I have a .txt file called 'test.txt' that is a JSON array like this:
[{"email":"chrono#gmail.com","createdate":"2016-03-23","source":"email"}]
I'm trying to use PHP to decode this JSON array so I can send my information over to my e-mail database for capture. I've created a PHP file with this code:
<?php
$url = 'http://www.test.com/sweeps/test.txt';
$content = file_get_contents($url);
$json = json_decode($content,true);
echo $json;
?>
For some reason, it's not echoing the decoded JSON when I visit my php page. Is there a reason for this and can anyone shed some light? Thanks!
You use echo to print scalar variables like
$x = 'Fred';
echo $x;
To print an array or object you use print_r() or var_dump()
$array = [1,2,3,4];
print_r($array);
As json_decode() takes a JSON string and converts it to a PHP array or object use print_r() for example.
Also if the json_decode() fails for any reason there is a function provided to print the error message.
<?php
$url = 'http://www.test.com/sweeps/test.txt';
$content = file_get_contents($url);
$json = json_decode($content,true);
if ( json_last_error() !== JSON_ERROR_NONE ) {
echo json_last_error_msg();
exit;
}
You'll need to split that json string into two separate json strings (judging by the pastebin you've provided). Look for "][", break there, and try with any of the parts you end up with:
$tmp = explode('][', $json_string);
if (!count($tmp)) {
$json = json_decode($json_string);
var_dump($json);
} else {
foreach ($tmp as $json_part) {
$json = json_decode('['.rtrim(ltrim($json_string, '['), ']').']');
var_dump($json);
}
}
Related
Can anyone please shows me how to get the input of PHP to JSON file (.json) and read data from JSON file and display in PHP (Echo).
for example:
$myObj->name = "John";
$myObj->age= 20;
to result.json
{"name":"John","Age":20}
and retrieve from result.json and display data in PHP as
name=John
Age=20
To convert the object to json use this:
$json = json_encode($myObj);
See the json_encode docs.
To return it back to the format you want try this...
$obj = json_decode($json);
$name = $obj->name; // John
$age = $obj->age; // 20
See the json_decode docs.
To iterate over keys and values do something like this:
foreach($obj as $key=>$value)
{
echo $key . " = " . $value . "\n";
}
json_encode() is used for encoding PHP data into a JSON format and json_decode() is used to decode JSON into a PHP data
json_encode documentation:
http://php.net/manual/en/function.json-encode.php
json_decode documentation
http://php.net/manual/en/function.json-decode.php
if you are having an php array you can convert it into json.
$json_string = json_encode($array);
and write this into a json file.
$fp = fopen('results.json', 'w');
fwrite($fp, json_string);
fclose($fp);
now convert your json string which is in results.json to array.
$str = file_get_contents('./results.json');
$array = json_decode($str, true); // decode the JSON into an associative array
here is my json
{
"rgInventory": {
"5455029633": {
"id":"5455029633",
"classid":"310776543",
"instanceid":"302028390",
"amount":"1"
}
}
}
Here is my way to parse json in php
$content = file_get_contents("http://steamcommunity.com/profiles/76561198201055225/inventory/json/730/2");
$decode = json_decode($content);
foreach($decode->rgInventory->5455029633 as $appid){
echo $appid->id;
}
I need to get that 5455029633 but it dont work in foreach.
And I want to store it in the variable too.
Json, which you've provided is invalid. Remove last comma from "amount":"1", and you are missing closing curly bracket. Then you should be able to access desired value as $decode->rgInventory->{"5455029633"}.
Or make your life simpler ;) and just go for assoc array $decode = json_decode($content, true);
You will need to pass true as second argument to the function json_decode to get an array instead of an object :
PHP
<?php
$content = file_get_contents("http://steamcommunity.com/profiles/76561198201055225/inventory/json/730/2");
$decode = json_decode($content, true);
echo $decode['rgInventory']['6255037137']['id']; // will output the property 'id' of the inventory 6255037137
$invetory = $decode['rgInventory']['6255037137'] // will store the inventory 6255037137 in the variable $inventory
?>
My php code <?php echo $art->capt; ?> gives the following output:
{"path":"location\/file.png"}
However, I want to show only location/file.png as the output and remove all the junk.
