Highlighting MySQL Data Results - php

Question

I'm going to struggle to explain this.. so please feel free to ask for more information.
I'm reading data from a MySQL DB Using :
SELECT * FROM resource where date > DATE_SUB(now(), INTERVAL 12 MONTH) ORDER BY `date` DESC
This produces results like this :
ID DATE STACK REF NAME LOCATION CREW
9 2016-01-01 06:34:50 A6YH75F 12 Local List SPAIN 1A
8 2016-01-01 06:34:48 QWE343 23 POINT ONE GERMANY 3A
7 2016-01-01 06:34:46 WER342 43 Insite UK 4A
6 2016-01-01 06:34:44 WFF5G1 34 LANWise FRANCE 5A
5 2016-01-01 06:34:42 2D3D35 21 Polent USA 7A
4 2016-01-01 06:34:40 8541FW 33 Rosta UK 4B
3 2015-12-30 16:48:23 A6YH75F 12 Local List SPAIN 2A
2 2015-11-21 14:32:01 FFCWF4 34 LANWISE FRANCE 6A
1 2015-10-14 11:02:22 POI8H6 75 BALAND IRELAND 6B
This is where it's hard to explain.
I'm looping through the results and echoing out the results into a <table>
When this is live there may appear hundreds of entries for each NAME, what I want to do it highlight output based on some specific criteria.
For example:
If a NAME appears multiple times, compare the latest and previous values of STACK & REF for that name. (so comparing the last two entries per name)
If they are different highlight the output for that entry.
ie:
I can see Local List appears twice in the list. The first date stamp is 2016-01-01 06:34:50 & then at 2015-12-30 16:48:23
Thats fine. On both occasions the STACK and REF are the same.
However LANWISE also appears twice but it's STACK is different on the newer occasion. How do I flag this and highlight the LATEST Entry for LANWISE.
I'm also looking to see if an entry hasn't appeared in the last 65 days.
So looking at the list BALAND last appeared 2015-10-14 11:02:22 so this is greater than 65 days and they haven't appeared since. How do I highlight this ?
Thanks

Answer 1

You can use the following query that returns all of the information required in order to determine records that need to be highlighted:
SELECT ID, `DATE`, STACK, REF, NAME, LOCATION, CREW,
--Calculate difference between `DATE` field and current date
DATEDIFF(NOW(), `DATE`) AS DaysDiff,
-- Get the count of newer records having the same NAME
COALESCE((SELECT COUNT(*)
FROM resource AS r2
WHERE r2.NAME = r1.NAME AND r2.`Date` > r1.`Date`), 0) CountNewer,
-- Find wether an older record exists having the same NAME and
-- different REF or STACK or both
COALESCE((SELECT 1
FROM resource AS r3
WHERE r3.NAME = r1.NAME AND
r3.`Date` < r1.`Date` AND
(r3.REF <> r1.REF OR r3.STACK <> r1.STACK)), 0) IsHighlighted
FROM resource AS r1
WHERE date > DATE_SUB(now(), INTERVAL 12 MONTH)
ORDER BY `date` DESC

Answer 2

I don't know if it's the best way, but I do something like that ($variable is the result of your query)
$already = array();
#The loop where you make your table. I use foreach but use your current loop (probably while if you fetch a query response) :
foreach ($variable as $key => $value) {
$class='';
if(isset($already[$value['name']]) && $already[$value['name']] == $value['date']) {
$class='highlight';
}
#The next time, the variable exist :
$already[$value['name']] = $value['date'];
#do your stuf and add $class to your class in your HTML (and do something inyour CSS)
}
With the isset($already[$value['name']]) you know if the line existing before. And with the == comparator, you know if it's the same value.
Use CSS and class HTML attribute for Highlighting the concerned lines.
Adapt this code for your usage, it's just an example based of your post.
For compare date, you can use DateTime. Example of use :
$datetime1 = new DateTime($xDateDebut[2].'-'.$xDateDebut[1].'-'.$xDateDebut[0]);
$datetime3 = new DateTime(date('Y').'-'.date('m').'-'.date('d'));
$delaisAvantJourJ = $datetime1->diff($datetime3);
($xDateDebut is an explosed SQL date field)
$delaisAvantJourJ is now an object with a lot of usefull information (like the number of day diff)