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I need to put a shortcode inside a php variable like this.
<?php
var Variable = "<div class='container-uppotential'>
</div>
<div class='container-historialdepagos'>
</div>
<?php echo do_shortcode('[mper_account_form]');?>
";
return Variable;
?>
But it doesn't work like that. Any idea how can I make this code work as it is in the example?
first of all you are in php, then your variables should start with the $ sign, then you save the html markup, in a variable, and output it, finally, after all the markup your insert your shortcode. (By the way you have a typo in the shorcode, is mepr not mper)
<?php
$variable = "<div class='container-uppotential'>
</div>
<div class='container-historialdepagos'>
</div>";
echo $variable;
echo do_shortcode('[mepr_account_form]');
?>
PHP is executed before anything is sent to the browser. PHP is not executed in the browser, only by the server.
You're trying to emit PHP code in Javascript. Javascript is executed in the browser. By the time the Javascript is executed, the PHP execution is long over. The server never sees the PHP code.
Basically you can't emit PHP in Javascript and expect it to work. You can emit Javascript in PHP, because the PHP will be executed first, and the resulting javascript will be sent to the browser, where the javascript will then be executed.
Imagine running the microwave for a minute, then putting a glass of water in it. The water will not be heated, because you added the water after the water-heating process.
If I were you, I would make the do_shortcode() call and save the result in a PHP variable, then emit the contents of that variable into the Javascript. That way the PHP execution happens at the PHP execution stage.
Now, if you depend on the Javascript to set some state that the PHP function depends on, you're next bet would be to use something like AJAX, and write a standalone PHP servlet that takes the state information from the AJAX call, executes PHP to generate the desired output, then the Javascript displays the result in the AJAX component.
The only problem I see with your code is that Javascript doesn't allow strings to contain newlines, so you need to split it up if you want it on multiple lines.
var Variable = "<div class='container-uppotential'>" +
"</div>" +
"<div class='container-historialdepagos'>" +
"</div>" +
"<?php echo do_shortcode('[mper_account_form]');?>";
return Variable;
Related
I am trying to hide our mailing address on our website, until someone cliks a button to "load" the address. I am doing it like follows:
Homepage.php:
<button onclick="test()"> Click </button>
<div> </div>
<script>
function test(){
$.ajax({url:"address.php", success:function(result){
$("div").text(result);}
})
}
</script>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.2.4/jquery.min.js"></script>
Address.php:
<?php
function php_func(){
echo '<span><?php echo $address; ?></span>';
}
php_func();
?>
This works in echoing the text onto homepage.php, but it's not loading the PHP function. Just showing the function as text as seen here:
I tried $("div").write(result);} and it won't even load.
$address is already defined elsewhere. Any tips?
You're trying to write code which outputs code which outputs the address. Why? You're already in the context of outputting something from the PHP code:
echo "something...";
If what you want to output is the value of $address then just output that:
echo "<span>$address</span>";
I suspect the reason you did it that way is because you're expecting the currently loaded page to parse and execute that PHP code. This is a fundamental misunderstanding of how these technologies work. The PHP code for that page executed once, on the server, and delivered the resulting HTML/CSS/JavaScript to the client.
The AJAX operation is making a new, separate request to another PHP resource which will execute on the server and output back to the client. In this case it's just outputting a string value, which the client-side JavaScript code will then write to an element on the page:
$("div").text(result);
(This is a good opportunity for you to use your browser's debugging tools and observe the AJAX request/result in the network tab, to see what's actually being sent/received. At no point should actual PHP code be visible to the browser. All of that is executed on the server.)
The reason this is important is because, if this is the case, then you are likely misunderstanding where $address is defined. If it's defined in the PHP script which rendered the page you're looking at, that doesn't mean it's defined in address.php. If the code you're showing us for address.php is the entirety of that page then $address is not defined.
So you'll need to define $address on that page.
After having said all of that... You might find it much easier not to involve AJAX for this at all in the first place. Just output the address to the page but style the <span> to not be visible. Then when the user clicks the button, make it visible. No need for the complexity of an entirely new HTTP request:
$('button').click(function () {
$('span').show();
});
span {
display: none;
}
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<button>Click</button>
<span>this is the address</span>
You don't use <?php echo inside strings; that's only used when you're in a section of the script that's outputting literal text, not executing PHP code.
If you're in PHP code doing echo, you use variable substitution or concatenation.
<?php
function php_func(){
echo "<span>$address</span>";
}
php_func();
?>
You'll need additional code to set the $address variable; I assume you just left that out for simplification in the question.
<?php
function php_func(){
echo '<span>' . $address .'</span>';
}
php_func();
?>
this should work, u can't use 'echo' and inside echo open 'php' tag to use again.... more another 'echo'
This question already has answers here:
What is the difference between client-side and server-side programming?
(3 answers)
Closed 7 years ago.
So now i now this was a dumb question but does anyone now the best way to solve it without an ajax request, becaus I think it would be stupid to make a new file for just one line of code
I am making a gallery and I want two types of views one grid-view and a slide view. My slide and my grid view both work but they stand in different files. So I wrote a simple jquery function to load some php code into the html code. So that when I click a button the html code dissappears and there is php code. The jquery funtion works but the problem is that when the code is changed it doesn't recognise it as php code but just as a string.
