Calculating data from one DB table with range of dates - php

Question

I have sql function:
$sql = "SELECT date(datum_ura) as datetime,
COUNT(CASE rezultat_status_fk WHEN 5 THEN rezultat_status_fk END) AS half_lost, AVG(kvota) as average, SUM(vlozek) as vlozek,
SUM(CASE rezultat_status_fk WHEN 1 THEN vlozek * kvota WHEN 2 THEN vlozek WHEN 3 THEN 0 END) AS case_profit,
SUM(CASE rezultat_status_fk WHEN 1 THEN vlozek * kvota-vlozek WHEN 2 THEN 0 WHEN 3 THEN -vlozek END) AS profit
FROM bs_analiza
WHERE users_fk=$user_id"." group by date(datum_ura)";
The function is getting data from one table and calculates it and show results by dates. I'm trying to do a function which can sum current date result with the day before result....and so on.
I'm thinking of something like:
foreach ($items as $key => $value) {
$date = $value->datetime;
$prev_date = date('Y-m-d', strtotime($date .' -1 day'));
$prev_date = strtotime($prev_date);
$i = $key-1;
$profit_before = $items[$i]->$prev_date;
But I'm still getting the same results.

Answer 1

You can achieve this with selects from your intermediate result, I suggest you either create a view or use WITH.
SELECT
datetime,
(SELECT SUM(vlozek) FROM ... WHERE datetime >= t.datetime) vlozek_cumsum,
(SELECT SUM(case_profit) FROM ... WHERE datetime >= t.datetime) case_profit_cumsum,
(SELECT SUM(profit) FROM ... WHERE datetime >= t.datetime) profit_cumsum
FROM
... t
ORDER BY
datetime DESC
... is your intermediate result.
Edit (to clarify): You get your intermediate result by a select statement. So you can either
Create a view and replace ... by the name of the view or
CREATE OR REPLACE VIEW <view_name> AS <select_stmt>
Use WITH and replace all ... in the query above by the alias name.
WITH <alias_name> AS ( <select_stmt> )
SELECT
...