how to view database data in vertical way - php

Here is my code to view data from db. some of the column must be get from other table so it will have different query. the problem is, why the second and third 'while loop' show the result in horizontal way and not vertical.
//FIRST WHILE
$result = $waran->getall();
while($row = mysql_fetch_array($result)) {
echo "<tr>";
echo " <td style='text-align:center'>".$bil."</td>";
if($_SESSION['mPosition'] == "FULL ACCESS"){
echo " <td><a href='javascript:showDialog(\"view_Waran\");showWaran(\"".$row['id']."\")' class='no_decoration'>".$row["name_position"]."</a></td>";
}else{
echo " <td>".$row['name_position']."</td>";
}
echo " <td style='text-align:center'>".$row['grade_position']."</td>";
echo " <td style='text-align:center'>".$row['code_skim']."</td>";
//SECOND WHILE
$resultWaranFix = $waran->getListWaranFix();
while ($rowWaranFix = mysql_fetch_array($resultWaranFix )) {
echo "<td>".$rowWaranFix ['total_waran_fix']."</td>";
}
//THIRD WHILE
$resultFullfilmentFix = $waran->countFullfilmentFix ();
while ($rowFullfilmentFix = mysql_fetch_array($resultFullfilmentFix )) {
echo "<td>".$rowFullfilmentFix ['fullfilment_fix']."</td>";
}
echo "</tr>";
$bil=$bil+1;
}

You could try something like this:
$result = $waran->getall();
while($row = mysql_fetch_array($result)) {
echo "<tr>";
echo " <td style='text-align:center'>".$bil."</td>";
if($_SESSION['mPosition'] == "FULL ACCESS"){
echo " <td><a href='javascript:showDialog(\"view_Waran\");showWaran(\"".$row['id']."\")' class='no_decoration'>".$row["name_position"]."</a></td>";
}else{
echo " <td>".$row['name_position']."</td>";
}
echo " <td style='text-align:center'>".$row['grade_position']."</td>";
echo " <td style='text-align:center'>".$row['code_skim']."</td>";
// You could end the row here for example.
echo "</tr><tr>";
// Instead of just adding cells you can put a table inside the cell and display all those items as rows in the sub table.
echo "<td><table>";
$resultWaranFix = $waran->getListWaranFix();
while ($rowWaranFix = mysql_fetch_array($resultWaranFix )) {
echo "<tr><td>".$rowWaranFix ['total_waran_fix']."</td></tr>";
}
echo "</table></td>";
echo "</tr><tr>";
// Same for this loop.
echo "<td><table>";
$resultFullfilmentFix = $waran->countFullfilmentFix ();
while ($rowFullfilmentFix = mysql_fetch_array($resultFullfilmentFix )) {
echo "<tr><td>".$rowFullfilmentFix ['fullfilment_fix']."</td></tr>";
}
echo "</table></td>";
echo "</tr>";
$bil=$bil+1;
}
I have changed it so the loops inside are displayed inside sub tables.

Related

Using php switch statement to display an image url in an html table from a mysql query

