I'm new with php. I'm trying to post some input with ajax but it doesn't work.
This is my HTML for input:
<div class="form-group">
<h3>Answer:</h3>
<div class="input-group">
<textarea name="q1" id="q1" class="form-control" rows="4" ></textarea>
</div>
</div>
<button type="button" id="button" class="btn btn-primary btn-lg">Submit</button>
And this is my jquery function to post data:
$(function(){
$('button').click(function(){
var q1= $('#q1').val();
$.ajax({
type: 'post',
url: 'test.php',
data: {
q1: q1
},
success: function (response) {
console.log( response);
}
});
});
});
My test.php is a simple code to display the input:
<?php
$q1= $_POST['q1'];
echo $q1;
?>
I don't know why in my test.php I get this error : Notice: Undefined index: q1 in C:\xampp\htdocs\series\file\test.php on line 2
Can anyone tell me where is the issue?
First of all you are trying to post a json data to your php file so jQuery may not create correct payload for your request since you getting undefined index:q1. Can you try the code below;
$(function () {
$('button').click(function () {
var q1 = $('#q1').val();
$.ajax({
type : 'post',
url : 'test.php',
data : "q1="+q1,
success : function (response) {
console.log(response);
}
});
});
});
Try this:
$('document').ready(function(){
$("form#data").submit(function(){
var formData = new FormData($(this)[0]);
$.ajax({
url: 'url',
type: 'POST',
data: formData,
async: false,
success: function (data)
{
alert(data);
},
cache: false,
contentType: false,
processData: false
});
return false;
});
});
}
<form id="data" method="post">
<div class="form-group">
<h3>Answer:</h3>
<div class="input-group">
<textarea name="q1" id="q1" class="form-control" rows="4" ></textarea>
</div>
</div>
<input type="submit" id="button" class="btn btn-primary btn-lg">
</form>
Related
I want to update the child div but all the divs are getting updated on ajax success.
My html
<div class="add_wishlist">
<input type="hidden" name="prd_wishlist" class="prd_wishlist" value="1">
<div class="wishlist_icon">
<p><i class="far fa-heart"></i></p>
</div>
</div>
<div class="add_wishlist">
<input type="hidden" name="prd_wishlist" class="prd_wishlist" value="2">
<div class="wishlist_icon">
<p><i class="far fa-heart"></i></p>
</div>
</div>
Jquery
$('.add_wishlist').click(function(){
var prd_wish = $(this).find("[name='prd_wishlist']").val()
$.ajax({
type: 'post',
url: weburl+'pages/login-script.php',
data: {
prd_wish:prd_wish,
wishlist_submit:'submit',
},
success: function (response) {
$('.add_wishlist').children('.wishlist_icon').html(response)
}
});
})
I also tried to update the code with $('.add_wishlist').children('.wishlist_icon').html(response) but its not working.
Store a reference to the clicked .add_wishlist element in the click handler, then use that within the success handler:
$('.add_wishlist').click(function() {
let $addWishlist = $(this);
let prd_wish = $addWishlist.find("[name='prd_wishlist']").val()
$.ajax({
type: 'post',
url: weburl + 'pages/login-script.php',
data: {
prd_wish: prd_wish,
wishlist_submit: 'submit',
},
success: function(response) {
$addWishlist.children('.wishlist_icon').html(response);
}
});
})
I Want to receive the values from the CKEditor. I Have written this HTML code
<div class="col-md-12">
<div class="form-group">
<label for="Image" class="control-label">Item Description </label>
<textarea id="item_description" name="item_description" rows="10" cols="80" style="resize:none"></textarea>
</div>
<!-- /.form-group -->
</div>
<div class="col-md-2">
<input type="submit" name="submit" id="Add" value="Add Items" class="btn btn-success">
</div>
This is the JQuery Code to get the value of the CKEditor
$("#Add").on("click", function(e) {
e.preventDefault();
var item_description = CKEDITOR.instances["item_description"].getData();
var formData = new FormData($("#form1")[0]); //It automatically collects all fields from form
$.ajax({
url: "'.base_url().'Home/add_items",
type: "post",
data: formData,
success: function(output) {
alert('Added'):
}
});
});
And this the Home controller but when I here access the item_description
value is empty.
<?php
class Home extends MY_Controller
{
public function add_items()
{
echo $title = $this->input->post('item_description');
//$this->show('admin/add_items.php');
}
}
?>
Modify your javascript codes, like this :
$("#Add").on("click", function(e) {
e.preventDefault();
var formData = new FormData($("#form1")[0]); //It automatically collects all fields from form
formData.append('item_description', CKEDITOR.instances['item_description'].getData());
$.ajax({
url: "<?=base_url()?>Home/add_items",
type: "post",
data: formData,
success: function(output) {
alert(output);
}
});
});
How can I send input values through AJAX on button click? My code is below. Thanks in advance.
while
{
<form class="commentform">
<input type="hidden" class="proid" name="proid" value="<?=$rr['id']?>">
<input type="text" class="form-control" name="comval" placeholder="Write a comment.." autocomplete="off">
<button class="btn btn-post" type="button">Post</button>
</div>
</form>
}
$(document).ready(function() {
$(document).on('click', '.btn-post', function(){
var thePostID = $(this).val;
$.ajax({
url: 'fetch_comments.php',
data: { postID: thePostID },
type: 'POST',
success: function() {
alert(data);
}
});
Firstly, the correct method is $(this).val(), not just $(this).val.
Secondly, you can simplify your code by getting the data from the closest form element using serialize(). Try this:
$(document).on('click', '.btn-post', function() {
var $form = $(this).closest('form');
$.ajax({
url: 'fetch_comments.php',
data: $form.serialize(),
type: 'POST',
success: function() {
alert(data);
}
});
});
$("form").serialize();
Serialize a form to a query string, that could be sent to a server in an Ajax request.
