Just a simple question to ask if there is someone available to assist me. Please take a look at this section on my index page:
<?php foreach($galleries as $item) { ?>
<div class="col-md-2">
<p>Eagle Fruit <?= $item['gallery_name'] ?></p>
<img src="<?php echo base_url() . 'assets/img/site/' . $item['gallery_cover'] ?>" class="img-responsive">
View the Gallery
</div>
<?php } ?>
My Controller is setup with the following function
<?php defined('BASEPATH') OR exit('No direct script access allowed');
class Site extends MX_Controller {
public function __construct()
{
parent::__construct();
$this->load->model('gallery/Gallery_m');
}
public function index($id = 'ID')
{
$data['title'] = 'Welcome to Eagle Fruit Alliance (Pty) Ltd';
$data['galleries'] = $this->Gallery_m->get_galleries();
$data['gallery'] = $this->Gallery_m->view($id);
$data['content'] = 'index_view';
$this->load->view('templates/site/template',$data);
}}
Now when I click on the link i would like the gallery to open in a modal how would i achieve this? I have added a modal with the following code where am I going wrong:
Modal
<!-- Modal -->
<div class="modal fade" id="gallery" tabindex="-1" role="dialog" aria-labelledby="myModalLabel">
<div class="modal-dialog" role="document">
<div class="modal-content">
<div class="modal-header">
<button type="button" class="close" data-dismiss="modal" aria-label="Close"><span aria-hidden="true">×</span></button>
<h4 class="modal-title" id="myModalLabel"><?= $gallery['name'];?></h4>
</div>
<div class="modal-body">
...
</div>
<div class="modal-footer">
<button type="button" class="btn btn-default" data-dismiss="modal">Close</button>
</div>
</div>
</div>
</div>
<!-- ./Model -->
Because you are interacting with the user's click on an image, this isn't a PHP or HTML question. User interaction always involves javascript/jQuery.
AJAX is a two-part methodology. It is initiated in javascript, and sends data to a server-side PHP file that does something and returns a response, which is received/dealt with in javascript. See this SO post for more information on AJAX.
However, this question doesn't need to use AJAX either, because there is no additional data to fetch.
It's a bit difficult from your code to see exactly how to trigger the modal. Usually, we look for a commonality in the code, such as a class name, to use as the trigger. In your case, you could try:
$('p+img').click()
However, I recommend modifying your code like this:
<img class="mod_trig img-responsive" src="<?php echo base_url() . 'assets/img/site/' . $item['gallery_cover'] ?>" >
Note: I moved the class to front of tag only to make it very visible in this answer. Keep it where it is in your code, if you wish.
Next, when a trigger is clicked, you use CSS selectors (jQuery uses CSS selectors, so learn them -- and Bootstrap uses jQuery, so learn jQuery) to get the href attribute of the <a> tag -- this is the direct link to the desired image, correct? You would only need to use AJAX if you didn't already have some information available to you on the page, but in this case you have all you need.
Use jQuery's .html() method to create an <img> tag inside the Bootstrap modal, replacing whatever was in that particular DIV. Here is a very simple example where we demonstrate exactly this procedure, but instead of putting it into the Bootstrap modal's framework we simply create the <img> tag inside a pre-existing DIV called #msg.
jsFiddle Demo
$('p+img').click(function(){
var i = $(this).next('a').attr('href');
//alert(i);
$('#msg').html('<img src="'+i+'" class="msg" width="200" height="200" />');
});
#msg{position:absolute;top:30%;left:40%;}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.0/jquery.min.js"></script>
<div>
<p>This is a test</p>
<img src="http://placeimg.com/98/100/animals" />
View the Image
</div>
<div>
<p>This is a test</p>
<img src="http://placeimg.com/100/95/animals" />
View the Image
</div>
<div>
<p>This is a test</p>
<img src="http://placeimg.com/95/95/animals" />
View the Image
</div>
<div id="msg"></div>
*It's not a perfect example, because the placeholder image website does not serve the same image when requesting identical parameters, so you can uncomment the alert() line to see that each time you click an image you get different parameters injected into the #msg div -- you get the correct parameters for the <img> on which you clicked.
