Display different content depending on Referrer - php

Question

Hey I am trying to display a different phone number for visitors my website from my Google adwords campaign.
The code below works without the else statement (so if I click through to the page from Google it will display a message, and if I visit the site regularly it does not). When I added the else statement it outputs both numbers. Thank you
<?php
// The domain list.
$domains = Array('googleadservices.com', 'google.com');
$url_info = parse_url($_SERVER['HTTP_REFERER']);
if (isset($url_info['host'])) {
foreach($domains as $domain) {
if (substr($url_info['host'], -strlen($domain)) == $domain) {
// GOOGLE NUMBER HERE
echo ('1234');
}
// REGULAR NUMBER HERE
else {
echo ('12345');
}
}
}
?>

Answer 1

Your logic is slightly skewed; you're checking to see if the URL from parse_url matches the domains in your array; but you're running through the whole array each time. So you get both a match and a non-match, because google.com matches one entry but not the other.
I'd suggest making your domains array into an associative array:
$domains = Array('googleadservices.com' => '1234',
'google.com' => '12345' );
Then you just need to check once:
if (isset($url_info['host'])) {
if (isset($domains[$url_info['host']])) {
echo $domains[$url_info['host']];
}
}
I've not tested this, but it should be enough for you to see the logic.
(I've also removed the substr check - you may need to put that back in, to ensure that you're getting the exact string that you need to look for)