I have TWO table
task_emp_designation
task_employee
*task emp_designation table like this *
id -> 1 2 3 4
designation -> webdeveloper, designe, tester, programmer
And task_employee tabel one field nane is there, called emp_designation,in that table i stored like 1 or 4 or 3 ...
For my question is while selecting the emp_designation values,it will return like 1 or 4 or 3,
i want to show 1 means developer,2 means designer ,3 means tester,like that i want show,i don't know how to do this
SELECT task_employee.id, task_emp_designation.designation
FROM task_employee
INNER JOIN task_emp_designation
ON task_employee.emp_designation = task_emp_designation.id;
That would do what you want if I understood you correctly
Related
I am wanting to convert data that is queried from the database to another string. The best way I can explain what I'm trying to do is below:
I have a table called "users". Inside that table I have a column called "rank". Rank is a two-digit integer ranging from 1 to 21.
I want to convert that "1" or whichever number into more understandable text in my php file. So if your rank is set to "1", the output is "User" or what-have-you.
How do I go about doing this? I'm not sure what this process is called. I'm very new to php.
Thank you!
Create a rank table having 2 columns, id and rank:
id | rank
-------------
1 | user
2 | admin
3 | goof
Then JOIN the users table with the rank table:
SELECT u.name, r.rank
FROM users u
LEFT JOIN rank r
ON u.rank = r.id
You can store the ranks title in another table like mentioned by Jay Blanchard or you can define an array with the rank titles like this
$ranks = array(
1 => 'User',
2 => 'Administrator',
3 => 'Moderator'
);
and can echo like this
echo $ranks['rank_id_fetched_using_sql'];
rank_id_fetched_using_sql is supposed to be 1 to 21
I have three tables where table_2 is the middle(connected) between table_1 and table_3
tables
table_id
...
...
table_rest
rest_id
table_id
...
rest
rest_id
...
...
And the query to select I use
SELECT m.table_id, table_name
FROM tables m
JOIN table_rest mr
ON m.table_id = mr.table_id
WHERE rest_id = '$rest_id'
What I need now is to join in this query another table reserv
id
...
status
To check if status is 0, 1,or 2 to not show me anything if there is no status this mean there is no record to show me. In other words this is resserved system where I show on screen few tables. If status is 0,1,2 thats mean the table is taken. If nothing is found for status this mean that there is no record for table and can be shown to user.
EDIT: Sample scenario
tables
table_id
1
2
3
4
5
rest
rest_id
1
2
table_rest
table_id | rest_id
1 2
2 2
3 2
4 2
5 2
So the query that is above will generate 5 tables for rest_id=2 and none for rest_id=1
So now I have another table
reserv
id | status
1 0
2 1
3 2
So in this table reserv currently are saved 3 tables. The idea is to show me other two whit id=4 and id=5 because they are not in table reserv and don't have any status.
Hope is a little bit more clear now.
You have to point from table reserv to which table is beign booked, let's call it reserv.table_id
SELECT m.table_id, table_name
FROM tables m
JOIN table_rest mr
ON m.table_id = mr.table_id
left join reserv
on reserv.table_id = m.id
WHERE rest_id = '$rest_id'
and reserv.status is null (*note)
*note use 'is' or 'is not' depending of your needs, as far as I read, first seems that you want !=, later that what you want is =
It's better if you provide sample data or sqlfiddle. Based on what I realize: Is this what you want:
select tables.table_id, rest.rest_id
from tables
left join table_rest on table_rest.table_id = tables.table_id
left join rest on rest.rest_id = table_rest.rest_id
where rest.rest_id = '$rest_id'
and tables.table_id not in (select id from reserv)
I've got two tables:
content:
id access
1 3
2 5
3 9
viewlevels:
id group
1 [10,12,15]
2 [8,12,11]
3 [9,10,5]
The access field in content is related with the id field in viewlevels.
