i try to call a php function with Ajax. This is my JavaScript code in my html file:
<script type="text/javascript">
function ajax(){
$.ajax({
type:"POST",
url: "SQLCommunication.php",
dataType: "JSON",
success : function(json){
json = jQuery.parseJSON(json);
alert(json.value);
}
}
)
}
$("#btn_refresh").click(function(){
ajax();
});
</script>
I don't know if i have to specify which PHP function i actually want to call? I also don't know how i do that.
My PHP function:
header('Content-Type: application/json');
function readValue(){
$conn = establishConnection();
if($conn->connect_error){
die("Connection failed: " . $conn->connect_error);
}
$sql = "SELECT datetime, value FROM tempvalues";
$result = $conn->query($sql);
if($result->num_rows > 0){
$row = $result->fetch_assoc();
$arr["datetime"] = $row["datetime"]; //return datetime and value as array
$arr["value"] = $row["value"];
if(is_ajax()){
return json_encode($arr);
} else {
return $arr;
}
}
$conn->close();
}
So the problem is now, that nothing happens if i press the button.
I'll rewrite to my style
jQuery
<script type="text/javascript">
$("#btn_refresh").click(function(){
$.ajax({
type:"POST",
url: "SQLCommunication.php",
dataType: "JSON",
success : function(data){
console.log(data);
if(data.status === "success"){
alert("success");
}else{
alert("error");
}
}
error : function(XHR, status){
alert("fatal error");
}
})
});
</script>
PHP
header('Content-Type: application/json');
function readValue(){
$conn = establishConnection();
if($conn->connect_error){
die("Connection failed: " . $conn->connect_error);
}
$sql = "SELECT datetime, value FROM tempvalues";
$result = $conn->query($sql);
if($result->num_rows > 0){
$row = $result->fetch_assoc();
$arr["datetime"] = $row["datetime"]; //return datetime and value as array
$arr["value"] = $row["value"];
$arr["status"] = "success";
}else{
$arr["status"] = "error";
}
return json_encode($arr);
$conn->close();
}
echo readValue();
Untested
Updated
functions.php
function readValue(){
$conn = establishConnection();
if($conn->connect_error){
die("Connection failed: " . $conn->connect_error);
}
$sql = "SELECT datetime, value FROM tempvalues";
$result = $conn->query($sql);
if($result->num_rows > 0){
$row = $result->fetch_assoc();
$arr["datetime"] = $row["datetime"]; //return datetime and value as array
$arr["value"] = $row["value"];
$arr["status"] = "success";
}else{
$arr["status"] = "error";
}
return json_encode($arr);
$conn->close();
}
function writeValue(){
...
}
SQLCommunication.php
header('Content-Type: application/json');
if(!isset($_GET['func']) && empty($_GET['func'])){
//make the file inaccessible without $_GET
$arr['status'] = "error";
echo json_encode($arr);
exit();
)
if($_GET['func'] === "readvalue"){
echo readValue();
}elseif($_GET['func'] === "writevalue"){
echo writeValue();
}elseif($_GET['func'] === "whatever"){
//whatever...
}
....
