explode/implode from database php - php

Question

I'm want string out of the column data.
But it failed.
<?php
$conn = mysql_connect("localhost", "nantawat", "12345678") or die(mysql_error());
$select_db = mysql_select_db("my_db", $conn) or die(mysql_error());
$select_tbl = mysql_query("SELECT * FROM log", $conn);
while ($fetch = mysql_fetch_object($select_tbl)) {
$r = $fetch->data;
$i = explode(",", $r);
if (!isset($i[1])) {
for ($j = 0; $j <= 200; $j++) {
$i[$j] = null;
}
}
$name = $i[0];
$mama = $i[1];
$no = $i[2];
$a = $i[3];
$b = $i[4];
echo $name . "</br>";
echo $mama . $no . $a . $b . "</br>";
}
while ($data = mysql_fetch_object($select_tbl)) {
echo $data->data . "<br>";
}
?>
But i want output =
bus
car
bike
aabus
car
bike
aabus
car
bike
aabus
ddd
ee
And i not
Notice: Undefined offset: 3 in C:\xampp\htdocs\logs\New folder
(2)\explode.php on line 21
Notice: Undefined offset: 4 in C:\xampp\htdocs\logs\New folder
(2)\explode.php on line 22
Thank You.

Answer 1

You should just do what you want to do.
You want to connect to database then do it:
$conn = mysql_connect("localhost", "nantawat", "12345678") or die(mysql_error());
I suggest you to use mysqli library instead of mysql (mysql is deprecated in new php versions and totally removed in php7)
$conn = mysqli_connect("localhost", "nantawat", "12345678", "my_db") or die(mysql_error());
You want to query on log table, then do it:
$select_tbl = mysqli_query($conn, "SELECT * FROM log");
You want to fetch info from your result, then do it:
while ($row = mysqli_fetch_array($select_tbl)) {
echo $row['id_user'];
echo $row['id_doc'];
echo $row['date'];
echo $row['data'];
}
You want to explode data, then do it:
while ($row = mysqli_fetch_array($select_tbl)) {
echo $row['id_user'];
echo $row['id_doc'];
echo $row['date'];
$data = explode(',', $row['data']);
foreach ($data as $d) {
if ($d !== '') { // because before first comma or after last can be empty
echo $d . PHP_EOL;
}
}
}
If you want to save database result in variables:
If you are getting only one row of database, you can save them in variables directly:
$id_user = '';
$id_doc = '';
$date = '';
$data = array();
id ($row = mysqli_fetch_array($select_tbl)) {
$id_user = $row['id_user'];
$id_doc = $row['id_doc'];
$date = $row['date'];
$tempData = explode(',', $row['data']);
foreach ($tempData as $d) {
if ($d !== '') {
$data[] = $d;
}
}
}
And if you have multiple rows of database you need to save them all in a total array:
$array = array();
id ($row = mysqli_fetch_array($select_tbl)) {
$id_user = $row['id_user'];
$id_doc = $row['id_doc'];
$date = $row['date'];
$data = array();
$tempData = explode(',', $row['data']);
foreach ($tempData as $d) {
if ($d !== '') {
$data[] = $d;
}
}
$array[] = array(
'id_user' => $id_user,
'id_doc' => $id_doc,
'date' => $date,
'data' => data,
);
}
And finally use this to see what structure your final array has:
echo '<pre>';
pront_r($array);
echo '</pre>';

Answer 2

First off it is not wise to store comma seperated values in a single cell and you are using deprecated mysql_ functions. I think your solution can be found in using a foreach instead of the isset part:
while ($fetch = mysql_fetch_object($select_tbl)) {
$r = $fetch->data;
$i = explode(",", $r);
foreach ($i as $q){
echo $q . '<br/>';
}
}
If you still want to access your variables $name, $mama, $no and $ab, you can use isset for those specifically.
while ($fetch = mysql_fetch_object($select_tbl)) {
$r = $fetch->data;
$i = explode(",", $r);
if (isset($i[0])){
$name = $i[0];
echo $name . '<br>'; //only echo if it exists
}
if (isset($i[1])){
$mama= $i[1];
echo $mama. '<br>'; //only echo if it exists
}
//try it yourself for $no and $ab
}

Answer 3

Try:
while ($row = mysqli_fetch_array($select_tbl)) {
extract($row);
/* Using extract method can get the array key value as variable
Below variables are available
$id_user;
$id_doc;
$date;
$data; */
}