I have a table in Database PhpMyAdmin with certain values, and I want to UPDATE only ONE value of these, WHERE the latest initial_date (TIMESTAMP) is.
I write down here the code I generated as an example, so you can see I actually obtain that date value through SELECT, but I don't manage to UPDATE it. Thank you very much.
$select = "SELECT MAX(initial_date) AS max_value FROM services WHERE matricula = '" . $_POST["taxi"] . "'";
$select_results = mysqli_query($conexion, $select);
while($row = mysqli_fetch_array($select_results)){
echo $row['max_value'];
$update_carrera = "UPDATE services SET";
$update_carrera .= " costo_carrera = costo_carrera + " . $_POST["costo_carrera"] . ",";
$update_carrera .= " final_date = CURRENT_TIMESTAMP";
$update_carrera .= " WHERE initial_date = ''";
$update_carrera_results = mysqli_query($conexion, $update_carrera);
}
I leave WHERE initial_date = '' empty so you can tell what should it be. I get a correct date value in the echo $row['max_value']; if I solve the WHERE with a WHERE initial_date = '20160405153315' (INTEGER), but I don't want to put myself the integer, of course I want to get the newest date from the table database.
Related
I would like to start from an example: you received some list with needed fields. This list may vary and even if it is empty, select all fields. This list can include fields from several tables. Is there any way to generate SELECT query for doing this?
Probably there is a way, but it will look like parsing received list, adding appropriate table alias, and then adding modified list into select clause. Is it best way actually?
Update 1
The goal is only to get passed fields from several tables, not to
control result from any of them(its about first answer)
You could create a query that first selects dynamically fields, depending on your criteria.
for example lets assume you have two criteria passed to you. Then (after you have made sure your criteria1 and criteria2 are safe):
$mySelect = ''; //placeholder so that you can add select fields
$extraTables = ''; //placeholder to put the extra tables I may need
$criteria = " WHERE 1 "; //this will select everything
if ($criteria1>'') {
$mySelect .= ' , t3.field3 ';
$extraTables = " , aDifferentTable AS t3";
$criteria .= " AND t3.someKey = t1.someKey '";
$criteria .= " AND field_crit1 = '" . $criteria1 . "'";
}
//and an example of connecting dynamically to an other table
if ($criteria2>'') {
$mySelect .= ' , t2.field5 ';
$extraTables = " , anOtherTable AS t2";
$criteria .= " AND t2.someKey = t1.someKey '";
$criteria .= " AND t2.field_crit2 = '" . $criteria2 . "'";
}
//lets combine all together into one dynamically created query
$myquery = "SELECT t1.something " . $mySelect . " FROM myTable AS t1";
$myquery = $myqury . $extraTables . $criteria;
Below is my small code for inserting some info into AthleteID. It doesn't actually insert the information to the table though, any help is appreciated. (sorry for asking twice, but I think my first question isn't addressing whatever issue is holding me up here!)
<?php
require_once('resources/connection.php');
echo 'hello noob' . '<br />';
$query = mysql_query('SELECT LName, MyWebSiteUserID FROM tuser WHERE MyWebSiteUserID = MyWebSiteUserID');
$athleteId = strtoupper(substr($row["LName"], 0, 2)) . $row["MyWebSiteUserID"];
$update = "UPDATE `tuser` SET `AthleteID`='$athleteId' WHERE `MyWebSiteUserID` = `MyWebSiteUserID`;";
while($row = mysql_fetch_array($query)){
mysql_query( $update);
}
Where to begin..
1) Your using mysql and not mysqli. mysql is now deprecated but you could be on a PHP 4 system so keep that in mind.
2) You are building the $athleteID before you have found out what LName and SkillshowUserID is.
3) Your using a where of 1 = 1. You dont need this as it will return true for every row.
4) So...
// Execute a query
$results = mysql_query('SELECT LName, MyWebsiteID FROM tuser WHERE SkillshowUserID = SkillshowUserID');
// Loop through the result set
while($row = mysql_fetch_array($query))
{
// Generate the athleteId
$athleteId = strtoupper(substr($row["LName"], 0, 2)) . $row["MyWebsiteID"];
// Generate an sql update statement
$update = "UPDATE `tuser` SET `AthleteID`='" . $athleteId . "' " .