This is what I see, you can see the text but it needs to execute that code:
Here is the jquery function:
$(document).ready(function(){
$("img.grid_icon").click(function() {
$(".werkvenster").html("<?php include_once('resources/UberGallery.php'); $gallery = UberGallery::init()->createGallery('img/gallerij/'); ?>");
})
});
I use the < and >, otherwise the browser sees it as php code it has to execute instead of seeing it as a string.
Here is the html code it has to be in:
<body>
<section class="werkvenster">
<img src="img/website/icon_grid.png" height="30px" class="grid_icon">
<div class="galerij" id="galerij">
</div>
<button class="omlaag" id="galerij_knop">Terug</button>
<button class="omhoog" id="galerij_knop">Verder</button>
</section>
</body>
So everything between the section tags with class "werkvenster" needs to be changed by
<?php include_once('resources/UberGallery.php'); $gallery = UberGallery::init()->createGallery('img/gallerij/'); ?>
When someone clicks on the grid icon.
Thanks a lot in advance and please don't mark this as a duplicate because I have been searching for over an hour to find an answer to this question.
It seems you need some clarification how PHP and JS work.
a) PHP-code is executed on the server-side. all of it. and nothing else
b) The output, completely free of PHP, is sent to the browser
c) JS-code is executed on the client-side. all of it. and nothing else
If you use JS to write PHP-code, it only happens inside the browser, which doesn't know what to do with it. and long after every bit of PHP-execution.
You do NOT write anything back to the server with this.
what you CAN do is to do an AJAX-request to a specific PHP file that returns your desired output. but you can't just mix JS and PHP like that. it just doesn't work.
edit: in response to your edit about how to solve the problem without using AJAX
to put it simply: not at all. you have to get the data from the server, the best way to do this is AJAX (it was made for this and nothing else) and on the server you have to generate the data somehow. and the cleanest way is a new file.
it doesn't recognise it as php code but just as a string
That's because it is a string:
"<?php include_once('resources/UberGallery.php'); $gallery = UberGallery::init()->createGallery('img/gallerij/'); ?>"
PHP doesn't run in the browser, it runs on the server. By the time the page is delivered to the browser, the PHP code has executed and completed and produced its output. PHP is no longer involved after that point.
If you want to execute code client-side, that's what JavaScript is for. If you need code to execute server-side, the browser will have to make a request to the server to make that happen. A page load, a form post, AJAX, etc. They all take the form of an HTTP request (potentially with some data sent to the server) which invokes a PHP script and receives that script's output as the response.
You could do what you are trying to do without ajax. You just have to create a hidden <section> that contains the php code (which you have to do on the server-side before it gets sent to the browser). And then in the browser, use jquery to get the contents from the hidden <section> (or just swap the sections)
Here is an example:
Server-side PHP:
<body>
<section class="werkvenster">
<img src="img/website/icon_grid.png" height="30px" class="grid_icon">
<div class="galerij" id="galerij">
</div>
<button class="omlaag" id="galerij_knop">Terug</button>
<button class="omhoog" id="galerij_knop">Verder</button>
</section>
<section id="hiddenStuff" style="display:none">
<?php include_once('resources/UberGallery.php'); $gallery = UberGallery::init()->createGallery('img/gallerij/'); ?>
</section>
</body>
jQuery:
$(document).ready(function(){
$("img.grid_icon").click(function() {
$(".werkvenster").html($("#hiddenStuff").html());
})
});
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I am trying to pass JS variable to php echo statement.
here is my code
<?php print 'test'; ?>
how can I do that
I just test this and it works but how can I write the value within the href
alert(myvalue); ";
This is impossible from a temporal point of view.
When the PHP code is run, there is no JavaScript. The page is not yet loaded into the browser. There is no JavaScript engine being run. There are no JavaScript variables. By the time the browser renders the page, the server code has already done its job.
With that said, you can render HTML which refers to a JavaScript function. For example:
<?php print 'test'; ?>
Then, implement DoNav accordingly:
function DoNav(url)
{
location.href = url + '?id=' + my_JS_value; // Navigate to the new URL with the JavaScript variable
}
JavaScript and PHP cannot directly communicate as JavaScript is client-side and PHP is server-side, i.e. PHP is executed before the JavaScript is sent to the browser.
The only way to achieve what you want is to sent a request from JavaScript that calls a PHP script (e.g. AJAX) and passes the variable via GET (like your example) or POST.
Javascript code is executed on the client side, so you do not have access to it.
You can just create the link using Javascript, like this:
var my_JS_value = 0;
document.write('test');
You can insert the element with php and set the href attribute later with JS. Anyway there's a ton of other ways to achieve the same.
