I'm just wondering is it possible to have a csv file (with many values) and scan the file for a specific value with php?
Ideally if this is possible, Id also like to get the index of that value in the file (i.e what row number the value falls on).
I'm quiet new to php so I'm not sure where to start.
All help is greatly appreciated.
Sure,
Not tested:
<?php
$search = 'mysearchstring';
$row = 1;
if (($handle = fopen("test.csv", "r")) !== FALSE)
{
while (($data = fgetcsv($handle, 1000, ",")) !== FALSE)
{
$num = count($data);
$row++;
for ($c=0; $c < $num; $c++)
{
if ($data[$c] == $search)
{
echo "Found in row $row in column {$c+1} <br />\n";
}
}
}
fclose($handle);
}
?>
Related
Pretty new to PHP. I have a csv feed that i am trying to display every line of in the right place. The feed is loaded into a multidimentional array and I can echo out specific places like this.
echo $readcsv[0][2]
But I am trying to use the value of the variable $row in stead of the first number while doing a while loop.
Something like:
echo $readcsv[$row][2]
I have tried next(), str_replace() and strtr() but none of them seems to work while the loop is running.
$row = 1;
$readcsv = array();
if (($handle = fopen("file.csv", "r")) !== FALSE) {
while (($data = fgetcsv($handle, 1000, ";")) !== FALSE) {
$num = count($data);
echo $readcsv[$row][2];
$row++;
for ($c=0; $c < $num; $c++) {
}
$mycsvfile[] = $data;
}
fclose($handle);
}
CSV file:
title;image_link;link;empty;price;
1;back.gif;http://link.com;;19.95;
2;back.gif;http://link.com;;19.95;
3;back.gif;http://link.com;;19.95;
4;back.gif;http://link.com;;19.95;
5;back.gif;http://link.com;;19.95;
I am not quite sure from your code and question exactly what you are trying to do, but maybe its something like this
if (($handle = fopen("file.csv", "r")) !== FALSE) {
while (($data = fgetcsv($handle, 1000, ";")) !== FALSE) {
// you load the line into $data and its a one dimentional array
// occurance 2 is the `link` (http://link.com) if that what you want to echo
echo $data[2];
// as you have a loop, maybe you were trying to
// echo each fields from the csv so you can do that like this
foreach ($data as $idx => $value) {
echo "Column $idx = $value";
}
$mycsvfile[] = $data;
}
fclose($handle);
}
I have .csv file with 9k rows. When I use script from php manual :
<?php
$row = 1;
if (($handle = fopen("test.csv", "r")) !== FALSE) {
while (($data = fgetcsv($handle, 1000, ";")) !== FALSE) {
$num = count($data);
echo "<p> $num fields in line $row: <br /></p>\n";
$row++;
for ($c=0; $c < $num; $c++) {
echo $data[$c] . "<br />\n";
}
}
fclose($handle);
}
?>
I got on my output everysingle cell from the csv file.
Problem occurs when I want to treat every row as record create object from it and store it into database. I have modified it like:
if (($handle = fopen("test.csv", "r")) !== FALSE) {
while (($data = fgetcsv($handle, 1000, ";")) !== FALSE) {
$num = count($data);
$record= new Record($db);
echo "<p> $num fields in line $row: <br /></p>\n";
$row++;
for ($c=0; $c < $num; $c++) {
$record->$attributes[$c] = utf8_encode($data[$c]);
}
$record->Store();
}
fclose($handle);
}
In this case only about 2k records are store into mine PostgreSQL database, but no exception or error is shown. I have no idea why my loop stops. Everytime i run the script it loads into mine database different amount of records between 1,6k and 2,1k.
I have no limits set on my PostgreSQL (At least i don't knew of any..)
Can anyone explain me what am I doing wrong?
Two Things here I will change
A. change the !== FALSE) to !=false), don't ask me why , it sometimes work
B. do NOT NEW you record instance in the loop without unset it , you are creating 2000 new instance so that may be the reason.
