SQL syntax error in php code - php

Question

I am passing value from android using POST and run the query in SQL DB using PHP. I am always getting
You have an error in your SQL syntax; check the manual that
corresponds to your MySQL server version for the right syntax to use
near '' at line 1.
The code is working fine if i pass the values directly insted $_POST[].
I've gone through SO but no questions solved my problem. I tried with mysql_real_escape_string($searchTermBits) also but that doesn't worked.
PHP:
<?php
$username = "xxxx";
$password = "xxxx";
$host = "xxxx";
$database = "xxxx";
$server = mysql_connect($host, $username, $password);
$connection = mysql_select_db($database, $server);
$search = $_POST["deskey"];
$search = explode(" ", $search);
$commonwords = "a,an,and,I,it,is,do,does,for,from,go,how,the,etc,in,on,are";
$commonwords = explode(",", $commonwords);
foreach ($search as $value)
{
if (!in_array($value, $commonwords))
{
$query[] = $value;
}
}
$query = implode(" ", $query);
$searchTerms = explode(" ", $query);
$searchTermBits = array();
foreach ($searchTerms as $term)
{
$term = trim($term);
if (!empty($term))
{
$searchTermBits[] = "description LIKE '%$term%'";
}
}
$myquery = "SELECT * FROM `logins` WHERE " . implode(' OR ', mysql_real_escape_string($searchTermBits)) . "";
$query = mysql_query($myquery);
if (!$query)
{
echo mysql_error();
die;
}
$data = array();
for ($x = 0; $x < mysql_num_rows($query); $x++)
{
$data[] = mysql_fetch_assoc($query);
}
echo json_encode($data);
mysql_close($server);
?>
What changes can i make this code to work with $_POST[].