" WHERE LName = '" . $row['LName'] . "' " .
" AND MyWebsiteID = '" . $row['MyWebsiteID'] . "';";
// Fire off that bad boy
mysql_query($update);
}
I'm guessing that I'm just a little rusty or something because it seems like this should be working. Am I missing something here...
Here is the code I am trying to use...
<?php
echo dbConn();
$existing_time = mysql_result(mysql_query("SELECT p_time FROM scores WHERE p_uid=$uid"), 0);
$existing_category = mysql_result(mysql_query("SELECT p_cat FROM scores WHERE p_uid=$uid AND p_cat=$pieces"), 0);
if ($existing_category == "") {
mysql_query(
"INSERT INTO scores VALUES (
'',
'$uid',
'$pusername',
'$time',
'$pieces'
)");
} elseif ($existing_time <= $time) {
echo "No Change! Old Score Was Better (Lower)";
} elseif ($existing_time > $time) {
mysql_query("UPDATE scores SET p_time = " . $time . " WHERE p_uid = " . $uid . " AND p_cat = " . $pieces . "");
};
?>
Now... Here is what I am trying to do...
I am collecting info from the database where the users username AND category match. If the category for that user does not exist, it inserts the latest score. (This much works.)
Then, if the category does exist but the old score is better, it just does nothing. (This part works too)...
However, what I can't seem to do is get it to update the last score, if the current score is better (lower score, since this is a time based game.) It doesn't update the score.
I am trying it this way: By updating a row in "scores" where the USERNAME and the CATEGORY match at the same time.
Please note... where it says "pieces". this is a category. Where it says "time", this is a score. The score is returned as 00:00:00 for hours minutes and seconds.
EXAMPLE: (in parentheses is the database row name)
id (ID) = just KEY id in sequencial order
user id (p_uid) = 123456789
username (p_username) = somename
score (p_time) = 00:01:03
category (p_cat) = 10
Change you update statement to:
mysql_query("UPDATE scores SET p_time = '" . $time . "' WHERE p_uid = " . $uid . " AND p_cat = " . $pieces . "");
You have missed quotes in the update statement around $time.
I have a database of records that have a timestamp asscoiated with them. I would like to pull records from the database grouped by day, so if there are other records with the same date (24 hour span) I would like them to be grouped together. Can this be done with MYSQL or will I have to pull the records and organise them into arrays using PHP?
Here is a screenshot of my table:
Here is my model function so far:
public function getUsersMoves($options) {
$query = "SELECT * FROM myzone_user_hr_records";
if(isset($options['GUID'])) {
$query .= " WHERE GUID = '" . $options['GUID'] . "'";
}
if((isset($options['minHR'])) && isset($options['maxHR'])) {
$query .= " AND (hr BETWEEN '" . (int)$options['minHR'] . "' AND '" . (int)$options['maxHR'] . "')";
} else if (isset($options['zone'])) {
$query .= " AND zone = '" . (int)$options['zone'] . "'";
}
if(isset($options['activity'])) {
$query .= " AND title = '" . $options['activity'] . "'";
}
$query .= " ORDER BY time DESC";
$query = $this->db->query($query);
return $query->result_array();
}
And my controller code:
$moves = $this->myzone_model->getUsersMoves($options);
I want the data sorted so that these records are grouped together if they have the same date in the timestamp, for example (2012-11-20).
Thanks
try this :
SELECT *, DATE(time) AS date FROM [whatever you want] GROUP BY date
select * from TABLE where `time` like '2012-11-20%'
The option I have suggested works because the LIKE condition in the WHERE selects all dates from the time field that start with 2012-11-20. That means that it doesn't matter what time it is during the day, it will return all results for that day.
To make this work, you must remember to use LIKE and then add the wildcard at the end - %. You can also add the wildcard at the beginning if you wanted. An example to return all days (11th December) for multiple years would be:
SELECT * FROM TABLE WHERE `time` like '%-12-11%'
I'm trying to update a range of dates with a Shift_ID but the Shift_ID that is entered depends upon what day of the week it is. So, for example, if I have a range of dates $from = "2012-12-01" $to = "2012-12-28" I'm trying to make it so that I can select a check box (for example: value="Fri" name = "offdays[]") to indicate what day is an offdays. If an offdays is matched with a day in the set range, then the Shift_ID = "6" otherwise it is a work day and Shift_ID = "3"
Hopefully this will all make sense in a minute, I'm doing my best to explain it as well as give you some useful variables.
