How I can execute the second query in php [duplicate] - php

Question

This question already has answers here:
How I can execute many queries in one page?
(2 answers)
Closed 6 years ago.
I use this code it run very good but the problem how I can execute the second query:
$query .= "SELECT * FROM `course` where id = 201102887;";
which is from another table.The first query work fine . Can you help me or advise me to another way to run many query .
<?php
$link = mysqli_connect("localhost", "root", "", "uoh");
/* check connection */
if (mysqli_connect_errno()) {
printf("Connect failed: %s\n", mysqli_connect_error());
exit();
}
$query = "SELECT * FROM `student_record` where id = 201102887;";
$query .= "SELECT * FROM `course` where id = 201102887;";
/* execute multi query */
if (mysqli_multi_query($link, $query)) {
do {
/* store first result set */
if ($result = mysqli_store_result($link)) {
while ($row = mysqli_fetch_row($result)) {
printf("%s\n", $row[0]);
printf("%s\n", $row[1]);
}
mysqli_free_result($result);
}
/* print divider */
if (mysqli_more_results($link)) {
printf("-----------------\n");
}
} while (mysqli_next_result($link));
}
/* close connection */
mysqli_close($link);
?>

Answer 1

Try UNION for this
<?php
$link = mysqli_connect("localhost", "root", "", "uoh");
$query = "SELECT * FROM `student_record` where id = 201102887 UNION SELECT * FROM `course` where id = 201102887";
$result = mysqli_query($link, $query);
while($row = mysqli_fetch_row($result))
{
print_r($row);
}
?>
This should print two arrays (one per row), one from the student_record table (assuming id is unique) and one from the course table assuming that id is unique.