<?php
print '<a id="mylinkelement" >test</a>
<script>
var mylinkelement=getElementById("mylinkelement");
mylinkelement.href="thisTest.html?id="+my_JS_value;
</script>';
?>
You don't even need php for that :D
Okay, I have created a new question to clarify my old one, which is available here: Check if certain text was outputted to the screen PHP
Currently I have this code:
<?php
echo "
<noscript><h2>! JavaScript is not enabled!!! Features will not work !</h2></noscript>
<script type=\"text/javascript\">
document.cookie= \"jsEnabled=true\";
</script>
";
if (isset($_COOKIE['jsEnabled'])) {
// Javascript is enabled!
}
else {
die("JavaScript is not enabled!");
}
?>
I am not sure why this wont work! It should kill the PHP if JS is disabled! Thanks!
JavaScript processes after PHP has fully given out the page, not before, and not in symbiosis. As such, your PHP call will only work for the second call to the page, not the first.
That is, if you accept cookies in the first place.
If you want to prevent users without JS from using the interface on a page, consider generating the interface in pure JS instead. More reliable.
Here is what I'm trying to do...
$("div").prepend("<div id='comment-number'><?php the_comment_number(); ?></div>");
Is there some way to get this to work?
<div class="gallery-item">
<div class="comment-number"><!--?php echo htmlspecialchars(the_comment_number()); ?--></div>
</span>
<span class="gallery-icon">
<img src="http://mysite.com/test/wp-content/uploads/2011/06/fff-150x150.gif">
</span>
</div>
PHP is executed on the server, but JavaScript code (jQuery) is executed later, in the web browser. For that reason, PHP can produce JavaScript code, but JavaScript can't produce PHP code.
The <!--? in your posted output shows that something is filtering our your PHP code. So the problem isn't your PHP code, it's that you're not actually executing PHP code. If it's a .js file, PHP almost certainly can't be included.
If PHP were being evaluated (ex. if this were in a <script> tag in a .php file), this should produce valid JavaScript code that will do what you want:
$("div").prepend("<div id='comment-number'><?php echo htmlspecialchars(the_comment_number()); ?></div>");
1) php is SERVER side scripting
2) javascript is CLIENT side scripting (generally)
so this is what happens:
1) User opens up your page http://example/
2) Your CLIENT sends GET request to http://example/ server
3) Apache (given you run on it) captures the request, based on the server config approaches index.php (index.html, etc). If php is installed, your index.php will be parsed by mod_php module
<<<< this is where SERVER side scripting is activated
4) outcome of the parsing of index.php will be then transferred back to CLIENT
5) CLIENT will digest the outcome received by SERVER
6) If there are javascript calls, those are executed either immediately OR when document is loaded (based on approach)
That's it. Here normal request life ends.
NOW if you want your page to dynamically update some parts of it, here is how you do that:
1) Usually to update your page dynamically, you would use AJAX approach. When AJAX request is created, 2-7 happens again, but this time the caller is your ajax process and information which is received is sent back to that process to decided what to do with it.
Okay, some coding:
1) index.php
<!-- include jquery, etc //-->
<div id="comments"></div>
<script>
function fetch_comments(){
$.get("ajax.php", null, function(data)){
// this is called, when response from SERVER is received
$("#comments").prepend(data);
setTimeout("fetch_comments", 5000); // fetch again in 5 seconds
}
}
$(document).ready({
fetch_comments();
});
</script>
2) ajax.php
<?php
//fetch comments, return them for CLIENT
echo "<p>Comment on " . date("Y-m-d H:i:s") . "<br />Lorem Ipsum</p>";
This should help you understand the whole process. Did not test the code, but should be quite ok.
do a .ajax() query to PHP script that will provide you value of the_comment_number(); and put result to comment-number by $("#comment-number").prepend(result); on success event in ajax query.
Remebmer that PHP script have to have connection to database and pass to it all variables you need (like entity id, article id, page etc.). You can do it by GET or POST.
Request is sended by browser so session/cookies will be the same unless you changed it in current request.
PHP is executed on the server side so you cannot call it from javascript
You can try something like this which will render once the page loads
$("div").prepend("<div id='comment-number'>"+ <?php the_comment_number(); ?> +"</div>");
Couldn't you just add the value directly to the template instead of using javascriot? eg:
<div class="gallery-item">
<div class="comment-number"><?php echo (the_comment_number());?></div>
...
</div>
Also you have a </span> tag with out matching <span> tag in your example.
As already told, you can't produce or call php code from javascript directly(you need to make an ajax call or form submit). You need to make ajax call using jquery to fetch the comment number and then update it into div.
However, you may want to look at this library - http://www.phplivex.com/ .It may help you in doing things your way. It allows you to call user defined php functions in javascript using AJAX internally.
Reading through this disccussion and from what i understand you want to acheive.. You gotta figure how your page is served. If it is an .php file that is serving the content, then you wont need Javascript at all and could get your function call to work by adding the function between the div as so..
<div class="comment-number"><?php echo htmlspecialchars(the_comment_number()); ?></div>
Assuming you don't have access to the .php or if its a .html/htm page that serves the content then your only bet would be to use ajax. That is make an ajax call to a php file(on the same domain) that makes your function call and echos the comment no. The Ajax will retrieve the echo'd comment no. which you can append/prepend to the desired