Unable to get feed content with CURL - php

Question

I'm trying to get the content of this feed :
http://www.institut-viavoice.com/viavoice-paris/publications/sondages-publies?format=feed&type=rss
Here is my code :
$url = 'http://www.institut-viavoice.com/viavoice-paris/publications/sondages-publies?format=feed&type=rss';
$options = array(
CURLOPT_RETURNTRANSFER => true,
CURLOPT_HEADER => false,
CURLOPT_FOLLOWLOCATION => true,
CURLOPT_ENCODING => "",
CURLOPT_USERAGENT => "Mozilla/5.0 (Windows NT 6.1; WOW64; rv:18.0) Gecko/20100101 Firefox/18.0",
CURLOPT_AUTOREFERER => true,
CURLOPT_CONNECTTIMEOUT => 30,
CURLOPT_TIMEOUT => 30,
CURLOPT_MAXREDIRS => 10
);
$curl = curl_init($url);
curl_setopt_array( $curl, $options );
$content = curl_exec($curl);
curl_close($curl);
echo $content;
I tried many other CURL options but it doesn't work.
As the content is accessible through my browser, I suppose it can be done with PHP. But what is wrong with my code ? It seems like there is an exception with the server of this feed ?

Answer 1

Not sure, may be your breaking the cURL options and calling the URL.
Here a simple example, give it a try:
function get_data($url) {
$ch = curl_init();
$timeout = 5;
curl_setopt($ch, CURLOPT_URL, $url);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
curl_setopt($ch, CURLOPT_CONNECTTIMEOUT, $timeout);
curl_setopt($ch, CURLOPT_USERAGENT, "Mozilla/5.0 (Windows NT 6.1; WOW64; rv:18.0) Gecko/20100101 Firefox/18.0");
$data = curl_exec($ch);
curl_close($ch);
return $data;
}
$content = get_data('http://www.institut-viavoice.com/viavoice-paris/publications/sondages-publies?format=feed&type=rss');
echo $content;