I have same div multiple times.If I click on 'Mr' radio button in first div field should change last div radio button value as 'male' Here my code.It is changing all div values as 'male'.How do I change related form Gender radio button value when clicking the title radio button.Please anybody help me.
<?php
for($i=1;$i<=$totalchilds;$i++){
?>
<div class="primary Applicant-details">
<h3>Tourist Details </h3>
<div>
<label>Title : </label>
<input type="radio" class="gender" name="c_genderinfo_<?=$i?>" value="Mr" checked>
Mr
<input type="radio" class="gender1" name="c_genderinfo_<?=$i?>" value="Mrs">
Mrs </div>
<div>
<label for="fname">Name</label>
<input type="text" name="c_name_<?= $i ?>" placeholder="child name">
</div>
<div>
<label for="lname">Age</label>
<input type="text" name="c_age_<?=$i?>" placeholder="Enter child age">
</div>
<div>
<label>Gender : </label>
<input type="radio" class="gender" name="c_gender_<?=$i?>" value="M" checked>
Male
<input type="radio" class="gender1" name="c_gender_<?=$i?>" value="F">
Female </div>
</div>
<?php }?>
To change the gender radio button in the same div use this code:
$('.gender').click(function(){
$(this).closest('.Applicant-details').find('.gender').prop('checked',true);
});
$('.gender1').click(function(){
$(this).closest('.Applicant-details').find('.gender1').prop('checked',true);
});
The structure of the code isn't very optimal. Rename the title from gender to title. Naming the radio buttons gender and gender1 isn't any better. Besides, from a usability perspective, having both selections that have the same value doesn't make a lot of sense.
You can use jQuery. There are different methods to achieve this. This is one of them.
Pass your id and value from html like this:
<div>
<label>Title : </label>
<input onclick="changeGender(<?=$i?>, 'M')" type="radio" class="gender" name="c_genderinfo_<?=$i?>" value="Mr" checked>
Mr
<input onclick="changeGender(<?=$i?>, 'F')" type="radio" class="gender1" name="c_genderinfo_<?=$i?>" value="Mrs">
Mrs
</div>
And in script:
function changeGender(id, value)
{
$("input[name=c_gender_"+id+"][value=" + value + "]").prop('checked', true);
}
Related
my question is how can I keep the radio button checked after I miss filling one of the form fields?
I have a form for the admin to fill out to add a user, I have 3 radio buttons to choose user type, and of course, the rest of the form: user name, age, etc. when the user misses filling one of the fields and click submit, the filled information stay but the radio button get back to the old selection. how can I keep the new selection when correcting the form?
this is my code
نوع المستخدم
مدير
<input class="margin-radio" type="radio" value="clerk" name="usertype"> مساعد مدير
<input class="margin-radio" type="radio" value="client" name="usertype"> عميل
</div>
<!-- ------------- -->
<div class="all-input">
<label for="">الاسم الاول:</label>
<input type="text" name="firstname" value="<?php if(isset($_POST['firstname'])) echo $_POST['firstname'];?>" required>
</div>
<!-- ------------ -->
<div class="all-input">
<label for="">الاسم الأخير:</label>
<input type="text" name="lastname" value="<?php if(isset($_POST['lastname'])) echo $_POST['lastname'];?>" required>
</div>
<!-- ------ -->
<div class="all-input">
<label for="">البريد الالكتروني:</label>
<input type="email" name="email" value="<?php if(isset($_POST['email'])) echo $_POST['email'];?>" required>
You can use the Checked attribute of the <input type="radio"
For example:
<input type="radio" name="foo" value="bar" <?php if(isset($_POST['foo']) && $_POST['foo'] == 'bar') echo 'checked="checked"'; ?>>
This method also works for the type="checkbox" In that case you would need to iterate over the array of possible values.
I am creating a quiz application...
I have created a question text area, and a number of input fields for options..
Each input field has a radio button, if user clicks it, it will consider the associated input field as correct answer..
I have created some input fields and radio button with each input field
<div id="items">
<input class="form-control" type="text" name="options[]" required /> Is Correct: <input type="radio" name="is_correct" value="yes"/> <br><br>
<input class="form-control" type="text" name="options[]" required /> Is Correct: <input type="radio" name="is_correct" value="yes"/>
</div>
when i Submit this form it stores yes with each Option. I am unable to understand how to store the value of only 1 input field.