jQuery
$("#btn_refresh").click(function(){
$.ajax({
type:"POST",
url: "SQLCommunication.php?func=readvalue", //SQLCommunication.php?func=writevalue
dataType: "JSON",
success : function(data){
console.log(data);
if(data.status === "success"){
alert("success");
}else{
alert("error");
}
}
error : function(XHR, status){
alert("fatal error");
}
})
});
If you want to see the result in your ajax response, you have to use echo(), or any other printing method in your controller instead of return
Related
I have the following code:
<?php
session_start();
?>
<html>
<head>
<title>Dashboard</title>
<script src="//ajax.googleapis.com/ajax/libs/jquery/1.8.3/jquery.min.js"></script>
</head>
<body>
<button id="openjob">View open job requests</button>
<button id="jobtoday">View all job requests today</button>
<div id="responsecontainer"></div>
<script type="text/javascript">
$('#openjob').click(function() {
<?php
$_SESSION["flag"] = 0;
?>
$.ajax({
type: "GET",
url: "cssdashsubmit.php",
dataType: "html", //expect html to be returned
success: function(response){
$("#responsecontainer").html(response);
}
});
});
$('#jobtoday').click(function() {
<?php
$_SESSION['flag'] = 1;
?>
$.ajax({
type: "GET",
url: "cssdashsubmit.php",
dataType: "html", //expect html to be returned
success: function(response){
$("#responsecontainer").html(response);
}
});
});
</script>
</body>
</html>
cssdashsubmit.php includes
session_start();
if (mysqli_connect_errno()) {
printf("Connect failed: %s\n", mysqli_connect_error());
exit();
}
echo $_SESSION['flag'];
if (isset($_SESSION['flag']) && $_SESSION["flag"] === 0) {
$sql = "SELECT * FROM Ticket WHERE ticket_close_open = 'open'";
$result = $link->query($sql);
if ($result->num_rows > 0) {
while($row = $result->fetch_assoc()){
echo $row['ticket_id'];
echo $row['ticket_equipment'];
}
}
unset($_SESSION['flag']);
}
if (isset($_SESSION['flag']) && $_SESSION["flag"] === 1) {
$sql = "SELECT * FROM Ticket WHERE DATE(ticket_open_datetime) = date('Ymd')";
$result = $link->query($sql);
if ($result->num_rows > 0) {
while($row = $result->fetch_assoc()){
echo $row['ticket_id'];
echo $row['ticket_equipment'];
}
}
unset($_SESSION['flag']);
}
?>
Now when I click on the buttons, it always echoes 3, irrespective of which button I click. I've tried changing the session variable name, but it still persists. Can anybody point where I am erroring?
Instead of session - use simple url parameter:
$('#openjob').click(function() {
$.ajax({
type: "GET",
url: "cssdashsubmit.php?type=jobs",
dataType: "html", //expect html to be returned
success: function(response){
$("#responsecontainer").html(response);
}
});
});
$('#jobtoday').click(function() {
$.ajax({
type: "GET",
url: "cssdashsubmit.php?type=requests",
dataType: "html", //expect html to be returned
success: function(response){
$("#responsecontainer").html(response);
}
});
});
On server side code can be:
session_start();
if (mysqli_connect_errno()) {
printf("Connect failed: %s\n", mysqli_connect_error());
exit();
}
switch ($_GET['type']) {
case "jobs":
$sql = "SELECT * FROM Ticket WHERE ticket_close_open = 'open'";
break;
case "requests":
$sql = "SELECT * FROM Ticket WHERE DATE(ticket_open_datetime) = date('Ymd')";
break;
}
$result = $link->query($sql);
if ($result->num_rows > 0) {
while($row = $result->fetch_assoc()){
echo $row['ticket_id'];
echo $row['ticket_equipment'];
}
}
I am trying to insert data using AJAX JSON but it's not working. I tried without JSON and it works, but an alert box shows with some HTML code.
HTML:
Short Break
AJAX:
$(document).ready(function() {
$('#sbreak').on('click', function() {
var name = $("SBreak").val();
$.ajax({
type: "POST",
dataType: 'json',
url: "brkrequest.php",
data: {
sname: name
}
cache: false,
success: function(server_response) {
if (server_response.status == '1') //if ajax_check_username.php return value "0"
{
alert("Inserted ");
} else if (server_response == '0') //if it returns "1"
{
alert("Already Inserted");
}
},
});
return false;
});
});
PHP: :
session_start();
date_default_timezone_set('Asia/Kolkata');
$sname=$_POST['sname'];
$sname= $_SESSION['myusername'];
$reqdate = date("Y-m-d H:i:s");
include("connection.php");
//Insert query
$query = sprintf("SELECT * FROM `breakqueue` WHERE (`sname` ='$sname')");
$result = mysql_query($query);
if(mysql_num_rows($result) > 0){
$data['status']= '1';//If there is a record match Already Inserted
}
else { // if there is no matching rows do following
$query = mysql_query("INSERT INTO `breakqueue`(`id`, `sname`, `btype`, `reqdate`, `apdate`, `status`) VALUES ('','$sname','Sbreak','$reqdate','','Pending')");
$data['status']= '0';//Record Insered
}
echo json_encode($data);
}
use it in php
header('Content-Type:application/json');
and write
success: function(server_response){
console.log(typeof server_response);
...