I have a MySQL table field which consists of a URL pointing towards an image. I'm using php and want the image to display in a table along with the other fields.
I think I need to use the PHP Switch statement and reference either the Row('Name') or Field Ref Number to create the code. I have this working fine in classic-asp, but need to code this in php.
$result = mysql_query("SELECT sometext,urlvalue,somemoretext FROM Table");
if (!$result) {
die("Query to show fields from table failed");
// Table fields
// sometext
// urlvalue an http image address such as http://www.example.com/image.jpg"
// somemoretext
$fields_num = mysql_num_fields($result);
echo "<table border='1'>
<tr bgcolor='yellow' align='left'>";
for($i=0; $i<$fields_num; $i++) {
$field = mysql_fetch_field($result);
echo "<th>{$field->name}</th>";
}
echo "\n";
// printing table rows
while($row = mysql_fetch_row($result)) {
echo "<tr>";
// $row is array... foreach( .. ) puts every element
// of $row to $cell variable
foreach($row as $cell)
switch $fields_num {
case "2":
// result cell looks like this ---->
// <td><a target='_blank' href='http://www.example.com/image.jpg'><img src='http://http://www.example.com/image.jpg'></a></td>
echo "<td><a target='_blank' href='" . $cell ."'><img src='" . $cell ."'></a></td>";
break;
default:
echo "<td>$cell</td>";
echo "</tr>\n";
}
mysql_free_result($result);
If you know the columns that you are going to be accessing and you know which column is the url, then you can use the following mysqli_-based code block with a condition in the inner loop to check for the matching column name.
If you don't know the columns that you will be dealing with, you can use filter_var($val, FILTER_VALIDATE_URL) assuming you only have one url string in your resultset. If you go for this second option, the one side effect on my code block is that you would have re-engineer the <th> portion.
I refuse to write answers using mysql_ functions, so please take this chance to modernize your code. I've included the connection declaration and basic error checking for your debugging convenience. (Never display error messages on your public site.)
Untested Code:
$columns = ['sometext', 'urlvalue', 'somemoretext'];
if (!$mysqli = new mysqli("localhost", "my_user", "my_password", "my_db")) {
echo "Database Connect Error: " , $mysqli->connect_error;
} elseif (!$result = $mysqli->query("SELECT `" . implode('`, `', $columns) . "` FROM `Table`")) {
echo "Query Syntax Error: " , $mysqli->error;
if (!$result->num_rows) {
echo "No Rows Found";
} else {
echo "<table border='1'>";
echo "<tr bgcolor='yellow' align='left'>";
echo "<th>" , implode("</th><th>", $columns) , "</th>";
echo "</tr>";
while ($row = $result->fetch_assoc()) {
echo "<tr>";
foreach ($row as $col => $val) {
echo "<td>";
if ($col == 'urlvalue') { // or if (filter_var($val, FILTER_VALIDATE_URL)) {
echo "<a target='_blank' href='$val'><img src='$val'></a>";
} else {
echo "$val";
}
echo "</td>";
}
echo "</tr>";
}
echo "</table>";
}
}
I am not completely sure what you mean but rather than referencing the field number just reference the name.
if ($result->num_rows > 0) {
echo "<table border='1'><tr bgcolor='yellow' align='left'>";
while($row = $result->fetch_assoc()) {
echo "<th>".$row['field-name']."</th>";
echo "<tr>";
echo "<td><a target='_blank' href='" . $row['field-name'] ."'><img src='" . $row['field-name'] ."'>
</a>
</td>";
echo "</tr>";
}
echo "</table>";
}

php - how to exclude a line of code in a loop

I have a code in HTML in a table. And I want the loop to just ignore them
<?php
$sel_admin = "query ";
$rs_admin = mysql_query($sel_admin);
while($row = mysql_fetch_array($rs_admin))
{
echo "<th>". $row['a']. "</th>";
</thead> // This two line of code
<tbody> // is the one I want to exclude in the while loop
$sel_admin2 = "query2 ";
$rs_admin2 = mysql_query($sel_admin2);
while($row2 = mysql_fetch_array($rs_admin2))
{
echo" <tr class='gradeX'> ";
echo "<td>" . $row2['sched3_time']. "</td>";
echo"</tr>";
}
}
?>
Is this even possible?
You need to end your first loop, spit out the html and then start the loop again, havent tested but i think the below should now work.
<?php
$sel_admin = "query ";
$rs_admin = mysql_query($sel_admin);
while ($row = mysql_fetch_array($rs_admin)) {
echo "<th>" . $row['a'] . "</th>";
}
?>
</thead>
<tbody>
<?php
$sel_admin2 = "query2 ";
$rs_admin2 = mysql_query($sel_admin2);
while ($row2 = mysql_fetch_array($rs_admin2)) {
echo " <tr class='gradeX'> ";
echo "<td>" . $row2['sched3_time'] . "</td>";
echo "</tr>";
}
?>
I'm guessing you want those lines printed once, not to be outside the loop, per se. You could use a variable to track it:
$linesNeeded = true;
while (...) {
...
if ($linesNeeded) {
echo $line1;
echo $line2;
$linesNeeded = false;
}
...
}
Please use mysqli instead of mysql. Take a look: MySQL vs MySQLi when using PHP
+
Your problem's answer too.
<?php
$sel_admin = "query ";
$rs_admin = mysqli_query($connection,$sel_admin);
while($row = mysqli_fetch_array($rs_admin))
{
echo "<th>". $row['a']. "</th>";
?>
</thead>
<tbody>
<?php
$sel_admin2 = "query2 ";
$rs_admin2 = mysqli_query($connection, $sel_admin2);
while($row2 = mysqli_fetch_array($rs_admin2))
{
echo" <tr class='gradeX'> ";
echo "<td>" . $row2['sched3_time']. "</td>";
echo"</tr>";
}
}
?>
This is honestly just a guess but based on the code you provided you actually need to add more code after remove the code you do not want:
<?php
$sel_admin = "query ";
$rs_admin = mysql_query($sel_admin);
while($row = mysql_fetch_array($rs_admin))
{
echo "<tr><th>". $row['a']. "</th></tr>"; // Notice the <tr></tr>
$sel_admin2 = "query2 ";
$rs_admin2 = mysql_query($sel_admin2);
while($row2 = mysql_fetch_array($rs_admin2))
{
echo" <tr class='gradeX'> ";
echo "<td>" . $row2['sched3_time']. "</td>";
echo"</tr>";
}
}
?>