Kindly guide me
Thanks.
if you get value of options is input1 answer is input1 or if options value is input2 answer is input2
<input type="radio" name="options" value="input1">Is Correct<br>
<input type="radio" name="options" value="input2">Is Correct
input1 is name of textbox 1
input2 is name of textbox 2
Get value on form post :-
$nam=$_POST['options'];
$answer=$_POST[$nam];
You can use input as below :
<div id="items">
<input class="form-control" type="text" name="options[]" required /> Is Correct: <input type="radio" name="is_correct[]" value="yes"/> <br><br>
<input class="form-control" type="text" name="options[]" required /> Is Correct: <input type="radio" name="is_correct[]" value="yes"/>
</div>
For my app I need to fetch the data from the database and mark fields accordingly. I am stuck with how to mark the radio button based on the value fetched. I am sharing the code I wrote to fetch the data and the radio button which I need to check.
$Medical_Record_Id=$_SESSION['Medical_Record_Id'];
$DOL=$_SESSION['DOL'];
$hour=$_SESSION['hour'];
$Question1="xxx";
$data1 = 'SELECT Option_Selected FROM Form1 WHERE Medical_Record = "'.$Medical_Record_Id.'" and DOL="'.$DOL.'" and hour="'.$hour.'" and Question="'.$Question1.'"' ;
$query = mysql_query($data1) or die("Couldn't execute query. ". mysql_error());
The html code which I have for the radio button is
<div>
<span>
<input type="radio" name="Gestational_age" class="field checkbox" value="<28" tabindex="7" />
<label class="choice" for="Gestational_age"><28</label>
</span>
<span>
<input type="radio" name="Gestational_age" class="field checkbox" value="28-31" tabindex="7" />
<label class="choice" for="Gestational_age">28-31</label>
</span>
<span>
<input type="radio" name="Gestational_age" class="field checkbox" value=">=32" tabindex="7" />
<label class="choice" for="Gestational_age">>=32</label>
</span>
</div>
Please guide me in how to check the radio button based on the value I am fetching in $query .
First of all, your HTML is really messed up. If you want to use symbols such as >, < in HTML attribute values or as text to display in the labels, you should convert them to the respective HTML entities, e.g., <, >.
After that, if you need to mark a value as selected, you should use the checked attribute on the specific <input> control:
<input type="radio" checked="checked" .... >
In order to show your input checked put some like below, see the second input
<form>
<input type="radio" name="Gestational_age" class="field checkbox" value="<28" tabindex="7">
<input type="radio" name="Gestational_age" class="field checkbox" value="28-31" tabindex="7" checked="checked">
<input type="radio" name="Gestational_age" class="field checkbox" value=">=32" tabindex="7">
</form>
I have a database with pictures that i can delete from or use them in different parts of the the website by choosing one of the radio buttons in the popup.Problem is everytime I click I click on a picture the name of the first picture in the database comes up not the one from the picture i clicked . What's wrong? I used PHP 5.3 and HeidiSQL
<?php
// ...
$result=mysql_query("SELECT * FROM imagini WHERE menu_id=6");
while($data=mysql_fetch_row($result)){ ?>
<div class="tag">
<div id='container_poze_originale'>
Alege alt rol
<div id="my_popup" style="display:none;border:1px dotted gray;padding:.3em;background-color:white;position:absolute;width:auto;left:100px;top:100px">
close
<form action="popup.php" method="post" >
<input type="text" name="alt-rol" value="<?php echo $data[1];?>" /> //always returns the name of the first picture in the database not the one i select
<input type="submit" value="Adauga imagine" class="buton_imagine" />
<div class="radio">
<input type="radio" name="tip_imagine" value="0"/><label for="tip_imagine" class="radio2">Logo</label>
<input type="radio" name="tip_imagine" value="1"/><label for="tip_imagine" class="radio2">Slider</label>
<input type="radio" name="tip_imagine" value="2"/><label for="tip_imagine" class="radio2">Hot destinations</label>
<input type="radio" name="tip_imagine" value="3"/><label for="tip_imagine" class="radio2">Pachete</label>
<input type="radio" name="tip_imagine" value="4"/><label for="tip_imagine" class="radio2">Reclama</label>
<input type="radio" name="tip_imagine" value="5"/><label for="tip_imagine" class="radio2">Background</label>
</div>
</form>
</div>
<div class="imagine_originala">
<img src= "../upload/original/<?php echo $data[1];?>" /></a>
</div>
<div class="Btag" style="display:none;">
<div id="buton_slide4" >
Sterge</td>
</div>
</div>
</div>
</div>
<?php
}
?>
I think I understand your question. You are clicking on
Alege alt rol
and you are surprised that the same <div> always appears?
