Laravel 5. Using the USING operator - php

Question

I tried to find it for a long time, and I can't believe that Laravel doesn't have this functionality.
So, I can write:
select * from a join b where a.id = b.id
or more beautiful:
select * from a join b using(id)
First case is simple for Laravel:
$query->leftJoin('b', 'a.id', '=', 'b.id')
But how to write second case? I expect that it should be simple and short, like:
$query->joinUsing('b', 'id')
But thereis no such method and I can't find it.
PS: it's possible that the answer is very simple, it's just hard to find by word "using", because it's everywhere.
UPDATE
I'm going deeper to source, trying to make scope or pass a function to join, but even inside of this function I can't to anything with this $query. Example:
public function scopeJoinUsing($query, $table, $field) {
sql($query->join(\DB::raw("USING(`{$field}`)")));
// return
// inner join `b` on USING(`id`) ``
// yes, with "on" and with empty quotes
sql($query->addSelect(\DB::raw("USING(`{$field}`)")));
// return
// inner join `b` USING(`id`)
// but in fields place, before "FROM", which is very logic :)
}
So even if forget about scope , I can't do this in DB::raw() , so it's impossible... First time I see that something impossible in Laravel.

Answer 1

So, the answer is - it's impossible.
Laravel doesn't support this functionality, which is really sad.
I fix it in Laravel source code, my PULL REQUEST here - https://github.com/laravel/framework/pull/12773

Answer 2

Nothing is impossible in Laravel.
Until support for join using is added to Laravel core, you can add support for it by installing this Laravel package: https://github.com/nihilsen/laravel-join-using.
It works like this:
use Illuminate\Support\Facades\DB;
use Nihilsen\LaravelJoinUsing\JoinUsingClause;
DB::table('users')->leftJoin(
'clients',
fn (JoinUsingClause $join) => $join->using('email', 'name')
);
// select * from `users` left join `clients` using (`email`, `name`)