PHP - How to get datetime string from DateTime object - php

I've made a DateTime object using
$currtime = DateTime::createFromFormat("YmdHi");
Is there a way to get a string or an integer, which contains, for example, 201604041825?
$currtime->modify("+2 hours");
$newtime = $currtime->format("YmdHi");
returned
$newtime = 2147483647

This will help you
$current_date_object= new DateTime();
$current_date_object->modify("+2 hours");
$current_date_string= $current_date_object->format("Y-m-d H:i:sO");

Related

How to correctly add a date and a time (string) in PHP?

What is the "cleanest" way to add a date and a time string in PHP?
Albeit having read that DateTime::add expects a DateInterval, I tried
$date = new \DateTime('17.03.2016');
$time = new \DateTime('20:20');
$result = $date->add($time);
Which was no good and returned nothing to $result.
To make a DateInterval from '20:20', I only found very complex solutions...
Maybe I should use timestamps?
$date = strtotime($datestring);
$timeObj = new \DateTime($timestring);
// quirk to only get time in seconds from string date
$time = $timeObj->format('H') * 3600 + $timeObj->format('i') * 60 + $timeObj->format('s');
$datetime = $date+$time;
$result = new \DateTime;
$result->setTimestamp($datetime);
In my case, this returns the desired result, with the correct timezone offset. But what do you think, is this robust? Is there a better way?
If you want to add 20 hours and 20 minutes to a DateTime:
$date = new \DateTime('17.03.2016');
$date->add($new \DateInterval('PT20H20M'));
You do not need to get the result of add(), calling add() on a DateTime object will change it. The return value of add() is the DateTime object itself so you can chain methods.
See DateInterval::__construct to see how to set the intervals.
DateTime (and DateTimeImmutable) has a modify method which you could leverage to modify the time by adding 20 hours and 20 minutes.
Updated
I've included examples for both DateTime and DateTimeImmutable as per the comment made, you don't need to assign the outcome of modify to a variable because it mutates the original object. Whereas DateTimeImmutable creates a new instance and doesn't mutate the original object.
DateTime
<?php
$start = new DateTimeImmutable('2018-10-23 00:00:00');
echo $start->modify('+20 hours +20 minutes')->format('Y-m-d H:i:s');
// 2018-10-23 20:20:00
Using DateTime: https://3v4l.org/6eon8
DateTimeImmutable
<?php
$start = new DateTimeImmutable('2018-10-23 00:00:00');
$datetime = $start->modify('+20 hours +20 minutes');
var_dump($start->format('Y-m-d H:i:s'));
var_dump($datetime->format('Y-m-d H:i:s'));
Output
string(19) "2018-10-23 00:00:00"
string(19) "2018-10-23 20:20:00"
Using DateTimeImmutable: https://3v4l.org/oRehh

Not getting the required date

I want to calculate the difference between date using date_diff(), whose 1st parameter is saved data in database and the 2nd parameter is today's date. The $pro_deadline is coming from database and is of type text (format yyyy-mm-dd), so I converted it into time using strtotime(). But in the end I'm getting "
Warning
: date_diff() expects parameter 1 to be DateTimeInterface, string given"
$today = date("Y-m-d");
echo $today;
$end = strtotime($pro_deadline);
$end_line = date("Y-m-d",$end);
echo $end_line;
$diff = date_diff($end_line,$today);
echo $diff;
as per PHP documentation http://php.net/manual/en/function.date-diff.php
date_diff — Alias of DateTime::diff()
so the perameters to date_diff should be DateTimeInterface types.
i would try
<?php
$today = date("Y-m-d");
echo $today." ";
$today = date_create($today);
$pro_deadline = '10-15-18';
$end = strtotime($pro_deadline);
$end_line = date_create(date("Y-m-d",$end));
$diff = date_diff($end_line,$today);
echo $diff->format('%a');
echo " days apart";
?>
the date_create() function is an alias of the DateTime constructor.
http://php.net/manual/en/datetime.construct.php
this creates an interface for the date/time that the date_diff() function can interpret. then date_diff() returns a DateInterval object
http://php.net/manual/en/class.dateinterval.php
the DateInterval object has a format method
http://php.net/manual/en/dateinterval.format.php
that can return the date in a sting for you.
Hope this explanation helps!
Like the error message says, date_diff expects DateTimeInterface parameters. strtotime returns a timestamp as an integer, which it can't work with.
Instead of creating timestamps, you can pass your deadline to the DateTime constructor, along with another version that'll default to now:
$today = new DateTime;
$end = new DateTime($pro_deadline);
and then pass these two objects to date_diff, and use the DateInterval::format method to display the number of days (assuming this is your desired output):
$diff = date_diff($today,$end);
echo $diff->format('%a');
See https://3v4l.org/QVkad for a full example
First of all, if you want a difference between a date in a database and today's date, just do it in the database directly. You didn't specify which DB, but, for example in MySQL you'd do something like:
SELECT DATEDIFF(some_field, now()) FROM ...
If you insist on doing it in PHP, then don't use strtotime but use DateTime object:
$today = new DateTime();
$end = new DateTime($pro_deadline);
$diff = $end.diff($today)
The date() function returns a simple string, but the date_diff() function expects a date object.
You can do it all much more simply with the functions in the DateTime class:
$pro_deadline = "2018-09-01";
$today = new DateTime();
$end = new DateTime($pro_deadline);
$interval = $end->diff($today);
echo $interval->format('%R%a days');
This example outputs +25 days Click here for Runnable Demo
Further examples of the diff() function here