Limiting column for fetched data in php

I am trying to put extracted mysql data into a table using php. The issue is that I am able to put the fetched data into either all rows or all columns. What I would like to do is put the fetched data into a column format and as soon as 4 columns are used, the next data should start on the next row and so on.
Currently I am using the logic below, however I am getting everything in a column.
The goal is to limit the data to a page size so the data can be printed.
<div>
$result = mysql_query("SELECT * FROM master_data");
echo "<table border='1'>
<tr>
<th>Accounts</th>
</tr>";
echo "<tr>";
while($row = mysql_fetch_array($result))
{
echo "<td>";
echo "First Name:" . $row['First_Name'] . "</br>";
echo "Middle Name:" . $row['Middle_Name'] . "</br>";
echo "Last Name:" . $row['Last_Name'] . "</br>";
echo "</td>";
}
echo "</tr>";
echo "</table>";
mysql_close($con);
?></div>
If I understand your problem correctly you will want to do something like:
Keep a counter to see which number record you're looking at ($i)
$i = 0; // Your counter
while($row = mysql_fetch_array($result))
{
// ...
On every 4th iteration of the loop output something like </tr><tr>.
if ($i % 4 == 0 && $i > 0) // Will return true if `$i` is a multiple of 4 and greater than 0
{
echo "</tr><tr>"; // Output your HTML to start a new row
}
One final note: As others will be pointing out. You should avoid using the MySQL extension. You should use MySQLi or PDO instead.
<div>
$result = mysql_query("SELECT * FROM master_data");
echo "<table border='1'>
<tr>
<th>Accounts</th>
</tr>";
echo "<tr>";
$i = 1;
while($row = mysql_fetch_array($result))
{
if($i == 4)
{
echo "<td>";
echo "First Name:" . $row['First_Name'] . "</br>";
echo "Middle Name:" . $row['Middle_Name'] . "</br>";
echo "Last Name:" . $row['Last_Name'] . "</br>";
echo "</td>";
$i=0;
}
$i++;
}
echo "</tr>";
echo "</table>";
mysql_close($con);
?>
</div>

Retrieve data from sql database and display in tables - Display certain data according to checkboxes checked

