I would want to display a plus sign between my do while loop result as illustrated below:
If i get two results i would want it to display as e.g. 46+56 and if three results 45+76+89.
Where do i place the plus sign + so that it does not display at the ends?
<?php do { ?>
+ <?php echo $row_studentcat['marks']; ?>
<?php } while ($row_studentcat = mysql_fetch_assoc($studentcat)); ?>
The code above would display result as +45+56 but i would want it to display as 45+56
Any help..
You should use the ltrim() function instead:
echo ltrim($s,'+');
Otherwise, rtrim() will do the same right hand side
For removing + sign from starting (left side), you can use ltrim() function:
Example:
$Yourstring = '+45+10';
echo ltrim($Yourstring,'+'); //45+10
Second param of Function ltrim() will remove the starting + from your string.
From PHP Manual:
ltrim — Strip whitespace (or other characters) from the beginning of a
string
I would implode the data so I can store the data from the other columns in other variables.
$marks = array();
while($row = mysql_fetch_assoc($studentcat)) {
$marks[] = $row['marks'];
}
echo implode('+', $marks);
This is very simple my friend, use php JOIN()...
<?php
$marksArray= array()l
while ($row_studentcat = mysql_fetch_assoc($studentcat))
{
$marksArray[] = $row_studentcat['marks'];
}
echo join('+',$marksArray);
?>
The faster way is concatenating the elements into a string and delete the first + using this method:
substr($string, 1);
Comparing with implode is 3 times faster and comparing with ltrim is a little bit faster because we only change the index array in this case, which is faster than remove an element
Furthermore, I would like to comment you two important issues of this code:
In case mysql_fetch_assoc returns you an empty result you will have an error, because you will try to access to an unexisting index array, better use while(){}
The method mysql_fetch_assoc is deprecated and is removed in PHP7, your code will have problems in the future: http://php.net/manual/es/function.mysql-fetch-assoc.php
Related
sorry if my question was stupid, please someone help me to fix this issue.
i have string like
$str_value = "http://99.99.99.99/var/test/src/158-of-box.html/9/";
this $str_value is dynamic , it will change each page. now i need to replace 9 in this string as 10. add integer 1 and replace
for example if the $str_value = "http://99.99.99.99/var/test/src/158-of-box.html/251/"
then output should be
http://99.99.99.99/var/test/src/158-of-box.html/252/
i tried to replace using preg_match but i m getting wrong please somesone help me
$str = preg_replace('/[\/\d+\/]/', '10',$str_value );
$str = preg_replace('/[\/\d+\/]/', '[\/\d+\/]+1',$str_value );
Thank's for the answer, #Calimero! You've been faster than me, but I would like to post my answer, too ;-)
Another possibilty is to fetch the integer by using a group. So you don't need to trim $matches[0] to remove the slashes.
$str_value = "http://99.99.99.99/var/test/src/158-of-box.html/9/";
$str = preg_replace_callback('/\/([\d+])\//', function($matches) {
return '/'.($matches[1]+1).'/';
}, $str_value);
echo $str;
You need to use a callback to increment the value, it cannot be done directly in the regular expression itself, like so :
$lnk= "http://99.99.99.99/var/test/src/158-of-box.html/9/";
$lnk= preg_replace_callback("#/\\d+/#",function($matches){return "/".(trim($matches[0],"/")+1)."/";},$lnk); // http://99.99.99.99/var/test/src/158-of-box.html/10/
Basically, the regexp will capture a pure integer number enclosed by slashes, pass it along to the callback function which will purge the integer value, increment it, then return it for replacement with padded slashes on each side.
I'd suggest also another approach based on explode and implode instead of doing any regexp stuff. In my opinion this is more readable.
$str_value = "http://99.99.99.99/var/test/src/158-of-box.html/11/";
// explode the initial value by '/'
$explodedArray = explode('/', $str_value);
// get the position of the page number
$targetIndex = count($explodedArray) - 2;
// increment the value
$explodedArray[$targetIndex]++;
// implode back the original string
$new_str_value = implode('/', $explodedArray);
I'm trying to retrieve 4119850115 from the below number but i could not extract it properly
<?php
$num=1000014119850115;
if(strlen($num)>6){
$num = substr(($num), 6);
}
echo $num;
?>
the above code gives me 4119850100
but when i assign value to $num as below
$num='1000014119850115';
i get 4119850115 which is what i wanted but,
the number is generated dynamically and when i try to add single quotes to it like
$num=1000014119850115;
$num="'".$num."'";
even tried strval() and (string) to convert
its not working it gives 4119850100
can any one help me out with this . was checking this code in codepad.
thanks in advance.
In PHP you don't have to put single or double quotes around a number.
If you put quotes PHP considers a string.
Go to see the PHP documentation about the type juggling, I think it will resolve your problem.