Well, it is simply because an id should be unique. And if you cycle through your images you create a new <div> each time with the same id: my_popup. When clicking on the link (no matter which one), JavaScript will then just take the first <div> it finds with the id my_popup. So you should just assign an unique id to each div so your JavaScript knows which one to open. You could do this by appending your image id to the div id (assuming you have a unique image id in $data[1]).
So change it to (shortened):
<? while($data=mysql_fetch_row($result)) { ?>
<div class="tag">
<div id="container_poze_originale">
Alege alt rol
<div id="my_popup<?=$data[1]?>" style="display:none;border:1px dotted gray;padding:.3em;background-color:white;position:absolute;width:auto;left:100px;top:100px">
...
</div>
</div>
</div>
<? } ?>
Oh and it might be good to put all those huge inline CSS attributes into an external stylesheet, so it will be easier to maintain/change your webpage later on. And it makes things a bit more readable... :-)
I think your form is ok when you click on the radio but not when you click on the label.
The for attribute of the label need an ID as reference like this :
<input type="radio" name="tip_imagine" value="0" id="tip0" /><label for="tip0" class="radio2">Logo</label>
<input type="radio" name="tip_imagine" value="1" id="tip1"/><label for="tip1" class="radio2">Slider</label>
<input type="radio" name="tip_imagine" value="2" id="tip2"/><label for="tip2" class="radio2">Hot destinations</label>
<input type="radio" name="tip_imagine" value="3" id="tip3"/><label for="tip3" class="radio2">Pachete</label>
<input type="radio" name="tip_imagine" value="4" id="tip4"/><label for="tip4" class="radio2">Reclama</label>
<input type="radio" name="tip_imagine" value="5" id="tip5"/><label for="tip5" class="radio2">Background</label>
With your actual code, the FOR is always the same so you get always the first.
I currently have a form with lets say 5 radio button entries (see below).
What im looking archive is the following:
- Being able to choose multiple radio buttons - lets say 3 and submit the form.
Currently I got it working fine with PHP, SQL, but im only able to choose one radiobutton and submit that.
I figure it would also come in handy being able to deselect a radio button in case you wrongly click one.
My guess is that this can be done through some javascript? Any suggestions? Online examples perhaps?
<form id="pollform" action="poll.php" method="post">
<input id="option-1" type="radio" value="1" name="poll">
<label for="option-1">Select option 1</label>
<input id="option-2" type="radio" value="2" name="poll">
<label for="option-2">Select option 2</label>
<input id="option-3" type="radio" value="3" name="poll">
<label for="option-3">Select option 3</label>
<input id="option-4" type="radio" value="4" name="poll">
<label for="option-4">Select option 4</label>
<input id="option-5" type="radio" value="5" name="poll">
<label for="option-5">Select option 5</label>
</form>
Radio buttons are designed so that only one option from each group (as designated by their shared name) can be selected at once (just like you can only tune a radio to one station).
The input control which allows any number of options to be selected is the checkbox. If you append [] to their names, then the selected options will arrive on the PHP side as an array.
<input type="checkbox" value="1" name="poll[]" />
<input type="checkbox" value="2" name="poll[]" />
As it has same name poll you will not be able to do that as input type radio is specialized in selecting a single value from multiple inputs.
You can use input type checkbox for that and make them as an array:
<form id="pollform" action="poll.php" method="post">
<input id="option-1" type="checkbox" value="1" name="poll[]">
<label for="option-1">Select option 1</label>
<input id="option-2" type="checkbox" value="2" name="poll[]">
<label for="option-2">Select option 2</label>
<input id="option-3" type="checkbox" value="3" name="poll[]">
<label for="option-3">Select option 3</label>
<input id="option-4" type="checkbox" value="4" name="poll[]">
<label for="option-4">Select option 4</label>
<input id="option-5" type="checkbox" value="5" name="poll[]">
<label for="option-5">Select option 5</label>
</form>
LIMIT (with jQuery) the number:
$("input[type=checkbox][name=poll[]]").click(function() {
var numberSel = $("input[type=checkbox][name=poll[]]:checked").length >= 3;
$("input[type=checkbox][name=poll[]]").not(":checked").attr("disabled",numberSel);
});
Radio buttons are designed for only 1 item to be selected, use checkboxes instead.