So here is my code:
if(isset($_POST['submit']))
{
if(isset($_POST['offdays']))
{
//$off is set through the config settings//
$shift = mysqli_real_escape_string($_POST['shift']);
$from = mysqli_real_escape_string($_POST['from']);
$to = mysqli_real_escape_string($_POST['to']);
$emp_id = mysqli_real_escape_string($_POST['emp_id']);
foreach($_POST['offdays'] as $checkbox)
{
echo "Checkbox: " . $checkbox . "<br>";//error checking
$sql = ("SELECT Date FROM schedule WHERE (Date BETWEEN '$from' AND '$to') AND (Emp_ID = '$emp_id')");
if(!$result_date_query = $mysqli->query($sql))
{
echo "INSERT ERROR 1 HERE";
}
echo "SELECT SQL: " . $sql . "<br>";//error checking
while($row = $result_date_query->fetch_assoc())
{
echo "Date: " . $row['Date'] . "<br>";//error checking
$date = date('D',strtotime($row['Date']));
if($date == $checkbox)
{
echo "MATCHED! Date: " . $date . " Checkbox: " . $checkbox . "<br>";//error checking
$sql = ("UPDATE schedule SET Shift_ID = '$off' WHERE Date = '" . $row['Date'] . "' AND Emp_ID = '$emp_id'");
if(!$result_update_offdays_query = $mysqli->query($sql))
{
echo "INSERT ERROR 2 HERE";
}
echo "UPDATE DAYS OFF SQL: " . $sql . "<br><br>";//error checking
}
else
{
echo "NOT MATCHED! Date: " . $date . " Checkbox: " . $checkbox . "<br>";//error checking
$sql = ("UPDATE schedule SET Shift_ID = '$shift' WHERE Date = '" . $row['Date'] . "' AND Emp_ID = '$emp_id'");
if(!$result_update_shift_query = $mysqli->query($sql))
{
echo "INSERT ERROR 3 HERE";
}
echo "UPDATE SHIFT SQL: " . $sql . "<br><br>";//error checking
}
}
}
}
}
When I look at my printed echo statements, everything is perfect! When a date lands on a Friday, it shows that it's entering Shift_ID = "6" and any other day shows Shift_ID = "3". The problem is the tables don't reflect what my statements are telling me, they all just get updated to Shift_ID = "3".
In the end I want to be able to select more than one offdays, but when I select more than one, it overwrites my previous day during the next loop, which makes sense.
I've got no idea what is going on, if anyone can give me a clue, I would really appreciate it.
UPDATE: When I add exit; after the days off update, like this:
echo "UPDATE DAYS OFF SQL: " . $sql . "<br><br>";//error
exit;
it does update the day off to Shift_ID = "6", so it must be something happening after that.
EDIT: It appears as though the problem was with user permissions. I can't explain why, but after deleting the user and creating a new one with full permissions, things started to work. I chose #andho's answer as he helped me get to the answer in the chat forum and also added a way to clean up my code.
This doesn't solve your issue, but simplifies the solution!
if your offdays variable is as follows: $offdays = array('Fri', 'Sun');
You can first set all dates in range to $shift in one query:
UPDATE Schedule SET Shift_ID = '$shift' WHERE Date BETWEEN '$from' AND '$to' AND Emp_ID = '$emp_id'
Then you can loop through the foreach ($offdays as $offday) { and update those offdays:
UPDATE Schedule SET Shift_ID = '$off' WHERE Date BETWEEN '$from' AND '$to' AND Emp_ID = '$emp_id' AND DATE_FORMAT(Date, '%a') = '$offday'
That should update all the $offday's in the range to $off.
This will reduce your loops and queries, which gives leaner code.
$sql = ("SELECT `Date` FROM schedule WHERE (`Date` BETWEEN '$from' AND '$to') AND (Emp_ID = '$emp_id')");
Use backtick(`) to all the fieldname date because it is reserved in mysql.