You could try the copy statement. I belive it is similar to MySql LOAD DATA IN FILE
http://www.postgresql.org/docs/current/static/sql-copy.html
If it's just the data you need to add, it would be considerably faster that any other method.
the csv data as the following:
(first line) price url
(second line) $10 src="http://www.test.com/1455/"||src="http://www.test.com/image/1456/"||
(third line) $20 src="http://www.test.com/2260/"||src="http://www.test.com/2261/"||
.... ........
now i want to put all the data from the url column into a text file. and shows the data one by one. namely:
http://www.test.com/1455/
http://www.test.com/image/1456/
http://www.test.com/2260/
http://www.test.com/2261/
....
now,i am stucked.
a, i don't know how to prevent outputting the first line.
b,i don't know how to get the url, and put them i a text file one by one.
first i using the following code to output the data to the screen.
$row = 1;
if (($handle = fopen("test.csv", "r")) !== FALSE) {
while (($data = fgetcsv($handle, 1000, ",")) !== FALSE) {
$num = count($data);
$row++;
echo $data[1] . "<br />\n";
}
fclose($handle);
}
the above code also output the first line (url). i don't want to output it. how should i do.
thank you.
You're very close! I have modified your code just slightly to do what you're trying to do. Essentially you need a second file handler for the output. You can open that as append mode so that write append to the end of the file. As for not echoing the header, you just make sure that row is greater than the first row. Hope it helps!
$row = 1;
if (($handle = fopen("test.csv", "r")) !== FALSE && ($handle2 = fopen("output.txt", 'a')) !== FALSE) {
while (($data = fgetcsv($handle, 1000, ",")) !== FALSE) {
if($row > 1) {
fwrite($handle2, "{$data[1]}\n");
}
$row++;
}
fclose($handle);
fclose($handle2);
}
// Skips the first line of the CSV - outputting the second "column" of data.
$row = 0;
if (($handle = fopen("test.csv", "r")) !== FALSE) {
while (($data = fgetcsv($handle, 1000, ",")) !== FALSE) {
$num = count($data);
if ($row > 0 ) {
echo $data[1] . "<br />\n";
}
$row++;
}
fclose($handle);
}
In tried importing a csv into a table using phpMyAdmin and I'm getting permission errors so I'm looking for any php scripts available around that I can use.
What scripts are available? Can ane point to any free one's?
fgetcsv is the php function you should use.
For details see here.
Sample code here..
$row = 1;
if (($handle = fopen("test.csv", "r")) !== FALSE) {
while (($data = fgetcsv($handle, 1000, ",")) !== FALSE) {
$num = count($data);
echo "<p> $num fields in line $row: <br /></p>\n";
$row++;
for ($c=0; $c < $num; $c++) {
// write insert query here
echo $data[$c] . "<br />\n";
}
}
fclose($handle);
}
Thanks.
I want to display the contents of a CSV file by assigning it to a variable and then display it using echo statement.
This code is not working could someone point the error in it
$fh = fopen('db.csv', 'r');
$now = time();
$data=fgetcsv($fh);
$data[0]=$name;
echo $name;
Am a newbie to coding and scripting.
Thanks
This is the CSV line that I want to be printed
katz,26-11-2011,http//www.google.com
Why you first valorize the $data with an array of your CSV and then you overwrite the first position with the $name variable (which apparently is null)?
$data[0] = $name;
should be
$name = $data[0];
You could use the handy fgetcvs function for this.
Might as well post an example for want of a complete answer, shamelessly ripped from that same
manpage:
<?php
$row = 1;
if (($handle = fopen("test.csv", "r")) !== FALSE) {
while (($data = fgetcsv($handle, 1000, ",")) !== FALSE) {
$num = count($data);
echo "<p> $num fields in line $row: <br /></p>\n";
$row++;
for ($c=0; $c < $num; $c++) {
echo $data[$c] . "<br />\n";
}
}
fclose($handle);
}
?>
Hope that fits your needs. Happy coding.