Outputting each value in array - php

Question

I have this foreach loop nested inside a while loop:
foreach ($_SESSION['arrayPoints'] as $value) {
echo $value;
}
This outputs the all the values stored in the array, 543216 as shown below, but as the foreach loop is in the while loop, 543216 is repeated until there are no more rows:
I need the foreach loop to output each value in the array separately for each row.
So for example (using the image above and the array values of 543216):
I need the output to show 5 for the first row, then 4 for the second row, 3 for the 3rd row, 2 fourth row and so on (as shown below).
Dave Jackson |TEXT BOX| |DROP-DOWN| 5
Bobby Brown |TEXT BOX| |DROP-DOWN| 4
Daniel Grey |TEXT BOX| |DROP-DOWN| 3
Richard Green |TEXT BOX| |DROP-DOWN| 2
David Bolt |TEXT BOX| |DROP-DOWN| 1
Jason Moore |TEXT BOX| |DROP-DOWN| 6
How can this be done?
EDIT:
print_r($_SESSION['arrayPoints']);
outputs:
Array ( [0] => 5 [1] => 4 [2] => 3 [3] => 2 [4] => 1 [5] => 6 )
-The While loop: while ($data = mysqli_fetch_assoc($result)) { is a query fetch action.
-Each row shown in the image above is in order with each number in the array. So first row = 5 , second row = 4 and so on.
Thanks in advance.

Answer 1

Your current code says that you want to print every number for each data fetched from DB, which is not what you want. You want a single number printed for each data. So forget the foreach. What you need is:
echo $_SESSION['arrayPoints'][$i];
where $i is the current row being fetched (you need to set and increment it).