PDO Statement does not return full array - php

Question

I cant figure out why i only get 1 entry in the returning array, when the table has 4 entries in total.
My PDO code is:
$stmtkat = $this->db->prepare("SELECT * FROM kategorie");
$stmtkat->execute();
$katarray=$stmtkat->fetch(PDO::FETCH_ASSOC);
var_dump($katarray);
The return array i get:
array(2) { ["id"]=> string(1) "1" ["kategorie"]=> string(12) "Coaching" }
The table has 4 rows, why do i get only the first row into the array?
What i am doing wrong? Obviously i am new to PDO.
Ty for your time.

Answer 1

You are only fetching one of the result rows produced by your query
If you use ->fetch() to get result rows one at a time you do it in a while loop like this
$stmtkat = $this->db->prepare("SELECT * FROM kategorie");
$stmtkat->execute();
while ( $katarray=$stmtkat->fetch(PDO::FETCH_ASSOC) ) {
var_dump($katarray);
}
Or use fetchAll() to return all rows into a local array from a single call to the PDO Stmt object
$stmtkat = $this->db->prepare("SELECT * FROM kategorie");
$stmtkat->execute();
$katarray=$stmtkat->fetchAll(PDO::FETCH_ASSOC) ) {
var_dump($katarray);

Answer 2

You get only one row in return because:
PDOStatement::fetch — Fetches the next row from a result set
Use fetchAll() instead to get full array() of result or use fetch() inside while() loop.
Example with fetch() and while():
while ($stmtkat->fetch(PDO::FETCH_ASSOC)) {
var_dump($katarray);
}
Example with fetchAll():
$result = $stmtkat->fetchAll(PDO::FETCH_ASSOC)
var_dup($result);