Now, all you need to do is to inject (via html() method) the newly-created <img> tag into the appropriate Bootstrap div instead of into the #msg div:
$('.modal-body').html('<img src="'+i+'" class="msg" width="200" height="200" />');
And trigger the modal to display:
jsFiddle Next Demo
$('.mod-trigger').click(function(){
var i = $(this).next('a').attr('href');
$('.modal-body').html('<img src="'+i+'" class="msg" width="200" height="200" />');
$('#gallery-lightbox').modal('show');
});
Note how in this example I replaced the CSS selector with '.mod-trigger', and created a class on each image with that className
This new example shows you how to trigger the modal if a user clicks on the <a> tag:
jsFiddle Demo
Note that the <a> tag's default action is to navigate to another page. You don't want this, so the first thing you must do is suppress that default behavior:
$('.mod-atag').click(function(e){
e.preventDefault();
var i = $(this).attr('href');
$('.modal-body').html('<img src="'+i+'" class="msg" width="200" height="200" />');
$('#gallery-lightbox').modal('show');
});
Also note that I added a className to each <a> tag to make it easy to detect the click.
Related
Please I'm new to coding and I have a project i am working on.
I have a php while loop code that diplay 5 posts
I also have a jQuery code to display modal for the while loop with post url
The problem I'm face here is that the displayed url is inside a div
<p id="url"></p> this show the url
I want to add it as url.
I have tried </p>'> Click to view
But the link will not show
I have tried echo it still not showing.
I have been on this for two days now
The modal that display the content is outside the while loop and working
I need help
My ajax code
<script>
function showModal(id)
{
$("#url").text($("#url_"+id).text());
}
</script>
Php loop code
`<?php
foreach ($posts as $key => $result) { ?>
<div href="#" data-toggle="modal" data-target="#myModal" onClick="showModal(<?php echo $id ; ?>)" class="side-icon share-btn">
<i class="fa fa-share share-icon"></i> View link
<?php } ?>
<div class="modal fade" id="myModal" role="dialog" >
<div class="modal-dialog" style="position:absolute;bottom:0;margin:0;width:100%;">
<div class="modal-content">
<div class="modal-header">
<center><h4>Share with friends</h4></center>
<?php $t='<p id="name"></p>';
$t1?>
. Click to view
</div>
`
The id containers the url from MySQL table
The issue I'm facing is that, <p id="url"></p> is just showing www. example.com as plain test on user view but can't make it work as link to click
A hyperlink a is not necessary to invoke the modal dialog - most DOM elements can invoke whatever function you like. You assign an event listener either to all nodes of interest or a delegated listener bound to a common parent element. The snippet below might be of use?
// add delegated listener on the containing node that has the content that is to be clicked
// by the user to invoke the modal dialog.
document.querySelector('div.urls').addEventListener('click', function(e) {
// Only process nodes that are not the specified target itself. ie: it's children
if (e.target != e.currentTarget) {
let modal=document.getElementById('myModal');
// add the content from the clicked node to the modal somewhere
let link = modal.querySelector('a[data-id="modal-target"]');
link.setAttribute('href', e.target.textContent);
link.innerHTML = 'Click to view';
}
});
.url:hover {
color: red
}
.url {
cursor: pointer;
}
<div class='urls'>
<p class='url'>https://www.example.com</p>
<p class='url'>https://www.banana.com</p>
<p class='url'>https://www.bogus.org</p>
</div>
<div class="modal fade" id="myModal" role="dialog">
<div class="modal-dialog" style="position:absolute;bottom:0;margin:0;width:100%;">
<!-- Modal content-->
<div class="modal-content">
<div class="modal-header"></div>
<a data-id='modal-target'></a>
</div>
</div>
</div>
I split my body content in two parts. The left one has a map and buttons. When I click on the button, I get the result from Arad.php in another window.
How can I set the target to the second half (split right) of my body?
<body>
<div class="split left">
<div class="centered">
<h2>Button on Image</h2>
<p>Add a button to an image:</p>
<div class="container">
<img src="Harta_Romaniei.jpg" alt="Harta_Romaniei" style="width:100%">
<button class="btnarad"; onclick= "window.location.href='Arad.php'"; Target="split right">Arad</button>
<button class="btntimisoara">Timisoara</button>
</div>
</div>
</div>
<div class="split right">
<div class="centered">
<h2>Information</h2>
// I want the information here!
