PHP syntax error for storing data into mysql db - php

Question

I have resolved the issue. The following code now works perfectly.
Thank you all.
Please the relevant section of dbcontroller.php file as follows:
<?php
class DBController {
function runQuery2($query) {
$result = mysql_query($query);
return $result;
}
}
In addition, I have amended my original MySQL statements in my main html/php file to look like this:
<?php
session_start();
require_once("dbcontroller.php");
$db_handle = new DBController();
if(!empty($_POST["submit"])) {
if ($db_handle->runQuery2("INSERT INTO cquestionstable
(postid, ccode, nick, queries) VALUES ( 1,'cc-001', 'james', 'what
could be the problem?')") === TRUE) {
echo "New record created successfully";
} else {
echo "Error in posting question, pls try again." . "<br>";
}
?>
Thanks n cheers.

Answer 1

Your Code:
<?php
session_start();
require_once("dbcontroller.php");
$db_handle = new DBController();
if(!empty($_POST["submit"])) {
$sql = "INSERT INTO cquestionstable (postid, ccode, nick, queries) VALUES ( 1,'cc-001', 'james', 'what could be the problem?')";
if ($db_handle->runQuery($sql) === TRUE) {
echo "New record created successfully";
} else {
echo "Error: " . $**sql . "<br>" . $db_handle->error;
}
}
?>
I see the errors already.
First if (!empty($_POST["submit"])) { should be if (isset($_POST["submit"])) {
Then you used if ($db_handle->runQuery($sql) === TRUE) { which should actually be if ($conn->query($sql) === TRUE) {
Then in your echo you used $**sql which should be $sql
Then i did not know what dbcontroller.php was but the final code should be
<?php
// session_start(); You do not need this when inserting into database
include "dbcontroller.php";
if (isset($_POST["submit"])) {
$sql = "INSERT INTO cquestionstable (postid, ccode, nick, queries) VALUES (1, 'cc-001', 'james', 'what could be the problem?')";
if ($conn->query($sql) === TRUE) {
echo "New record created successfully";
} else {
echo "Error: " . $sql . "<br>" . $connn->error;
}
}
?>
dbcontroller.php
<?php
$servername = "localhost";
$username = "username";
$password = "password";
$dbname = "myDB";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
?>
If you still do not understand why it is not working please look at w3Schools
Hope this is the answer you we're looking for.