I am new in python,I am sending a php json encoded array to python
like this:
$myArray = array(1,5,8,6);
$jsonArray = json_encode($myArray);
exec("python ".$absPath."/myPythonFile.py $absPath $parm $jsonArray",$out);
Here is the python code:
from pydfs_lineup_optimizer import *
import sys
import json
optimizer = LineupOptimizer(FanDuelBasketballSettings)
optimizer.load_players_from_CSV("test_new.json")
try:
players_that_you_want = []
for number in sys.argv[3]:
print number
lineups = optimizer.optimize()
for l in lineups:
print(l)
except LineupOptimizerException as e:
print(e)
When I am trying to print number variable inside python file,This is how python returning:
[
1
,
5
,
8
,
6
]
and I want it like this:
1
5
8
6
Any Idea What I am doing wrong?
The argument is being sent in as a string, so you're not actually splitting it into the proper values with your loop. You can try stripping the square brackets and using split(',').
input = "[1,2,3,4]"
processed_input = input.strip('[]').split(',')
The above code will do the job.
This is what we need to do:
from pydfs_lineup_optimizer import *
import sys
import json
optimizer = LineupOptimizer(FanDuelBasketballSettings)
optimizer.load_players_from_CSV("test_new.json")
try:
players_that_you_want = []
for number in json.loads(sys.argv[3]):
print number
lineups = optimizer.optimize()
for l in lineups:
print(l)
except LineupOptimizerException as e:
print(e)
Related
I am working on this project that requires me to upload pictures on PHP, execute the picture on python, fetch the output from python and display it again on PHP.
PHP code:
<?php
$command = shell_exec("python C:/path/to/python/KNNColor.py");
$jadi = json_decode($command);
var_dump($jadi);
?>
Python code:
from PIL import Image
import os
import glob
import cv2
import numpy as np
import matplotlib.pyplot as plt
from skimage import io, color
from scipy.stats import skew
#data train untuk warna
Feat_Mom_M = np.load('FeatM_M.npy')
Feat_Mom_I = np.load('FeatM_I.npy')
Malay_Col_Train = Feat_Mom_M
Indo_Col_Train = Feat_Mom_I
#Data warna
All_Train_Col = np.concatenate((Malay_Col_Train, Indo_Col_Train))
Y_Indo_Col = [0] * len(Indo_Col_Train)
Y_Malay_Col = [1] * len(Malay_Col_Train)
Y_Col_Train = np.concatenate((Y_Malay_Col, Y_Indo_Col))
Train_Col = list(zip(All_Train_Col, Y_Col_Train))
from collections import Counter
from math import sqrt
import warnings
#Fungsi KNN
def k_nearest_neighbors(data, predict, k):
if len(data) >= k:
warnings.warn('K is set to a value less than total voting groups!')
distances = []
for group in data:
for features in data[group]:
euclidean_dist = np.sqrt(np.sum((np.array(features) - np.array(predict))**2 ))
distances.append([euclidean_dist, group])
votes = [i[1] for i in sorted(distances)[:k]]
vote_result = Counter(votes).most_common(1)[0][0]
return vote_result
image_list = []
image_list_pixel = []
image_list_lab = []
L = []
A = []
B = []
for filename in glob.glob('C:/path/to/pic/uploaded/batik.jpg'):
im=Image.open(filename)
image_list.append(im)
im_pix = np.array(im)
image_list_pixel.append(im_pix)
#ubah RGB ke LAB
im_lab = color.rgb2lab(im_pix)
#Pisah channel L,A,B
l_channel, a_channel, b_channel = cv2.split(im_lab)
L.append(l_channel)
A.append(a_channel)
B.append(b_channel)
image_list_lab.append(im_lab)
<The rest is processing these arrays into color moment vector, it's too long, so I'm skipping it to the ending>
Feat_Mom = np.array(Color_Moment)
Train_Set_Col = {0:[], 1:[]}
for i in Train_Col:
Train_Set_Col[i[-1]].append(i[:-1])
new_feat_col = Feat_Mom
hasilcol = k_nearest_neighbors(Train_Set_Col, new_feat_col, 9)
import json
if hasilcol == 0:
#print("Indonesia")
print (json.dumps('Indonesia'));
else:
#print("Malaysia")
print (json.dumps('Malaysia'));
So as you can see, There is only one print command. Shell_exec is supposed to return the string of the print command from python. But what I get on the "var_dump" is NULL, and if I echo $jadi, there's also nothing. Be it using print or the print(json) command
The fun thing is, when I try to display a string from this python file that only consists 1 line of code.
