYSQLI_ASSOC)){
$results["data"][] = $row ;
}*/
echo json_encode($results);
?>
Why is this only returning one result in my front end table?
http://orca.awaluminium.com/test.php
link above shows table.
You're replacing value of $data instead of pushing new rows in an array.
Change the following line.
$data = array(
array(
'Name'=>$row['jobnumber'],
'Empid'=>$row['ID'], 'Salary'=>$row['product']
)
);
To
$data[] = array(
'Name'=>$row['jobnumber'],
'Empid'=>$row['ID'], 'Salary'=>$row['product']
);
Also put $data=array(); before string while() looop.
You have to do foreach
while ($row = mysql_fetch_array($result)){
foreach($row as $a)
{$data[] = array(
array('Name'=>$a['jobnumber'], 'Empid'=>$a['ID'], 'Salary'=>$a['product']),
);
}
}
I have used the PHP Gantt Class from Github here:
https://github.com/bastianallgeier/gantti
I have a php script which generates a gantt chant from data in a php array:
$data = array();
$data[] = array(
'label' => 'Project 1',
'start' => '2012-04-20',
'end' => '2012-05-12'
);
$data[] = array(
'label' => 'Project 2',
'start' => '2012-04-22',
'end' => '2012-05-22'
);
Instead of this I would like to use a mysql database to print out results as arrays with a layout that matches the previous way of loading data:
$query=mysql_query("select main_task AS 'label', start, end from tasks") or
die(mysql_error());
// Collect the results
while($obj = mysql_fetch_object($query)) {
$arr[] = $obj;
}
// JSON-encode the response
$json_response = json_encode($arr);
// Return the response
echo $json_response;
This is the error response I get:
[{"label":"aris","start":"2012-05-15","end":"2012-07-03"},{"label":"test","start":"2012-06-01","end":"2012-07-03"},{"label":"test1","start":"2012-06-01","end":"2012-08-05"},{"label":"Adams","start":"2012-05-06","end":"2012-06-17"},{"label":"hellooo","start":"2012-07-22","end":"2012-09-05"},{"label":"hello 2","start":"2012-05-11","end":"2012-06-03"}]
Fatal error: Cannot use object of type stdClass as array in /home/inse1d/public_html/gantti-master/lib/gantti.php on line 44
You have to do as
while($obj = mysql_fetch_object($query)) {
$arr[] = array('label'=>$obj->label,'start'=>$obj->start,'end'=>$obj->end);
}
And then
$json_response = json_encode($arr);
I have an php array with presentation as follow:-
<?php
$ads = array();
$ads [] = array(
'name' => 'Apple',
'duration' => '3',
'price' => "$5"
);
$ads [] = array(
'name' => 'Orange',
'duration' => '2',
'price' => "$10"
);
$ads [] = array(
'name' => 'Banana',
'duration' => '5',
'price' => "$6"
);
and then, I would like to replace the static data with dynamic data from database:-
$sql = "SELECT * from tb_fruit order by fruit_id ASC";
$result = mysql_query($sql_approve, $conn_fruit);
while($record = mysql_fetch_array($result))
{
$fruit_id = $record['fruit_id'];
$fruit_name = $record['fruit_name '];
$fruit_price= $record['fruit_price'];
$fruit_duration= $record_approve['fruit_duration'];
}
Actually, how shall I combine the 2 presentations together? Thanks!
If you want to get a similar structure as the one that you have in the first example, you can modify your second to create a new array and append it to an existing $ads array.
$sql = "SELECT * from tb_fruit order by fruit_id ASC";
$result = mysql_query($sql_approve, $conn_fruit);
$ads = array();
while($record = mysql_fetch_array($result))
{
$ads[] = array(
'name' => $record['fruit_name'],
'price' => $record['fruit_price'],
'duration' => $record['fruit_duration']);
}
iteration over result can be modified (provided only the required attributes are fetched in the query)
$fruit = array();
while($record = mysql_fetch_array($result))
{
$fruit[] = $record;
}
may be you could use array_merge
$result = array();
$result = array_merge($ads,$fruit);
So, you want to populate your "ads" array with information from the database? It seems fairly counterintuitive seeing as mysql_fetch_array already returns a perfectly adequate associative array, but here you go:
$sql = "SELECT * from tb_fruit order by fruit_id ASC";
$result = mysql_query($sql_approve, $conn_fruit);
$ads = array();
while($record = mysql_fetch_array($result))
{
$ads[] = array (
'name' => $record['fruit_name'],
'price' => $record['fruit_price'],
'duration' => $record['fruit_duration']
);
}
If
the initial array is not just an example, but default data that you might overwrite with the db data, and
the fruit name is unique (a primary key of sorts)
then you should set the array key of the main array to that of the fruit name, so that if the db has a different value, it will automatically get overwritten but otherwise left alone. Like so:
$ads ['Apple'] = array(
'duration' => '3',
'price' => "$5"
);
$ads ['Orange'] = array(
'duration' => '2',
'price' => "$10"
);
$ads ['Banana'] = array(
'duration' => '5',
'price' => "$6"
);
$sql = "SELECT * from tb_fruit order by fruit_id ASC";
$result = mysql_query($sql_approve, $conn_fruit);
$ads = array();
while($record = mysql_fetch_array($result))
{
$ads[$record['fruit_name']]['price'] = $record['fruit_price'];
$ads[$record['fruit_name']]['duration'] = $record['fruit_duration'];
}
Now, if 'Apple' is in the db, the price and duration get overwritten, but otherwise, it stays where you set it before the query.
You could go a step further and have both the price and duration returned by the query checked for an empty value (Null, "", 0), and only set the value if it is not empty, etc. But that is more a of business logic decision.
This seems like a simple challenge, but I'm struggling.
I want to retrieve records using a join query on two database tables and represent them as an array of arrays, whereby each of the elements in the root array is a parent record and each nested element represents a child record.
The SQL query is working fine, and it returns a set of rows in which the channel_key column is a grouping column.
Here's my attempt at populating the array structure from the rows:
$rows = $db->get_results($query);
$key = '';
$programmes = array();
foreach ($rows as $row) {
$programme = array(
'title' => $row->title,
'start' => $row->start,
'duration' => $row->duration
);
$programmes[] = $programme;
if ($key != $row->channel_key) {
$channels[] = array(
'key' => $row->channel_key,
'programme' => $programmes
);
$key = $row->channel_key;
$programmes = array();
}
}
Unfortunately this only populates the root level arrays (the ones that correspond to the parent records).
Any suggestions please?
Thanks,
Tim
You only have one programme in the $programmes array when you assign it to the channel.
An alternative would be to build the channel array with the channel_key.
e.g.
<?php
$channels = array();
foreach($rows as $row) {
// Create the channel node if it doesn't exist
if (!isset($channels[$row->channel_key])) {
$channels[$row->channel_key] = array(
'key' => $row->channel_key,
'programme' => array()
);
}
$programme = array(
'title' => $row->title,
'start' => $row->start,
'duration' => $row->duration
);
// Add to the existing channel node.
$channels[$row->channel_key]['programme'][] = $programme;
}
Simple solution can be.
$rows = $db->get_results($query);
$key = '';
$programmes = array();
foreach ($rows as $row) {
$programme = array(
'title' => $row->title,
'start' => $row->start,
'duration' => $row->duration
);
$programmes[$row->channel_key][] = $programme;
}