The table have 11 rows
Query
SELECT COUNT(*) FROM `zars_all` ORDER BY id DESC LIMIT 9,9
Result
Zero Rows, even there are two rows having id 10 and 11
Query
SELECT * FROM `zars_all` ORDER BY id DESC LIMIT 9,9
Result
Two Rows having id 10 and 11
I have tried using column names as value in Count but it does't help. Any help is appreciated and please tell me if I am doing anything wrong here.
Your first sentence SELECT COUNT(*) returns an integer.
That means that the trailing LIMIT 9,9 is setting a minimum of 9 elements and a maximum of 9 elements.
Let’s examine the LIMIT offset, count clause parameters:
The offset specifies the offset of the first row to return.
The count specifies the maximum number of rows to return.
Your offset is out of bounds, that is why you get no rows.
Please remove that and leave it like:
SELECT COUNT(*) FROM `zars_all` ORDER BY id DESC
Waqas,
LIMIT cannot be applied directly along with COUNT instead change your query like
SELECT count(*) FROM (select * from zars_all limit 9,9) as a"**;
Related
I'm listing products from my database where I select the latest product as a big feature. The rest are sorted by latest product.
So I have two querys which looks like this.
SELECT * FROM products ORDER BY product_id DESC LIMIT 1
and
SELECT * FROM products ORDER BY product_id DESC LIMIT 4
However... This makes the latest product appear twice in my current layout. (The feature).
How do I tell the second query to skip the latest entry?
We can specify the LIMIT clause to start at second row instead, and then fetch next 4 rows.
SELECT * FROM products ORDER BY product_id DESC LIMIT 1,4
Syntax is:
[LIMIT {[offset,] row_count | row_count OFFSET offset}]
The LIMIT clause can be used to constrain the number of rows returned
by the SELECT statement. LIMIT takes one or two numeric arguments,
which must both be nonnegative integer constants With two arguments,
the first argument specifies the offset of the first row to return,
and the second specifies the maximum number of rows to return.
The offset of the initial row is 0 (not 1):
So, I'm writing an application to fetch records from the database, and my client has asked if I could sort the data by area. I've got the following query:
SELECT
*
FROM
customers
WHERE
account_type != 'x'
AND
account_type != 'tor'
ORDER BY
area ASC,
id ASC
LIMIT 30
The query returns 30 rows worth of data, all with an area value of 1.
I've got an AJAX query set up to fetch another 30 rows, however as I am ordering the data by area, I am unable to just fit a simple range string to my query as shown in the example below:
...
AND
id > 30
...
How would I write a query that would collect the next 30 records from the database?
Also, there is a record with an area value of 0. This is not shown as the first record in the list. Why is this? And how can I fix this?
Thanks
First, combine the where conditions into a single not in:
SELECT c.*
FROM customers c
WHERE account_type NOT IN ('x', 'tor')
ORDER BY area ASC, id ASC
LIMIT 30;
Then, for the next set, use:
SELECT . . .
OFFSET 30
LIMIT 30
This assumes that id is unique in the table. That is important, because that makes the sort stable.
Have a look at the the SELECT query documentation:
https://dev.mysql.com/doc/refman/5.7/en/select.html
[LIMIT {[offset,] row_count | row_count OFFSET offset}]
In summary, just limit returns you x records. With the offset you can set a starting position, basically allows you for paging.
MySQL LIMIT take an optional parameter offset, so you could send in a parameter telling where to start when picking the 30 results you want
SELECT
*
FROM
customers
WHERE
account_type != 'x'
AND
account_type != 'tor'
ORDER BY
area ASC,
id ASC
LIMIT 30, 30
Should give you the next 30 rows starting from row 30
I am trying to create a SQL call that first order all the rows by date and returns all the rows starting from the number 25.
So far I have
"SELECT * FROM 'users' ORDER BY 'table'.'regdate' OFFSET 24"
But this is not working .. How can I do this ?
try like this:
first get count all data in table like this:
$count=select count(*) from users
then
SELECT * FROM 'users' ORDER BY 'table'.'regdate' limit 25,$count
There is nothing wrong with your query, the problem must be elsewhere.
Your query includes an offset which omits the first 24 results. This imposes no limits and should therefore return evrey row pat the 24 oldest dates. To omit the new dates instead you have to set your order as DESC
SELECT * FROM 'users' ORDER BY 'table'.'regdate' OFFSET 24
To do that and limit results to 100 records simply do this:
SELECT * FROM my_table ORDER BY date_field DESC OFFSET 24 LIMIT 100
I'm wondering how I can sort an sql column by frequency, and then pick which row I want. I already know that you need to use:
SELECT `column`
FROM `your_table`
GROUP BY `column`
ORDER BY COUNT(*) DESC
LIMIT 1;
To sort from most frequent to least frequent. But how would I select the 1st, 2nd, or 3rd most occurring with using the least amount of different SQL? Could I use PHP?
Is there something akin to:
MAX(VAL)-2
or something close to this, for the 3rd most frequent?
Thanks!
You would use the limit clause. For instance:
limit 1 offset 0
would get the first.
limit 1 offset 2
would get the third.
(offset starts counting at 0 rather than 1.)
What I need to do is (using PHP) select the latest 10 rows from a table except the first (which has the highest ID). How is this done?
Try something like this:
SELECT * FROM `table`
ORDER BY `id` DESC
LIMIT 1,10
http://dev.mysql.com/doc/refman/5.0/en/select.html
The LIMIT clause can be used to constrain the number of rows returned
by the SELECT statement. LIMIT takes one or two numeric arguments,
which must both be nonnegative integer constants (except when using
prepared statements).
With two arguments, the first argument specifies the offset of the
first row to return, and the second specifies the maximum number of
rows to return. The offset of the initial row is 0 (not 1):
SELECT * FROM `table` ORDER BY id DESC LIMIT 1, 10
1 is the offset and 10 is the limit of records it's going to return!