Python dummy file:
print("Hello")
The "Hello" string, shows up just fine on my PHP. So, is shell_exec unable to read many codes? or is there anything else that I'm doing wrong?
I finally found the reason behind this. In my python script there are these commands :
Feat_Mom_M = np.load('FeatM_M.npy')
Feat_Mom_I = np.load('FeatM_I.npy')
They load the numpy arrays that I have stored from the training process in KNN and I need to use them again as the references for my image classifying process in python. I separated them because I was afraid if my PHP page would take too long to load. It'd need to process all the training data, before finally classifying the uploaded image.
But then when I execute my python file from PHP, I guess it returns an error after parsing those 2 load commands. I experimented putting the print command below them, and it stopped showing on PHP. Since it's all like this now, there's no other way than taking the worst option, even if it'd cost me long loading time.
I tested this in the console:
php > var_dump(json_decode("Indonesia"))
php > ;
php shell code:1:
NULL
php > var_dump(json_decode('{"Indonesia"}'))
php > ;
php shell code:1:
NULL
php > var_dump(json_decode('{"Indonesia":1}'))
php > ;
php shell code:1:
class stdClass#1 (1) {
public $Indonesia =>
int(1)
}
php > var_dump(json_decode('["Indonesia"]'))
php shell code:1:
array(1) {
[0] =>
string(9) "Indonesia"
}
you have to have it wrapped in {} or [] and it will be read into an object or an array.
After an error you can run this json_last_error() http://php.net/manual/en/function.json-last-error.php and it will give you an error code the one your's returns should be JSON_ERROR_SYNTAX
I'd like to be able to pass a PHP array to a Python script, which will utilize the data to perform some tasks. I wanted to try to execute my the Python script from PHP using shell_exec() and pass the JSON data to it (which I'm completely new to).
$foods = array("pizza", "french fries");
$result = shell_exec('python ./input.py ' . escapeshellarg(json_encode($foods)));
echo $result;
The "escapeshellarg(json_encode($foods)))" function seems to hand off my array as the following to the Python script (I get this value if I 'echo' the function:
'["pizza","french fries"]'
Then inside the Python script:
import sys, json
data = json.loads(sys.argv[1])
foods = json.dumps(data)
print(foods)
This prints out the following to the browser:
["pizza", "french fries"]
This is a plain old string, not a list. My question is, how can I best treat this data like a list, or some kind of data structure which I can iterate through with the "," as a delimiter? I don't really want to output the text to the browser, I just want to be able to break down the list into pieces and insert them into a text file on the filesystem.
Had the same problem
Let me show you what I did
PHP :
base64_encode(json_encode($bodyData))
then
json_decode(shell_exec('python ' . base64_encode(json_encode($bodyData)) );
and in Python I have
import base64
and
content = json.loads(base64.b64decode(sys.argv[1]))
as Em L already mentioned :)
It works for me
Cheers!
You can base64 foods to string, then passed to the data to Python and decode it.For example:
import sys, base64
if len(sys.argv) > 1:
data = base64.b64decode(sys.argv[1])
foods = data.split(',')
print(foods)
If you have the json string: data = '["pizza","french fries"]' and json.loads(data) isn't working (which it should), then you can use: MyPythonList = eval(data). eval takes a string and converts it to a python object
Was having problems passing json from PHP to Python, my problem was with escaping the json string, which you are doing. But looks like you were decoding then re-encoding with "food"
From what I understand
Python json.dumps(data) == PHP json_encode(data)
Python json.loads(data) == PHP json_decode(data)
json.loads(data) -> String Data
json.load(data) -> File Data
json.dumps(data) -> String Data
json.dump(data) -> File Data
PHP:
$foods = array("pizza", "french fries");
$result = shell_exec('python ./input.py ' . escapeshellarg(json_encode($foods)));
echo $result;
Python:
data = json.loads(sys.argv[1])
for v in data:
print(v)
ALSO
if you are passing key:value
PHP:
$foods = array("food1":"pizza", "food2":""french fries");
$result = shell_exec('python ./input.py ' . escapeshellarg(json_encode($foods)));
echo $result;
Python:
data = json.loads(sys.argv[1])
for(k,v) in content2.items():
print("k+" => "+v)
Python:
data = json.loads(sys.argv[1])
print(data['food1'])
I am new to python. I have created a gui based app to insert values into database.
