How to add a data to each JSON object PHP - php

Question

I'm getting posts details from 'postsTable' with php and encoding it in JSON Like this way
$result_json = mysqli_fetch_all ($result, MYSQLI_ASSOC);
echo json_encode($result_json);
each post has a unique ID
Then I have another table called 'postsLikes' I want to see how many Likes the post have using mysqli_num_rows()
But my question is how can I add the data it returns to each object in Encoded JSON ?
$query_checkup = "SELECT * FROM postsTable WHERE Post_AgeFrom < $age AND $age < Post_AgeTo AND Post_Reviewed = 1";
$result=mysqli_query($con, $query_checkup);
$result_json = mysqli_fetch_all ($result, MYSQLI_ASSOC);
echo "{\"result\":";
echo json_encode($result_json);
echo "}";

Answer 1

You should append extra data to your array before encoding to json.
foreach ($result_json as $key => $result) {
$result_json[$key]['likes'] = getLikes();
}
echo json_encode($result_json);
And you need to implement getLikes function as you wish or can do the operation inside foreach loop.
There a note that you need to pay attention: you need to query for each product to get likes. It is better to join tables and format your array as your need in a loop.

Answer 2

Maybe you can create a new array and use the foreach construct to add the previous values and the new values.
$new_array = array();
foreach($result_json as $result){
$new_array[] = array(
'id' => $result['id'],
'likes' => getlikes($result['id'])
);
}
function getlikes($id){
// your code to get likes number with mysqli_num_rows()
}
echo json_encode($new_array);

Answer 3

You should join the 'postsLikes' table in your original query to pull in all the data you need with a single trip to the database.
Something like this:
(Guessing on how your tables are setup)
$query = "
SELECT
P.* ,
L.Likes
FROM postsTable P
LEFT JOIN postsLikes L ON L.Post_id = P.Post_Id
WHERE
P.Post_AgeFrom < :age AND
:age < P.Post_AgeTo AND
P.Post_Reviewed = 1 ";
$params = array( "age" => $age );
$pdo = new PDO('mysql:dbname=testdb;host=127.0.0.1', $user, password);
$stmt = $pdo->prepare( $query );
$stmt->execute( $params );
$results = $stmt->fetchAll( PDO::FETCH_ASSOC );
$response = array( "results" => $results );
echo json_encode( $response );
Other bits of advice:
1) Use bound parameters to prevent SQL injection.
2) Don't manually create any of the JSON in your response, create the response array first and let json_encode do the rest of the work