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I have a piece of code below and according to a condition I wanted to know why the question is invalid
CREATE VIEW HotelBookingCount (hotelNo, bookingCount)
AS SELECT h.hotelNo, COUNT(*)
FROM Hotel h, Room r, Booking b
WHERE h.hotelNo = r.hotelNo AND r.roomNo b.roomNo
GROUP BY h.hotelNo;
The question is :
SELECT hotelNo
FROM HotelBookingCount
WHERE bookingCount > 1000;
When I type it shows error
What is the logic behind this? Why I am not supposed to do this?
You can't have VIEWs that way and also there is nothing to pass the arguments as they are unused. Try with -
CREATE VIEW HotelBookingCount
AS SELECT h.hotelNo, COUNT(*) bookingCount
FROM Hotel h, Room r, Booking b
WHERE h.hotelNo = r.hotelNo AND r.roomNo b.roomNo
GROUP BY h.hotelNo;
Then
SELECT hotelNo
FROM HotelBookingCount
WHERE bookingCount > 1000;
Related
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I want something like this:
Table
And my database table is like this:
Database
How can I get this records group by (hour and post) at the same time?
And How can I print this results on html?
SELECT post_id, hour, COUNT(*) FROM <table_name> GROUP BY post_id, hour
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I have already searched for possible answers but did not find any who helped me further.
I have two tables. One named users, where the user details are saved like: Name, ID, etc.
Second one is a table where the payments are stored.
Payments:
payment_id
date
amount
user_id
completed
Now I try to get all the payments of a user:
SELECT COUNT(amount) FROM ...
I already have tried this but did'nt gave me the right amount that has been paid.
SELECT
g.name,
g.user_id,
COUNT(m.amount) AS totalAmount
FROM users AS g
LEFT JOIN payments AS m ON g.user_id = m.user_id
GROUP BY g.user_id
Do you just want... SUM(m.amount) instead of COUNT(m.amount) ?
COUNT(m.amount) gives you the number of rows that were aggregated (that means the total number of payments).
SUM(m.amount) is the cumulated value of field m.amount, that is the total amount.
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Closed 7 years ago.
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I want to get data from database from specific row to last row.
How can I do it?
You can set limit and offset with your sql query like this.
SELECT *
FROM your_table
ORDER BY id DESC
LIMIT 1, 1;
See more : http://www.mysqltutorial.org/mysql-limit.aspx
$sql="Select * from table order by id desc limit 20";//It will give you last 20 records
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Closed 8 years ago.
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What's wrong with this query and how can i output the result?
`SELECT sum(BM) from (SELECT rpdc.BM from rpdc LIMIT $start, $limit) as totalbm`
You need to give an alias for the sum something as
SELECT
sum(BM) as total_sum
from (SELECT rpdc.BM from rpdc LIMIT $start, $limit) as totalbm
Then in php you can use as
$row['total_sum'];
Hey you need to add as 'some_name' like SELECT name as firstname
Replcae with this sum(BM) as total
So, result array will treat total_sum as key of array.
You can use it as $result['total']
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I have this query:
$sql = $link->query("SELECT m.id_rel, (SELECT SUM(visita) as total FROM icar_mas_vistas WHERE id_rel = m.id_rel), icar_categorias.nombre
FROM icar_mas_vistas AS m, icar_categorias WHERE m.id_rel = icar_categorias.id_categoria");
if($sql->num_rows){
while($row = $sql->fetch_object()){
echo ''.$row->total.' '.$row->nombre.'';
}
It's working great in the SQL console, but when printing in PHP the value of total is not showing, how can i print it?
Thanks
Try change query adding AS total after brackets, to:
SELECT m.id_rel,
(SELECT SUM(visita) as total FROM icar_mas_vistas WHERE id_rel = m.id_rel) AS total, icar_categorias.nombre
FROM icar_mas_vistas AS m, icar_categorias
WHERE m.id_rel = icar_categorias.id_categoria