I'm trying to send an input value to a php script and have the returned value posted to a div, using ajax, but I can't seem to get this right. Any help/suggestions would be appreciated. Thanks!!
This is what I have by now, but console says: "Failed to load resource: the server responded with a status of 404 (Not Found)".
test1.php:
<script>
$.ajax({
type: 'POST',
url: 'test2.php',
data: {url: $('#id1').val()},
success: function (data)
{
$(document).ready(function(){$("#content").load("test2.php");});
}
});
</script>
<form name="input">
<input type="text" id="id1">
<input type="submit">
</form>
<div id="content"></div>
test2.php:
<?php
$string=$_POST['id1'];
require_once('connect.php');
$inf = "SELECT * FROM `comments` WHERE date='$string'";
$info = mysql_query($inf);
while($info2 = mysql_fetch_object($info)) {echo $info2->username.$info2->date;}
?>
<script>
$(document).ready(function() {
$('#submit').click(function(e) {
e.preventDefault();
$.ajax({
type: 'POST',
url: 'test2.php',
data: {id1: $('#id1').val()},
success: function(data)
{
$("#content").html(data);
}
});
});
});
</script>
<form name="input">
<input type="text" id="id1">
<input type="submit" id="submit">
</form>
<div id="content"></div>
When you submit the ajax request, you're already submitting your content to test2.php, so you don't need to load it again. In the success function, you can append the result to the div from the callback.
$(document).on('click','#submit',function(e) {
e.preventDefault();
$.post('test2.php',{url: $('#id1').val()},function(data){
$("#content").html(data);
}
});
});
404 (Not Found) Error is for page not found. Please make sure that file test2.php is exist in same folder. Check url.
Also you can copy the URL from console and paste it in the browser URL to check the url correct or incorrect.
jQuery
<script>
$(document).ready(function() {
$('#submit').click(function(e) {
e.preventDefault();
$.ajax({
type: 'POST',
url: 'test2.php',
data: {id1: $('#id1').val()},
success: function(data)
{
$("#content").html(data);
}
});
});
});
</script>
HTML
<form name="input">
<input type="text" id="id1">
<input type="submit" id="submit">
</form>
You could try this:
<script>
$('#submitBtn').on('click',function(){
$.ajax({
type: 'POST',
url: 'test2.php',
data: {url: $('#id1').val()},
success: function (data)
{
$("#content").html(data);
}
});
return false;
});
</script>
<form name="input">
<input type="text" id="id1">
<input id="submitBtn" type="submit">
</form>
<div id="content"></div>
i have a problem with finding parent for form in this code:
<li class="comment<?php echo $comment[id]?>">
<div class="comment-content">
<div class="comment-top">
<div class="comment-nme">
<?php echo $comment[name]?>
</div>
<div class="comment-dt">
<?php echo $comment[dt]?>
</div>
</div>
<div class="comment">
<?php echo $comment[comment]?>
</div>
<a class="reply" href="#comment<?php echo $comment[id]?>">Ответить</a>
</div>
<div class="answer-form">
<form method="post" name="answer-form" class="ans">
<textarea class="comment-textarea" name="comment"></textarea>
<div class="a-comment-inputs">
<input type="hidden" name="parent_id" value="<?php echo $comment[id]?>">
<input type="hidden" name="status" value="new">
<div class="a-comment-name">
Имя</br>
<input type="name" name="name" class="a-comment-name">
</div>
<div class="a-comment-email" >
Eмейл</br>
<input type="email" class="a-comment-email" name="email">
</div>
</div>
<div class="comment-apply">
<button value="submit" onclick="return sendDataChild();" class="answer-but">Добавить</button>
</div>
</form>
</div>
<?php if($comment[childs]){ ?>
<ul class="commentsRoot<?php echo $comment[id]?>">
<?php echo commentsString($comment[childs]) ?>
</ul>
<?php } ?>
</li>
i use this jQuery function:
function sendDataChild() {
var form = $('FORM[name=answer-form]');
var data = form.serialize();
$.ajax({
type: "POST",
url: "req.php",
dataType: "json",
data: data,
cache: false,
success: function (data) {
form[0].reset();
},
error: function (xhr, str) {
alert('Возникла ошибка: ' + xhr.responseCode);
}
//$("#messageModalDialog").text(resultStat).show();
});
return false;
};
but it select every form that find on button click.
Can somebody advise how to solve it?
one possible solution
<button value="submit" onclick="return sendDataChild(this);" class="answer-but">Добавить</button>
then
//pass the clicked button reference then find the parent form of the button
function sendDataChild(btn) {
var form = $(btn).closest('FORM[name=answer-form]');
var data = form.serialize();
$.ajax({
type: "POST",
url: "req.php",
dataType: "json",
data: data,
cache: false,
success: function (data) {
form[0].reset();
},
error: function (xhr, str) {
alert('Возникла ошибка: ' + xhr.responseCode);
}
//$("#messageModalDialog").text(resultStat).show();
});
return false;
};
Bind submit event on the form and pass the object to the form object to your method
$(document).ready(function(){
$("form[name='answer-form']").on('submit', function(){
sendDataChild($(this));
});
});
function sendDataChild(form) {
var data = form.serialize();
$.ajax({
type: "POST",
url: "req.php",
dataType: "json",
data: data,
cache: false,
success: function (data) {
form.reset();
},
error: function (xhr, str) {
alert('Возникла ошибка: ' + xhr.responseCode);
}
//$("#messageModalDialog").text(resultStat).show();
});
return false;
};