Try this and see if it's works :
echo (int)$num;
echo (string)$num;
Try this:
$num = '1000014119850115';
$num = sunstr ($num,6);
$num = intval ($num);
Get substring first then convert it to int.
I am trying to use a License PHP System…
I will like to show the status of their license to the users.
The license Server gives me this:
name=Service_Name;nextduedate=2013-02-25;status=Active
I need to have separated the data like this:
$name = “Service_Name”;
$nextduedate = “2013-02-25”;
$status = “Active”;
I have 2 days tring to resolve this problem with preg_match_all but i cant :(
This is basically a query string if you replace ; with &. You can try parse_str() like this:
$string = 'name=Service_Name;nextduedate=2013-02-25;status=Active';
parse_str(str_replace(';', '&', $string));
echo $name; // Service_Name
echo $nextduedate; // 2013-02-25
echo $status; // Active
This can rather simply be solved without regex. The use of explode() will help you.
$str = "name=Service_Name;nextduedate=2013-02-25;status=Active";
$split = explode(";", $str);
$structure = array();
foreach ($split as $element) {
$element = explode("=", $element);
$$element[0] = $element[1];
}
var_dump($name);
Though I urge you to use an array instead. Far more readable than inventing variables that didn't exist and are not explicitly declared.
It sounds like you just want to break the text down into separate lines along the semicolons, add a dollar sign at the front and then add spaces and quotes. I'm not sure you can do that in one step with a regular expression (or at least I don't want to think about what that regular expression would look like), but you can do it over multiple steps.
Use preg_split() to split the string into an array along the
semicolons.
Loop over the array.
Use str_replace to replace each '=' with ' = "'.
Use string concatenation to add a $ to the front and a "; to the end of each string.
That should work, assuming your data doesn't include quotes, equal signs, semicolons, etc. within the data. If it does, you'll have to figure out the parsing rules for that.
I've got a string of:
test1.doc,application/msword,/tmp/phpDcvNQ5,0,23552
I want the first part before the comma. How do I get the first part 'test1.doc' on it's own without the rest of the string?
The string came from an array I imploded:
$uploadFlag=implode( ',', $uploadFlag );
echo $uploadFlag;
If it's easier to extract just the first value off the array on it's own that would also do the job. I don't think the array has any keys.
Thanks in advance.
echo $uploadFlag[0];
Uh, try that in place of that whole chunk of code. Since you're imploding it, you could just grab the first piece instead. That ought to echo the proper value!
$parts = explode(',', $uploadFlag);
$firstPart = $parts[0];
Use this code:
$part = substr($uploadFlag , 0, strpos($uploadFlag , ','));
To extract it from the string, you can use preg_replace() for example.
$firstPart = preg_replace('/,.*$/', '', $uploadFlag);
In the above example, the regular expression replaces everything (.*) that follows the first comma (,) until the end of the string ($) with nothing ('').
Or, if you can use the $uploadFlag array before replacing it with the imploded string, then you can use reset() to go to the first element in the array and current() to extract its value.
reset($uploadFlag);
$firstPart = current($uploadFlag);
Implode is not the right function. It takes an array and combines into one string. You are trying to do the reverse operation, which is handled by explode:
$uploadFlag=explode( ',', $uploadFlag );
echo $uploadFlag;
echo array_shift(array_slice($uploadFlag, 0, 1)); will output the first element of your array beit an associative or numbered array.
OK, so there is a page I'm querying on another server that returns a comma separated list of two values. Something it would return would be:
850,640
I have some PHP code that calls file_get_contents on that page and needs to do some numeric calculations based on the two values.
No matter what I try, I can't seem to get an int value out of this.
$res = trim(file_get_contents('http://thatURL/'));
echo "X" . $res . "X<br/>";
list($x,$y) = array_map(create_function('$a', 'return (int)$a;'), explode(',', $res));
echo "X:$x";
results in the output:
X 850,640 X
X:0
Note the spaces before and after the comma separated values(how the hell? I trim'd them!) and that $x is assigned the value 0.
What am I doing wrong here?
What am I doing wrong here?
Nothing, as far as I can see, which indicates that the content of $res is not quite what you expect. Could you change the first echo to:
echo htmlentities($res);
My guess is $res contains some un-printed characters, for example, it is actually:
<span> </span>850,640<span> </span>
or
850,640
Try the following. The array_map and llamda function are arguably overkill for your usage.
$res = " 850,640 ";
echo "X" . $res . "X<br/>";
list($x,$y) = explode(',', trim($res));
echo "X:" . (int)$x;
echo "Y:" . (int)$y;
Worked for me, but I'm not using file_get_contents(). If that doesn't work, something else is being output by the page.
PHP is not a typed language. Use intval to convert a string to integer.
Correction: it is a loosely typed language! That's what I meant!
Since I was using file_get_contents() on a URL, there was some HTML being put in as well that I didn't notice in my echo because it parsed out... just empty body and html tags. Oops!