for finding response type,
if type of server_response isn't object
use it for convert it to object :
server_response = JSON.parse(server_response);
php Code:
session_start();
//Here added...
header('Content-Type:application/json');
date_default_timezone_set('Asia/Kolkata');
$sname=$_POST['sname'];
$sname= $_SESSION['myusername'];
$reqdate = date("Y-m-d H:i:s");
include("connection.php");
//Insert query
$query = sprintf("SELECT * FROM `breakqueue` WHERE (`sname` ='$sname')");
$result = mysql_query($query);
if(mysql_num_rows($result) > 0){
$data['status']= '1';//If there is a record match Already Inserted
}
else{ // if there is no matching rows do following
$query = mysql_query("INSERT INTO `breakqueue`(`id`, `sname`, `btype`, `reqdate`, `apdate`, `status`) VALUES ('','$sname','Sbreak','$reqdate','','Pending')");
$data['status']= '0';//Record Insered
}
echo json_encode($data);
}
Javascript Code:
$(document).ready(function()
{
$('#sbreak').on('click', function(){
var name = $("SBreak").val();
$.ajax({
type: "POST",
dataType:'json',
url: "brkrequest.php",
data: {sname: name}
cache: false,
success: function(server_response){
//TODO:REMOVE IT After seeing. alert or console.log for seeing type
alert(typeof server_response);
if(typeof server_response){
server_response = JSON.parse(server_response);
}
if(server_response.status == '1')//if ajax_check_username.php return value "0"
{
alert("Inserted ");
}
else if(server_response == '0')//if it returns "1"
{
alert("Already Inserted");
}
},
});
return false;
I want to POST data from form. It works fine.
In the other functionality i want to get data from database.
I don't know where is mistake. I suspect that AJAX call is fine.
My PHP code:
<?php
$uuid = $_POST['uuid'];
$minor = $_POST['minor'];
$mayor = $_POST['mayor'];
$lokalizacja = $_POST['lokalizacja'];
$servername = "";
$username = "";
$password = "";
$dbname = "";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
} else{
echo "Polaczono";
}
$sql = "INSERT INTO beacons (uuid, major, minor, lokalizacja)
VALUES ('$uuid', '$minor', '$mayor', '$lokalizacja')";
if ($conn->query($sql) === TRUE) {
echo "Dane dodano prawidłowo";
} else {
echo "Error: " . $sql . "<br>" . $conn->error;
}
$sqlget = "SELECT uuid, major, minor, lokalizacja FROM beacons";
$result = $conn->query($sqlget);
if ($result->num_rows > 0) {
// output data of each row
while($row = $result->fetch_assoc()) {
echo json_encode(array("value" => "UUID: " . $row["uuid"]));
}
} else {
echo "Brak rekordów w bazie";
}
$conn->close();
?>
AJAX call:
$('#admin').submit(function(e){
e.preventDefault();
if( ($("input[name=uuid]").val().length) > 40 || ($("input[name=minor]").val().length) > 5 || ($("input[name=mayor]").val().length) > 5 || ($("input[name=lokalizacja]").val().length) > 20){
$(".error-pola").show();
} else{
$.post('administrator-connect.php', $(this).serialize() )
.done(function(){
$(".success-wyslanie").show();
})
.fail(function(){
$(".error-wyslanie").show();
});
}
});
$(document).ready(function() {
$.ajax({
type: "GET",
url: 'administrator-connect.php',
dataType: 'json',
success: function(data)
{
alert("fsdfsd"+ data);
},
error: function(){
alert("not");
}
});
});
I am using:
echo json_encode(array("UUID" => $row["uuid"]));
and in ajax:
var jqxhr = $.get( "administrator-get.php", function(data) {
var jsonx = JSON.parse(JSON.stringify(data));
$( "#data-listing" ).html(jsonx);
});
But I get response:
{"UUID":"B9407F30-F5F8-466E-AFF9-25556B57FE6D"}
How to get only string ?
