I am trying to redirect a page to:
product_page.php?rest_id=$rest_id&area=$rest_city
for example:
product_page.php?rest_id=3&area=Enfield
At the moment the page is redirecting to:
http://localhost/PhpProject2/product_page.php?rest_id=&area=
Even though i have specified :
if (isset($_GET['rest_id'])){
$rest_id = mysqli_real_escape_string($dbc,$_GET['rest_id']);
}
if (isset($_GET['area'])){
$area = mysqli_real_escape_string($dbc,$_GET['area']);
}
if (isset($_GET['add_item'])) {
(int)$_GET['add_item']]){
$_SESSION['Shopping_cart_' . (int) $_GET['add_item']]+='1';
//redirect
echo"<script>window.open('product_page.php?rest_id=$rest_id&area=$rest_city','_self')</script>"; //header does not work
}
How would i go about getting the echo to re-direct to the correct page.
What i have tried:
Calling both add_item, rest_id and rest_city in the same if asset.
Moving the $_GET rest_id and rest_city closing tag after the echo.
The two above options just stop the page from re-directing all together, this is my first time doing this, any suggestions or tips would be greatly appreciated.
You should use double qotes ["string $variable string"] for variable to work inside a string or if not you should concatenate the string with [.] sign.
echo"<script>window.open('product_page.php?rest_id=$rest_id&area=$rest_city','_self')</script>";
This will not work because of single qoute [']
Regards
There are many syntax errors in your code. Also, the way you echo the string is wrong. You need to concat the variables with the string, using the PHP concatenation operator, else use double quotes.
Below fixed your errors:
if (isset($_GET['rest_id'])){
$rest_id = mysqli_real_escape_string($dbc,$_GET['rest_id']);
}
if (isset($_GET['area'])){
$area = mysqli_real_escape_string($dbc,$_GET['area']);
}
if (isset($_GET['add_item'])) {
$_SESSION['Shopping_cart_'] = (int) $_GET['add_item']+='1';
echo"<script>window.open('product_page.php?rest_id=" . $rest_id . "&area=" . $rest_city . "','_self')</script>";
}
Related
I'm sorry that this is basic. When I use this PHP code it works fine:
$data = '{"reportID":1092480021}';
However, when I run my URL like this:
http://localhost:8000/new/reportget.php?type=1092480021
and use this PHP code:
$reportref = $_GET['type'];
$data = '{"reportID:".$reportref."}"';
I get the error
Error_description:reportID is required
I think it's an error with how I am joining my variable to the string but I can't understand where I am going wrong.
Your string is improperly quoted. To match the format in your first example use:
$data = '{"reportID":' . $reportref.'}';
Note there are no double quotes on the last curly.
Even better:
$reportref = 1092480021;
$data = [ 'reportId' => $reportref ];
var_dump(json_encode($data));
Output:
string(23) "{"reportId":1092480021}"
For simple view and understanding, can you try out:
$data = "{\"reportID\":$reportref}";
Think that should sort it out
Use it like this
data = '{"reportID:"'.$reportref.'"}"';
It isn't working because you wrap all the value within single quote and when it come to concatenate the $reprtref you put directly .$reportref without closing the first single quote and after putting the value to concatenate you forget to open another single quote
'{"reportID:".$reportref."}"';
the correct value is
'{"reportID:"' . $reportref . '"}"';
and to match the way you specify your $data value It must be like this
'{"reportID":' . $reportref . '}';
I am simply trying to echo or print out specific data from a DB into a string (i hope thats the right name), which should be a very simple process as I've done it before. The point is everytime a user inserts information into the database this string echo's or prints out the inserted data.
But for some very odd reason this time around when i try to echo out the data, I literally get this.
Very frustrating. As you can see from the image above i have tried using 2 different ways to do this a variable and a session, but the echo literally just prints it out. I have done this before so i am aware that it is possible. I am just a little lost into how i am meant to achieve this or even better where i went wrong. I know how to do this using a different style of coding, but i am trying to keep everything uniformed (newbie).
$addon_name = $_SESSION['Add_On_OpName'];
mysqli_report(MYSQLI_REPORT_INDEX); //overrid a common php nonsense error
$prod_sel = $dbc->query("SELECT * FROM Add_On WHERE Add_On_OpName = '$addon_name'");
$prod_sel->data_seek(0);
while ($output = $prod_sel->fetch_assoc()) {
$prod_run .= $output['Add_On_OpName'] . $output['Prod_Name'] . $output['Add_On_Price'] . $output['Add_On_Select'] . '<br>';
$addon = $output['Add_On_OpName']; //echo out product name
$_SESSION['Prod_Name'] = $output['Prod_Name']; //echo out product desc
$_SESSION['Add_On_Price'] = $output['Add_On_Price']; //echo out price
echo '
<p>$addon . " " . $_SESSION["Add_On_Price"]; </p>
';
My session is started and the php file is connected to the DB.
I also have error handling which has not given out any error messages.
You must do:
echo "<p>$addon ".$_SESSION["Add_On_Price"]."; </p>";
A string encapsulated into ' is rendered just as it is.
Use " to render a string that contains variables. Example:
$a = 3;
$a++;
echo "the result is $a";
will result in the result is 4.