Int overflow when creating php datetime

I am currently working on displaying a moment. I want the view to use DateTime->format(..). The value I am getting from the API is 1502462223168. However, this is displayed as 1945-5-26 16:36 instead of 2017-8-11 16:37, since the original value exceeds the PHP_MAX_INT value on the system.
Is there a way I can use the original value, maybe as a String, to create the DateTime object?
since your timestamp value is in milliseconds, divide it by 1000 and then use DateTime, like:
$date = new DateTime();
$stamp = intval(1502462223168/1000);
$date = DateTime::createFromFormat("U", $stamp)->format("Y-m-d H:i:s");
echo $date;
Use this it will be working fine for your question
$timestamp = 1465298940;
$datetimeFormat = 'Y-m-d H:i:s';
$date = new DateTime();
// If you must have use time zones
// $date = new \DateTime('now', new \DateTimeZone('Europe/Helsinki'));
$date->setTimestamp($timestamp);
echo $date->format($datetimeFormat);

PHP: How to set timezone for an offset DateTime

I'm trying to create a DateTime object offset from the present with a specific timezone. It works for 'today', or an absolute value like '2017-07-16 00:00:00', but if I try an offset, like '+1 sundays' it always has a timezone of "S".
$dtz = date_default_timezone_get();//"America/Vancouver"
$now = new \DateTime('today', new \DateTimeZone($dtz));
$sunday = new \DateTime('+1 sundays', new \DateTimeZone($dtz));
$later = new \DateTime('2357-04-13', new \DateTimeZone($dtz));
$tz1 = $now->getTimezone()->getName();//"America/Vancouver"
$tz2 = $sunday->getTimezone()->getName();//"S"
$tz3 = $later->getTimezone()->getName();//"America/Vancouver"
How should I do this?
The first parameter to DateTime should be a valid date/time string. It even takes null when using timezone as second parameter.
'+1 sundays' is not under the category of valid date/time string. Check the complete list here
Below should work -
$sunday = $now->modify('+1 sundays');
echo $sunday->getTimezone()->getName();//"America/Vancouver"

How to convert a PHP DateTime object to ISO string?

I have a date that I receive in MS format for JSON dates. It looks like this:
/Date(1365004652303)/
I can convert it to a PHP DateTime object by doing this:
$timestamp = round(((int) $originalMSdate) / 1000);
$convertedDate = new DateTime();
$convertedDate->setTimestamp($timestamp);
Ultimately, though, I need it to be a string in ISO 8601 format. I tried then converting it to an ISO date object & then converting that to a string with strval() but strval() doesn't work on date objects.
I've also tried
$dateString = date_format($convertedDate, 'YY-MM-DD H:i:s');
but I need it to also include timezone info, like this: 2015-10-01T21:22:57.057Z
I don't see characters for that in date_format.
How can I achieve this?
EDIT: I should clarify that I'm not printing the resulting string. I need to pass it to a field in a database that accepts a string datatype.
Please try the below code
<?php
// input
$time = microtime(true);
// Determining the microsecond fraction
$microSeconds = sprintf("%06d", ($time - floor($time)) * 1000000);
// Creating DT object
$tz = new DateTimeZone("Etc/UTC");
$dt = new DateTime(date('Y-m-d H:i:s.'. $microSeconds, $time), $tz);
$iso8601Date = sprintf(
"%s%03d%s",
$dt->format("Y-m-d\TH:i:s."),
floor($dt->format("u")/1000),
$dt->format("O")
);
// Formatting according to ISO 8601-extended
var_dump(
$iso8601Date
);
This worked:
$timestamp = round(((int) $originalMSdate) / 1000);
$dateString = date('c', $timestamp);
The format isn't EXACTLY the same. It's in this format:
2016-04-25T14:27:00-05:00 rather than
2016-04-25T14:27:00.057Z
but it's close enough that I can do some manipulation to get what I need.
this one is worked for me. For more please refer this article.
$date = date('Y-m-d H:m:s');
echo date('c', strtotime($date)); // 2020-04-08T16:04:56+05:30
echo date(DateTime::ISO8601, strtotime($date)); // 2020-04-08T16:04:56+0530
echo date(DateTime::ATOM, strtotime($date)); // 2020-04-08T16:04:56+05:30

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