I have created an sql database(with phpmyadmin) filled with measurements from which I want to call data between two dates( the user selects the DATE by entering in the HTML forms the "FROM" and "TO" date) and display them in a table.
Additionally I have put, under my html forms, some checkboxes and by checking them you can restrict the amount of data displayed.
Each checkbox represent a column of my database; so along with the date and hour column, anything that is checked is displayed(if none is checked then everything is displayed).
So far I managed to write a php script that connects to the database, display everything when none of my checkboxes is checked and also managed to put in order one of my checkboxes.
Problem: The data that I call for are been displayed twice.
Question: I want to have four checkboxes.
Do I need to write an sql query for every possible combination or there is an easier way?
<?php
# FileName="Connection_php_mysql.htm"
# Type="MYSQL"
# HTTP="true"
$hostname_Database_Test = "localhost";
$database_Database_Test = "database_test";
$table_name = "solar_irradiance";
$username_Database_Test = "root";
$password_Database_Test = "";
$Database_Test = mysql_pconnect($hostname_Database_Test, $username_Database_Test, $password_Database_Test) or trigger_error(mysql_error(),E_USER_ERROR);
//HTML forms -> variables
$fromdate = $_POST['fyear'];
$todate = $_POST['toyear'];
//DNI CHECKBOX + ALL
$dna="SELECT DATE, Local_Time_Decimal, DNI FROM $database_Database_Test.$table_name where DATE>=\"$fromdate\" AND DATE<=\"$todate\"";
$tmp ="SELECT * FROM $database_Database_Test.$table_name where DATE>=\"$fromdate\" AND DATE<=\"$todate\"";
$entry=$_POST['dni'];
if (empty($entry))
{
$result = mysql_query($tmp);
echo
"<table border='1' style='width:300px'>
<tr>
<th>DATE</th>
<th>Local_Time_Decimal</th>
<th>Solar_time_decimal</th>
<th>GHI</th>
<th>DiffuseHI</th>
<th>zenith_angle</th>
<th>DNI</th>
";
while( $row = mysql_fetch_assoc($result))
{
echo "<tr>";
echo "<td>" . $row['DATE'] . "</td>";
echo "<td>" . $row['Local_Time_Decimal'] . "</td>";
echo "<td>" . $row['Solar_Time_Decimal'] . "</td>";
echo "<td>" . $row['GHI'] . "</td>";
echo "<td>" . $row['DiffuseHI'] . "</td>";
echo "<td>" . $row['Zenith_Angle'] . "</td>";
echo "<td>" . $row['DNI'] . "</td>";
echo "</tr>";
}
echo '</table>';}
else
{
$result= mysql_query($dna);
echo
"<table border='1' style='width:300px'>
<tr>
<th>DATE</th>
<th>Local_Time_Decimal</th>
<th>DNI</th>
";
while($row = mysql_fetch_assoc($result))
{
echo "<tr>";
echo "<td>" . $row['DATE'] . "</td>";
echo "<td>" . $row['Local_Time_Decimal']."</td>";
echo "<td>" . $row['DNI'] . "</td>";
echo "</tr>";
}
echo '</table>';
}
if($result){
echo "Successful";
}
else{
echo "Enter correct dates";
}
?>
<?php
mysql_close();
?>
Try to create your checkbox like below:
Solar_Time_Decimal<checkbox name='columns[]' value='1'>
GHI<checkbox name='columns[]' value='2'>
DiffuseHI<checkbox name='columns[]' value='3'>
Zenith_Angle<checkbox name='columns[]' value='4'>
DNI<checkbox name='columns[]' value='5'>
And try to hange your PHP code to this:
<?php
//HTML forms -> variables
$fromdate = isset($_POST['fyear']) ? $_POST['fyear'] : data("d/m/Y");
$todate = isset($_POST['toyear']) ? $_POST['toyear'] : data("d/m/Y");
$all = false;
$column_names = array('1' => 'Solar_Time_Decimal', '2'=>'GHI', '3'=>'DiffuseHI', '4'=>'Zenith_Angle','5'=>'DNI');
$column_entries = isset($_POST['columns']) ? $_POST['columns'] : array();
$sql_columns = array();
foreach($column_entries as $i) {
if(array_key_exists($i, $column_names)) {
$sql_columns[] = $column_names[$i];
}
}
if (empty($sql_columns)) {
$all = true;
$sql_columns[] = "*";
} else {
$sql_columns[] = "DATE,Local_Time_Decimal";
}
//DNI CHECKBOX + ALL
$tmp ="SELECT ".implode(",", $sql_columns)." FROM $database_Database_Test.$table_name where DATE>=\"$fromdate\" AND DATE<=\"$todate\"";
$result = mysql_query($tmp);
echo "<table border='1' style='width:300px'>
<tr>
<th>DATE</th>
<th>Local_Time_Decimal</th>";
foreach($column_names as $k => $v) {
if($all || (is_array($column_entries) && in_array($k, $column_entries)))
echo "<th>$v</th>";
}
echo "</tr>";
while( $row = mysql_fetch_assoc($result))
{
echo "<tr>";
echo "<td>" . $row['DATE'] . "</td>";
echo "<td>" . $row['Local_Time_Decimal'] . "</td>";
foreach($column_names as $k => $v) {
if($all || (is_array($column_entries) && in_array($k, $column_entries))) {
echo "<th>".$row[$v]."</th>";
}
}
echo "</tr>";
}
echo '</table>';
if($result){
echo "Successful";
}
else{
echo "Enter correct dates";
}
?>
<?php
mysql_close();?>
This solution consider your particular table columns but if your wish a generic solution you can try to use this SQL too:
$sql_names = "SELECT COLUMN_NAME FROM INFORMATION_SCHEMA.COLUMNS WHERE TABLE_SCHEMA = '$database_Database_Test' AND TABLE_NAME = '$table_name'";
and use the result to construct the $column_names array.
Solution for your problem : Change the mysql_fetch_assoc with mysql_fetch_array
If you have the same problem try to print your result with print_r
Answer : Use the bit datatype in mysql for store and read your checkboxes.
When you're receiving thr value from the database then you can use
in the parameter checked you can use the php code as exist :
$value = ...get the value from db ( 1 or 0 )
echo '<input type="checkbox" name="thename" value="thevalue" '.($value==1?'checked=checked'.'').'/>';