How should I proceed?
That's json. you need to decode it.
<?php
$str = $art->$capt; //'{"path":"location\/file.png"}';
$json = json_decode($str, true);
$path = $json['path'];
echo($path);
?>
That is actually JSON, you can use json_decode to turn it into an object (or array if you pass true in the second argument of json_decode). Get the HTML output. If the HTML isn't already in a variable use output buffering.
ob_start();
/*html is output here*/
$json = ob_get_contents();
$json = json_decode($json, true);
$path = $json['path'];
print_r($path);
//output should be location/file.png
I am attempting to write PHP code to interact with JSON output from Mapquest's Open API / Open Street Map service. I have listed it below. I have been using this code in my Drupal 6 implementation. This code returns no output. When I use it, json_last_error() outputs 0.
function json_test_page() {
$url = 'http://open.mapquestapi.com/directions/v1/route?outFormat=json&from=40.037661,-76.305977&to=39.962532,-76.728099';
$json = file_get_contents($url);
$obj = json_decode(var_export($json));
$foo .= $obj->{'fuelUsed'};
$output .= foo;
return $output;
}
You can view the raw JSON output by following the URL. In this function I am expecting to get 1.257899 as my output. I have two questions:
(1) What can I call so I get items out of my array. For instance, how can I get the value represented in JSON "distance":26.923 out of the array?
(2) Is it possible am I running into a recursion limit issue that I've read about in the PHP Manual?
If you read the manual page for json_decode carefully, you'll notice there is a parameter (false by default) that you can pass to have it return an array rather than an object.
$obj = json_decode($json, true);
So:
<?php
function json_test_page() {
$url = 'http://open.mapquestapi.com/directions/v1/route?outFormat=json&from=40.037661,-76.305977&to=39.962532,-76.728099';
$json = file_get_contents($url);
$obj = json_decode($json, true);
//var_dump($obj);
echo $obj['route']['fuelUsed'];
}
json_test_page();
Remove the var_export function from json_decode.
You're trying to convert information about a string to json.
I was able to get the fuelUsed property this way
function json_test_page() {
$url = 'http://open.mapquestapi.com/directions/v1/route?outFormat=json&from=40.037661,-76.305977&to=39.962532,-76.728099';
$json = file_get_contents($url);
$obj = json_decode($json);
return $obj->route->fuelUsed;
}
<?php
$handle = fopen("https://graph.facebook.com/search?q=sinanoezcan#hotmail.com&type=user&access_token=2227472222|2.mLWDqcUsekDYK_FQQXYnHw__.3600.1279803900-100001310000000|YxS1eGhjx2rpNYzzzzzzzLrfb5hMc.", "rb");
$json = stream_get_contents($handle);
fclose($handle);
echo $json;
$obj = json_decode($json);
print $obj->{'id'};
?>
Here is the JSON: {"data":[{"name":"Sinan \u00d6zcan","id":"610914868"}]}
It echos the JSON but I was unable to print the id.
Also I tried:
<?php
$obj = json_decode($json);
$obj = $obj->{'data'};
print $obj->{'id'};
?>
Note that there is an array in the JSON.
{
"data": [ // <--
{
"name": "Sinan \u00d6zcan",
"id": "610914868"
}
] // <--
}
You could try $obj = $obj->{'data'}[0] to get the first element in that array.
data is an array, so it should be:
print $obj[0]->{'id'};
It looks like the key "data" is an array of objects, so this should work:
$obj = json_decode($json);
echo $obj->data[0]->name;
Have you tried $obj->data or $obj->id?
Update: Others have noted that it should be $obj->data[0]->id and so on.
PS You may not want to include your private Facebook access tokens on a public website like SO...
It's a bit more complicated than that, when you get an associative array out of it:
$json = json_decode('{"data":[{"name":"Sinan \u00d6zcan","id":"610914868"}]}', true);
Then you may echo the id with:
var_dump($json['data'][0]['id']);
Without assoc, it has to be:
var_dump($json->data[0]->id);