</div>
</div>
</body>
It doesn't have much to do with PHP, you should really do it with HTML + JavaScript.
The window.href.location will always redirect you to another route, and will never do what you want.
You'll need something like this: Simple Load an HTML page from javascript based on window width
I'm looking to change this bit of code to a link instead of having it appear as a small popup window. How would I change it to link to a page of "http://example.com/register" instead of having the registration window drop down?
<div class="login-wrapper">
<a id="sticky-login" class="info-bottom icon-login sticky-button" title="<?php _e('Login',IT_TEXTDOMAIN); ?>"></a>
<div class="sticky-form" id="sticky-login-form">
<div class="loading">
<div> </div>
</div>
<?php echo it_login_form(); ?>
</div>
</div>
This seems too easy so I'm probably missing something.
You'd add an href attribute to the <a> tag, and if javascript is creating the popup, remove either the id attribute from the <a> tag or the class to which the javascript is linked.
<a class="info-bottom icon-login sticky-button" title="<?php _e('Login',IT_TEXTDOMAIN); ?>" href="http://example.com/register"></a>
I have a 'blog' page in which the blog posts are generated using php. The divs all have the same classes, PHP code below:
$loopResult .= '
<div class="blogbox show">
<div class="blogtitle">'.$row['TITLE'].'</div>
<div class="blogdate">'.$row['DATE'].'</div>
<div class="blogcontent">'.$row['CONTENT'].'</div>
<div class="blogimage"> <img src="'.$row['IMAGE'].'"/></div>
<div class="blogimage"> <img src="'.$row['IMAGEB'].'"/></div>
<div class="blogimage"> <img src="'.$row ['IMAGEC'].'"/></div>
<div class="showHide">Show/Hide</div>
</div>
';
}
echo $loopResult;
I have a jquery click function on the showHide div that will toggle a class to expand the div for reading.
JQUERY:
$('.showHide').click(function() {
$('.blogbox').toggleClass('show');
});
Obviously, my issue is that the click function expands ALL of the blog posts, not just the one in which the user clicked.
How do I go about doing this so only the div selected is expanded? As you can see, I am relatively new to this so any help is appreciated.
Thank you!
Try this:
$('.showHide').click(function() {
$(this).closest('.blogbox').toggleClass('show');
});
Do it like this.
$('.showHide').click(function(){
$(this).toggleClass('show');
});
Using the general class name showHide as the selector fpr the click event, but referring only to the actual element with this will do the trick for you.
Here's a fiddle for you:
http://jsfiddle.net/hhgxsnv1/
And with smoother effects you can also include the jQuery ui library:
http://jsfiddle.net/hhgxsnv1/2/
$('.showHide').click(function(){
$(this).toggleClass('show', 500, 'easeOutSine');
});
I have some HTML menus, which I show completely when a user clicks on the head of these menus. I would like to hide these elements when the user clicks outside the menus' area as well as clicking on myaccount section again.
Here is the code,
<li onclick="san()">
<div id="topnav"><a id="displayText" href="#" class="signin">My Acount</a></div>
<div id="topnav1" style="display:none;"><a id="displayText1" href="#">My Acount</a></div>
</li>
<div id="signin_menu" style="display:none;">
<div class="droptop"></div>
<div class="maindropsign">
<div class="header_box">My Acount</div>
<div class="txt_drop">My Profile</div>
<div class="txt_drop">My Backer History</div>
<div class="txt_drop">Edit Settings</div>
<div class="txt_drop_log">Log Out</div>
</div>
<div class="dropbut"></div>
</div>
<script language="javascript">
function san()
{
if(document.getElementById('signin_menu').style.display=='')
{
document.getElementById('signin_menu').style.display='none';
document.getElementById('topnav1').style.display='none';
document.getElementById('topnav').style.display='';
}
else
{
document.getElementById('signin_menu').style.display='';
document.getElementById('topnav1').style.display='';
document.getElementById('topnav').style.display='none';
}
}
</script>
Please help me to do this.
You have to remember the state of the menu first, like set var open = true when its open. Then make a function that 'toggles' and bind that to the onClick event of your menu-head. Then either bind a closeMenu function on an onClick event directly to your whole document or on an onMouseOut from your menu (you can even build a delay here).