How to write this query in laravel 5.1
SELECT
(SELECT firstname FROM registration_details a INNER JOIN users b
ON a.id = b.registerid
WHERE c.patientid = b.id ) AS patient,
(SELECT firstname FROM registration_details a INNER JOIN users b
ON a.id = b.registerid
WHERE c.doctorid = b.id ) AS doctor,
c.`appoinmentdate`
FROM `appoinments` c
I tried like this But i get Undefined property: stdClass::$id error
DB::table('appoinments')
->select(DB::raw(
"(SELECT firstname FROM registration_details INNER JOIN users ON registration_details.id = users.registerid WHERE appoinments.patientid = users.id) AS patient",
"(SELECT firstname FROM registration_details INNER JOIN users ON registration_details.id = users.registerid WHERE appoinments.doctorid = users.id) As doctor",
"appoinments.appoinmentdate",
"appoinments.id",
"(SELECT timings FROM appoinment_time WHERE appoinment_time.id = appoinments.appoinment_time) AS apptime ",
"(SELECT branchname FROM branches WHERE branches.id = appoinments.branchcode) AS branch"))
->get();
Finally got the answer. Thanks to all who try for me.
$appoinment = DB::table('appoinments')->select(DB::raw("(SELECT firstname FROM registration_details INNER JOIN users ON registration_details.id = users.registerid WHERE appoinments.patientid = users.id) AS patientid"));
$appoinment = $appoinment->addSelect(DB::raw("(SELECT firstname FROM registration_details INNER JOIN users ON registration_details.id = users.registerid WHERE appoinments.doctorid = users.id) As doctorid"));
$appoinment = $appoinment->addSelect(DB::raw("appoinments.appoinmentdate"));
$appoinmentlist = $appoinment3->addSelect(DB::raw("appoinments.id"))->get();
Related
I want to write this code in one query with left join statement. Currently I use php for loop this query but its not good and is too slow
It's app that have like and dislike option. I want number of every user's like
public function getUserLikedCount($id) {
$query = $this->db->query(
"SELECT * FROM `users`, post, `like`
WHERE users.id = post.post_user_id
AND like.like_post_id = post.post_id
AND users.id = ?
AND post.post_is_active = 1", array($id)
);
return $query->num_rows();
}
thanks
Try like it ( I don't know your table like structure):
$sql = 'SELECT u.id AS `user_id`
COUNT(p.post_id) AS `liked_cnt` <-- or like.id ( if this field exists)
FROM `post` AS p
LEFT JOIN `users` AS u
ON ( u.id = p.post_user_id )
LEFT JOIN `like` AS l
ON ( l.like_post_id = p.post_id )
WHERE p.post_is_active = 1
AND l.status = 1 <-- "liked"
GROUP BY u.id ';
Try this :
$query = $this->db->query(
"SELECT * FROM `users` u
LEFT JOIN post p ON u.id = p.post_user_id AND u.id =?
LEFT JOIN like l ON l.like_post_id = p.post_id AND p.post_is_active = 1
", array($id)
For some reason the member id field(auto inc.) in my huge query is returning null.I've tried every which way of selecting it... m.member_id AS member_id, etc.I cannot figure out why it is returning null when there is a value for that field in the table.
<?php
public function get_info($criteria = 0){
if(is_numeric($criteria)){
$where = "WHERE m.member_id = ".$criteria;
} else {
$where = "WHERE email_address = '".$criteria."'";
}
$query_member = "
SELECT
m.member_id AS member_id, m.display_name, m.email_address, m.group_id, m.status, m.activation_code, UNIX_TIMESTAMP(m.date_joined) AS date_joined,
m.gender, m.location, m.biography, m.mantra, m.birth_date, m.results_per_page, m.admin_emails, m.member_emails, m.last_active, m.avatar_id,
m.banner_id, m.signature, m.newsletter_subscription, m.recruiting_status, m.facebook_username, m.website, m.steam_username, m.xboxlive_gamertag, m.psn_id,
g.group_id, g.title, g.description,
a.attachment_id, a.file_name,
f.message_id, f.author_id, COUNT(f.message_id) AS forum_count,
b.attachment_id AS banner_id, b.file_name AS banner_file,
mr.request_id, mr.author_id, mr.recipient_id, mr.status, COUNT(mr.request_id) AS total_friends,
tm.team_member_id, tm.member_id, tm.team_id
FROM members AS m
LEFT JOIN member_groups AS g ON (m.group_id = g.group_id)
LEFT JOIN attachments AS a ON (m.avatar_id = a.attachment_id)
LEFT JOIN forum_messages AS f ON (m.member_id = f.author_id)
LEFT JOIN attachments AS b ON (m.banner_id = b.attachment_id)
LEFT JOIN member_requests AS mr ON (m.member_id = mr.author_id OR m.member_id = mr.recipient_id) AND mr.status = 1
LEFT JOIN team_members AS tm ON (m.member_id = tm.member_id) AND date_left = ''
".$where."