I have created a Rest api to handle db operations. How can i append the api URL with json created in python.
app.py
from Tkinter import *
import tkMessageBox
import json
import requests
from urllib import urlopen
top = Tk()
L1 = Label(top, text="Title")
L1.pack( side = TOP)
E1 = Entry(top, bd =5)
E1.pack(side = TOP)
L2 = Label(top, text="Author")
L2.pack( side = TOP)
E2 = Entry(top, bd =5)
E2.pack(side = TOP)
L3 = Label(top, text="Body")
L3.pack( side = TOP)
E3 = Entry(top, bd =5)
E3.pack(side = TOP)
input = E2.get();
def callfunc():
data = {"author": E2.get(),
"body" : E3.get(),
"title" : E1.get()}
data_json = json.dumps(data)
# r = requests.get('http://localhost/spritle/api.php?action=get_uses')
#url = "http://localhost/spritle/api.php?action=insert_list&data_json="
#
url = urlopen("http://localhost/spritle/api.php?action=insert_list&data_json="%data_json).read()
tkMessageBox.showinfo("Result",data_json)
SubmitButton = Button(text="Submit", fg="White", bg="#0094FF",
font=("Grobold", 10), command = callfunc)
SubmitButton.pack()
top.mainloop()
Error:
TypeError: not all arguments converted during string formatting
i AM GETTING error while appending url with data_json ?
There is an error on string formating:
Swap this:
"http://localhost/spritle/api.php?action=insert_list&data_json="%data_json
by this:
"http://localhost/spritle/api.php?action=insert_list&data_json=" + data_json
or:
"http://localhost/spritle/api.php?action=insert_list&data_json={}".format(data_json)
The following statements are equivalents:
"Python with " + "PHP"
"Python with %s" % "PHP"
"Python with {}".format("PHP")
"Python with {lang}".format(lang="PHP")
Also, I don't think sending JSON data like this via URL is a good idea. You should encode the data at least.
You are trying to use % operator to format the string, and you need to put the %s placeholder into the string:
"http://localhost/spritle/api.php?action=insert_list&data_json=%s" % data_json
Or use other methods suggested in another answer.
Regarding the data transfer - you definitely need to use POST request and not GET.
Check this, using urllib2 and this, using requests.
my php code:
<?php
$data = array('as', 'df', 'gh');
$result=shell_exec("start test.py ".escapeshellarg(json_encode($data)));
?>
test.py code:
import sys
import json
try:
print json.loads(sys.argv[1])
except:
print "ERROR"
print
raw_input()
it's failing to try and showing ERROR.
while if change my python code to this:
import sys
try:
data=sys.argv[1]
except:
print "ERROR"
print data,
raw_input()
i'm getting the output as: [ as , df , gh ]
as i'm passing a json encoded data, i should be able to decode it with python's json.loads() method. but why it's not working?
don't know how it's working. but able to tune the program according to what i want.
php code:
<?php
$data = array('1'=>"as",'2'=>"df",'3'=>"gh");
$result=shell_exec("start test.py ".json_encode(json_encode($data)));
?>
test.py:
import sys
import json
try:
data=sys.argv[1]
except:
print "ERROR"
print data
dit=json.loads(data)
print dit
print dit['1']
raw_input()
and got the output as required:
{"1":"as","2":"df","3":"gh"}
{u'1': u'as', u'3': u'gh', u'2': u'df'}
as
someone having a good knowledge in these pls explain.
The problem is the following:
On Windows, escapeshellarg() removes percent signs, replaces double
quotes with spaces and adds double quotes around the string.
-> https://secure.php.net/manual/en/function.escapeshellarg.php
I'd recommend using addslashes(...)
exec("test.py " . addslashes(json_encode($json)) . " 2>&1", $output, $exit_code);
PHP code:
<?php
$arr=array(array('1','2','3','4'),array('21','12','23','54'),array('10','23','35','41'),array('14','62','93','40'));
$result = shell_exec("C:/Python27/python 123.py ".json_encode($arr));
echo $result;
?>
python code:
import sys, json
arr=sys.argv[1]
print arr
A=np.matrix(arr)
print A
print ("<br/>")
M=A.I
print M
result = {'Name':'abc'}
print ("Sending data to PHP")
print (json.dumps(result))
The output given as inverse is not coming correct plus the A matrix is coming out to be of dimenesion 1x16 instead of 4x4 and the dimension of array arr is correct(4x4).How to debug it and get correct matrices A and M?
You seem not to be decoding the JSON within the Python script, whilst json_encode($arr) should be json_decode($arr) unless I'm wrong.