I select the rows in viewlevels depending on the current user group. So for example, if group is = 10, my query will select rows 1 and 3. If the group is 12, it will select rows 1 and 2, etc. I'm using the following query:
$query="SELECT id FROM #__viewlevels WHERE rules LIKE '%$group%'";
My challenge is to count the number of rows for column id in table content where the access matches with the selected id's from the above query on table viewlevels.
I tried the following code but it is returning the error: undefined variable: nartigos
$query="SELECT count(id) FROM #__content WHERE access IN (SELECT id FROM #__viewlevels WHERE rules LIKE '%$group%')";
if ($stmt = mysqli_prepare($link, $query)) {
/* execute query */
mysqli_stmt_execute($stmt);
/* store result */
mysqli_stmt_store_result($stmt);
$nartigos=mysqli_stmt_num_rows($stmt);
/* close statement */
mysqli_stmt_close($stmt);
};
echo "Nº de artigos " .$nartigos;
First of all, you really should normalize your data. Consider having a many-to-many join table for viewLevels instead of having all groups in one row. That might look like this:
access_id group_id
1 10
1 12
1 15
2 8
2 11
2 12
3 5
3 9
3 10
That would make your query as simple as
SELECT c.id AS `content_id`, COUNT(v.access_id) AS `content_count`
FROM content AS c INNER JOIN viewLevels AS v
ON c.access_id = v.access_id
WHERE v.group_id = ?
GROUP BY c.id
Here ? is the group id you are querying against.
Without normalization (which again I STRONGLY recommend you do), you would still use a join, but it would look like this:
SELECT c.id AS `content_id`, COUNT(v.access_id) AS `content_count`
FROM content AS c INNER JOIN viewLevels AS v
ON c.access_id = v.access_id
WHERE v.group LIKE '%?%'
GROUP BY c.id
you need to "join" your tables.
the sql command cant query two tables seperately.
when you "join" 2 tables in your sql, think of it as making one virtual/temporary table in the air, of the 2 tables which you can then query.
this is quite a good intro http://www.sitepoint.com/understanding-sql-joins-mysql-database/
I have a Database table in MYSQL, it looks like this:
Project_ID user_ID name
11 1 fred
11 2 rick
11 1 fred
I want to get the names in the table, but when I display it I get the same name twice because the user_ID 1 appears twice in the table. I tried to display it with GROUP BY and SUM, but I don't want to do it this way. How do I get it not to return duplicate rows?
Use DISTINCT
SELECT DISTINCT user_ID
, verschil_ma
FROM project_uren
WHERE project_ID = 11
GROUP BY user_ID
Point 1 is that should the user be assigned to the project twice?
Point 2 - Use the DISTINCT keyword to return only unique records - http://dev.mysql.com/doc/refman/5.0/en/distinct-optimization.html
SELECT DISTINCT user_ID
FROM TABLE
WHERE Project_id = 11
That will return you 1 and 2 (You won't get 1 twice)
Thanks
$results = // query
$results = array_unique($results);
Is there a way I could somehow do the following?
Table ONE
id c_id type
-------------------
1 1 7
2 2 7
3 3 5
4 4 7
Table TWO
id title live
-------------------
1 row1 1
2 row2 0
3 row3 0
4 row4 1
The c_id column links the data from table ONE to table TWO. Example: in table ONE, if the c_id is 2, that row in table ONE will be directly linked to table TWO's row with id 2, which has a title of "row2".
I want to select from table ONE, everything with type 7, but only if their associated data in table TWO has live set to 1.
Here's how I thought I'd do it, but this doesn't seem to work:
SELECT * FROM ONE, TWO WHERE ONE.type='7' AND TWO.live='1' ORDER BY ONE.id DESC LIMIT 5
I would expect the above to return only rows 1 and 4 from table ONE, because although table ONE has three rows with type "7", only rows 1 and 2's associated row in table TWO have live set to 1.
You were close... try using an implicit join:
SELECT ONE.* FROM ONE, TWO WHERE ONE.type='7' AND TWO.live='1' AND ONE.c_id = TWO.id ORDER BY ONE.id DESC LIMIT 5
select * from one join two on c_id = two.id where type=7 and live = 1
order by one.id desc limit 5