Display result from database in two columns

EDIT: This is what I am trying to achieve: http://i.imgur.com/KE9xx.png
I am trying to display the results from my database in two columns. I'm a bit new to PHP so I haven't the slightest clue on how to do this. Can anybody help me with this? Thanks in advance.
Here is my current code:
include('connect.db.php');
// get the records from the database
if ($result = $mysqli->query("SELECT * FROM todo ORDER BY id"))
{
// display records if there are records to display
if ($result->num_rows > 0)
{
// display records in a table
echo "<table width='415' cellpadding='0' cellspacing='0'>";
// set table headers
echo "<tr><td><img src='media/title_projectname.png' alt='Project Name' /></td>
<td><img src='media/title_status.png' alt='Status'/></td>
</tr>";
echo "<tr>
<td><div class='tpush'></div></td>
<td> </td>
</tr>"
while ($row = $result->fetch_object())
{
echo "<tr>";
echo "<td><a href='records.php?id=" . $row->id . "'>" . $row->item . "</a></td>";
echo "<td>" . $row->priority . "</td>";
echo "</tr>";
}
echo "</table>";
}
// if there are no records in the database, display an alert message
else
{
echo "No results to display!";
}
}
// show an error if there is an issue with the database query
else
{
echo "Error: " . $mysqli->error;
}
// close database connection
$mysqli->close();
A good idea would be storing your data into a simple array and then display them in a 2-columned table like this:
$con = mysql_connect('$myhost', '$myusername', '$mypassword') or die('Error: ' . mysql_error());
mysql_select_db("mydatabase", $con);
mysql_query("SET NAMES 'utf8'", $con);
$q = "Your MySQL query goes here...";
$query = mysql_query($q) or die("Error: " . mysql_error());
$rows = array();
$i=0;
// Put results in an array
while($r = mysql_fetch_assoc($query)) {
$rows[] = $r;
$i++;
}
//display results in a table of 2 columns
echo "<table>";
for ($j=0; $j<$i; $j=$j+2)
{
echo "<tr>";
echo "<td>".$row[$j]."</td><td>".$row[$j+1]."</td>";
echo "</tr>";
}
echo "</table>";
mysql_close($con);
<table>
<tr>
<td>ProjectName</td>
<td>Status</td>
<td>ProjectName</td>
<td>Status</td>
</tr>
<?php
while($row = $result->fetch_object()) {
echo "<tr>";
echo "<td>".$row->ProjectName."</td>";
echo "<td>".$row->Status."</td>";
echo "<td>".$row->ProjectName."</td>";
echo "<td>".$row->Status."</td>";
echo "</tr>";
}
?>
</table>
This is the thing on picture. With a bit CSS you can manipulate the tds.
Your function should look similar to this:
$query = "SELECT *
FROM todo
ORDER BY id";
$result = $mysqli->query($query);
while($row = $result -> fetch_array()) {
$feedback .= "<tr>\n<td>" . $row['item'] . "</td><td>" . $row['priority'] . "</td>\n</tr>";
}
return $feedback;
Then, in your HTML have the <table> already setup and where you would normally insert your <td> and <tr> put <?php echo $feedback?> (where $feedback is the assumed variable on the HTML page that retrieves the $feedback from the function). This isn't a complete fix, your code is hard to read, but by starting here, you should be able to continue on the path filling in all the extra information you need for the table, including your CSS.

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