On the other hand,
echo 'the result is $a';
gives the result is $a.
As the documentation points out:
Single quoted ¶ The simplest way to specify a string is to enclose it
in single quotes (the character ').
Doued ¶
If the string is enclosed in double-quotes ("), PHP will interpret
more escape sequences for special characters
Try not mix it..
And if within double quotes you have an associative array you may concat.
echo "string $variable". $array["index"];
or
echo "string $variable {$array["index"]}";
Then your code should look like
$addon_name = $_SESSION['Add_On_OpName'];
mysqli_report(MYSQLI_REPORT_INDEX); //overrid a common php nonsense error
$prod_sel = $dbc->query("SELECT * FROM Add_On WHERE Add_On_OpName = '$addon_name'");
$prod_sel->data_seek(0);
while ($output = $prod_sel->fetch_assoc()) {
$prod_run .= $output['Add_On_OpName'] . $output['Prod_Name'] . $output['Add_On_Price'] . $output['Add_On_Select'] . '<br>';
$addon = $output['Add_On_OpName']; //echo out product name
$_SESSION['Prod_Name'] = $output['Prod_Name']; //echo out product desc
$_SESSION['Add_On_Price'] = $output['Add_On_Price']; //echo out price
echo "<p>$addon {$_SESSION["Add_On_Price"]}; </p>'";
}
Long time ago
I never use double quotes due to it require parse the whole string for special notations. However it.
Try not mix single quotes with double quotes. pick up a standard for you code you will not notice any difference than is easy to code and read without surprises
You're mixing single quotes and double quotes. Single quotes do not perform interpolation of variables so when you write this:
echo '... whatever including " char and $ sign';
PHP will just literally print everything inside.
You forget some ' or " !
echo '<p>' . $addon . ' ' . $_SESSION["Add_On_Price"] . '</p>';
Use double quotes
echo "<p>$addon $_SESSION['Add_On_Price']; </p>";
I have the following code which gets the URL parameter after the ? and displays it.
<?php
$qt = http_build_query($_GET);
echo $qt;
?>
But the problem i am having is that, whenever the URL is as follows:
http://example.net/blog?123
The output is as follows:
123=
How can i get rid of that "=" sign? I am parsing this into a mysql db, so the equal sign is not necessary.
Thank you!
P.S: I know that i need to sanitize the requests for security reasons, and i have that covered.
Use str_replace:
$qt = str_replace("=", "", http_build_query($_GET));
Just try this:
str_replace("=", "", $qt);
I'm trying to pass GET variables inside the URL with a bit of html inside of my PHP but can't figure out the quotes situation. I need to embed two variables inside the URL. I have one in but don't know how to embed the other. Here is the string:
echo "<a href='?id=".($id-1)."' class='button'>PREVIOUS</a>";
and here is what I need to go inside
&City=$City
Thanks for the help
Its pretty simple,
echo "<a href='?id=".($id-1)."&city=" . $City . "' class='button'>PREVIOUS</a>";
In php double quotes "" can eval variables inside them.
$test = "123;"
echo "0$test456"; // prints 0123456
In your case you better use single quote ''.
echo '<a href=\'?id=' . ($id-1) . '&City=' . $City . '\' class=\'button\'>PREVIOUS</a>';
or better
echo 'PREVIOUS';
Use something like this:
echo "<a href='?id=".$id."&City=".$city."'>";
You do need (well, it's good practice anyway) to use & for your ampersand. Otherwise it's fairly straight forward;
echo "<a href='?id=".($id-1)."&City=$City' class='button'>PREVIOUS</a>";
This is because you are using double quotes, which means you can put variables directly into the string (there are some exceptions which you might need to put in curly brackets {}).
I suggest you get a text editor with syntax highlighting, such as jEdit (other editors are available).
Hope this helps.
Maybe is it better to use the sprintf function
$id = 100;
$previousId = $id - 1;
$City = 'Amsterdam';
$link = 'PREVIOUS';
echo sprintf($link, $id, $City);
In my php code I need to invoke a script and passing it some arguments. How can I pass php variables (as arguments) ?
$string1="some value";
$string2="some other value";
header('Location: '...script.php?arg1=$string1&arg2=$string2');
thanks
header('Location: ...script.php?arg1=' . $string1 . '&arg2=' . $string2);
Either via string concatenation:
header('Location: script.php?arg1=' . urlencode($string1) . '&arg2=' . urlencode($string2));
Or string interpolation
$string1=urlencode("some value");
$string2=urlencode("some other value");
header("Location: script.php?arg1={$string1}&arg2={$string2}");
Personally, I prefer the second style. It's far easier on the eyes and less chance of a misplaced quote and/or ., and with any decent syntax highlighting editor, the variables will be colored differently than the rest of the string.
The urlencode() portion is required if your values have any kind of url-metacharacters in them (spaces, ampersands, etc...)
You could use the function http_build_query
$query = http_build_query(array('arg1' => $string, 'arg2' => $string2));
header("Location: http://www.example.com/script.php?" . $query);
Like this:
header("Location: http://www.example.com/script.php?arg1=$string1&arg2=$string2");
It should work, but wrap a urlencode() incase there is anything funny breaking the url:
header('Location: '...script.php?'.urlencode("arg1=".$string1."&arg2=".$string2).');