If you write this
dataType: 'json',
It expect for JSON value not string be sure to return only JSON.
You returns string value not JSON.
With like this code
echo "Polaczono";
Any echo would be the return value for ajax
At last you should return only one value like this.
echo json_encode($result);//an array result
You can check by string return. By removing dataType
I can read Qrcode and what i want is to check if the text in qrcode is in remote database. I have a php file where I do some process to check if database is in mysql. But it does not work. below my code
/*part of js file
scan: function() {
console.log('scanning');
var scanner = cordova.require("cordova/plugin/BarcodeScanner");
scanner.scan( function (result) {
var rs= result;
$.ajax({
type: 'POST',
data: rs,
url: 'http://url/page.php',
success: function(data){
console.log(data);
document.getElementById("info").innerHTML = data;
},
error: function(){
console.log(data);
alert('error');
}
});
return false;
}, function (error) {
console.log("Scanning failed: ", error);
} );
}
/* My php file
<?php
// Create connection
$conn = mysql_connect($servername, $username, $password);
mysql_select_db("database", $conn);
$result=$_POST['result'] ; //value from qrcode scanned by device
$sql="SELECT * FROM tabe WHERE code = '$result' ";
$rs = mysql_query($sql,$conn);
$count=mysql_num_rows($rs);
if($count == 1) {
echo "ok";
}
else
{
return "No Ok";
}
?>
Trying to pass data to the server but it keeps returning a "Parameter Missing"
So either the data is not being passed to the PHP script or I am doing something wrong.
Here is the jQuery:
function quickJob(obj) {
var quickJobNumber = $(obj).text();
//alert(quickJobNumber)
$.ajax({
type: "GET",
url: "quickJobCB.php",
data: quickJobNumber,
success: function(server_response)
{
$("#message").removeClass().html(server_response);
}
});
}
Ok....when tracing the issue I created an alert as seen below. The alert is producing the expected results.
Here is the PHP script:
<?php
require_once("models/config.php");
// Make the connection:
$dbc = #mysqli_connect($db_host, $db_user, $db_pass, $db_name);
if (!$dbc) {
trigger_error('Could not connect to MySQL: ' . mysqli_connect_error());
}
if (isset($_GET['quickJobNumber'])) {
$quickJobNumber = trim($_GET['quickJobNumber']);
$quickJobNumber = mysqli_real_escape_string($dbc, $quickJobNumber);
$query = "SELECT * FROM projects WHERE projectNumber = '" . $quickJobNumber . "'";
$result = mysqli_query($dbc, $query);
if ($result) {
if (mysqli_affected_rows($dbc) != 0) {
while ($row = mysqli_fetch_array($result, MYSQLI_ASSOC)) {
echo $row['projectName'];
}
} else {
echo 'No Results for :"' . $_GET['quickJobNumber'] . '"';
}
}
} else {
echo 'Parameter Missing';
}
?>
<?php include("models/clean_up.php"); ?>
data: quickJobNumber,
should be
data: { 'quickJobNumber': quickJobNumber },
You'll need to pass the data either as a query string like so
data: "quickJobNumber="+quickJobNumber,
or a map like so
data: data { quickJobNumber: quickJobNumber },
If you want to use the GET request, use $.get
$.get("/get_request.php", { quickJobNumber: "myAjaxTestMessage"},
function(data){
console.log("WOW! Server was answer: " + data);
});
In php
<?php
if(isset($_GET['quickJobNumber'])){
header('Content-Type: application/json; charset=utf-8');
echo json_encode(array('answer'=>'Hello user!'));
}
?>
If you want to use the POST request, use $.post
$.post("/post_request.php", { quickJobNumber: "myAjaxTestMessage"},
function(data){
console.log("WOW! Server was answer: " + data);
});
In php
<?php
if(isset($_POST['quickJobNumber'])){
header('Content-Type: application/json; charset=utf-8');
echo json_encode(array('answer'=>'Hello user!'));
}
?>
P.S. or you can use $_REQUEST in php.