Trying to connect sql database in xampp - php

Question

<?php
$host = 'localhost';
$user = 'root'
$password = '';
$db ='members';
$connection = mysqli_connect("localhost", "user", "password") or die("Unable to connect to the server!");
mysqli_select_db("members", $connection) or die("Couldn't connect to the database!");
I have installed xampp and create database named "members". I tried to connect it to phpmyadmin but didn't work. I try to google all the answers since three days but in vain. Please help me...

Answer 1

<?php
$host = 'localhost';
$user = 'root';
$password = '';
$db ='members';
$connection = mysqli_connect($host,$user,$password,$db);// you can select db separately as you did already
if($connection){
// do all your stuff that you want
}else{
echo "db connection error because of".mysqli_connect_error();
}

Answer 2

Are your credentials for username and password correct?
By default, the localhost has username = root and password as blank.
Also, what's the issue? Is it showing "Unable to connect to the server!"?

Answer 3

You are missing a semicolon after $user = 'root' and you are using a mixture of mysql_ and mysqli_. Also, you could select a table by passing a fourth argument to mysqli_connect()
$host = 'localhost';
$user = 'root';
$password = '';
$db ='members';
$connection = mysqli_connect($host,$user,$password,$db);// you can select db separately as you did already
if($connection){ echo "Connected Successfully";}else{ echo "Error connecting: . mysqli_connect_error()"; }
Use mysqli_ to do queries:
mysqli_query($connection, "INSERT INTO user_login (uname,upassword,email) VALUES ('$uname','$upassword','$email')");
I recommend you to use prepared statements to avoid SQL injection.
So the above query would look like:
$stmt->prepare("INSERT INTO user_login (uname,upassword,email) VALUES (?,?,?)");
$stmt->bind_param('sss', $uname, $upassword, $email);
$stmt->execute();