GROUP BY m.member_id
LIMIT 1";
//show_error($query_member);
if($query_member = $this->db->query($query_member)){
if($query_member->num_rows() > 0){
var_dump($query_member->row_array());
Because you select two fields with the same name. So MySQL will return result of last one. Add aliases:
SELECT m.member_id AS member_id_1, tm.member_id AS member_id_2 ...
i want to retrieve Data form 3 specifies Tables namely
UserDetail(Fname,Lname,User_id),
Movies(Movie_id,MovieName)
UserLikedMovies(User_id,Movie_id)
such that when a user enter a specific Movie_id then Userid Fname Lname form User detail MovieName from Movies,,
Here is what i tried
SELECT UserDetail.FName
FROM
UserDetail UserDetail
INNER JOIN
UserLikedMovies UserLikedMovies
ON
UserDetail.User_id = UserLikedMovies.User_id
INNER JOIN
(
SELECT
Movies.MovieName,
Movies.Movie_id
FROM
Movies Movies
INNER JOIN
UserLikedMovies UserLikedMovies
ON
Movies.Movie_id = UserLikedMovies.Movie_id
INNER JOIN
UserDetail UserDetail
ON
UserLikedMovies.User_id = UserDetail.User_id
WHERE
Movies.Movie_id IN ( Select UserLikedMovies.Movie_id from UserLikedMovies where UserLikedMovies.Movie_id = 4)
) as ABC
ON UserLikedMovies.Movie_id = ABC.Movie_id
AND Movies.Movie_id = ABC.Movie_id
Suppose movie_id is 9, then query is below.
SELECT User.Fname, User.Lname, (SELECT MovieName FROM Movies WHERE Movie_id = 9) AS MovieName
FROM UserDetail User
INNER JOIN UserLikedMovies Like
ON User.User_id = Like.User_id
WHERE Like.Movie_id = 9;
It is pretty simple query:
SELECT ud.`User_id`, ud.`Fname`, ud.`Lname`, m.`MovieName`
FROM `Movies` m
RIGHT JOIN `UserLikedMovies` ulm ON ulm.`Movie_id` = m.`Movie_id`
LEFT JOIN `UserDetail` ud ON ud.`User_id` = ulm.`User_id`
WHERE m.`Movie_id` = 4
I do not know why you are using fearful sub-queries for this simple task.
function search_num_rows($param){
$company_name=$param['company_name'];
$loan_no=$param['loan_no'];
$q = $this->db->query("select Count(0) as num_rows
from contact_new
inner join companies c on contact_new.company_id = c.id
inner join history on contact_new.id = history.receiver_email
inner join escalation_level on contact_new.escalation_level_id = escalation_level.id
inner join departments on contact_new.departmend_id = departments.id
WHERE loan_no= '$loan_no' if($company_name){ AND company_name= '$company_name'} ")->result();
return $q[0]->num_rows;
}
can i insert the php code as i done in where clause.Is there any other way to do this without using active records.
It's actually very easy:
function search_num_rows($param){
$company_name = (isset($param['company_name']) && !empty($param['company_name']) ? " AND company_name = '$param[company_name]'" : '');
$loan_no=$param['loan_no'];
$q = $this->db->query("select Count(0) as num_rows
from contact_new
inner join companies c on contact_new.company_id = c.id
inner join history on contact_new.id = history.receiver_email
inner join escalation_level on contact_new.escalation_level_id = escalation_level.id
inner join departments on contact_new.departmend_id = departments.id
WHERE loan_no= '$loan_no' $company_name")->result();
return $q[0]->num_rows;
}
I have the following SQL:
SELECT (
(SELECT SUM(vote_score)
FROM question_votes
JOIN questions
ON vote_question = q_id
JOIN users
ON q_author = users.id
WHERE q_author` = users.id)
+
(SELECT SUM(vote_score)
FROM answer_votes
JOIN answers
ON vote_answer = a_id
JOIN users
ON a_author = users.id
WHERE a_author = users.id)) AS rep
and I want it to be added here (Ion Auth's method):
$this->db->select(
array(
$this->tables['users'].'.*',
$this->tables['groups'].'.name AS '. $this->db->protect_identifiers('group'),
$this->tables['groups'].'.description AS '. $this->db->protect_identifiers('group_description'),
"(SELECT COUNT(`a_author`) FROM `answers` WHERE a_author = users.id) + (SELECT COUNT(`q_author`) FROM `questions` WHERE q_author = users.id ) AS total_posts",
"SELECT
((SELECT SUM(vote_score)
FROM question_votes
JOIN questions
ON vote_question = q_id
JOIN users
ON q_author = users.id
WHERE q_author` = users.id)
+
(SELECT SUM(vote_score)
FROM answer_votes
JOIN answers
ON vote_answer = a_id
JOIN users
ON a_author = users.id
WHERE a_author = users.id)) AS rep"
)
);
but I get the followin error:
Did you read the error message?
You have a (`) where shouldn't be any.
Change this: WHERE q_author' = users.id for this: WHERE q_author = users.id