Formatting fwrite output to a external file - Implode Error - php

The code I am working on queries a database through php and then placed the results into an array called CS. This array is then encoded so it can work with javascript. It is then supposed to edit the output so there is a newline after every row. The latter is where I have the problem. I get implode: invalid arguments passed every time regardless of how I edit the implode function.
Here is the code:
<?php
$servername = "*****";
$username = "****"; --> edited for privacy.
$password = "*******";
$database = "********";
// Create connection
$conn = new mysqli($servername, $username, $password, $database);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
echo "Connected successfully";
// sql statement for tables and naming array to hold it in
$sql = "SELECT COURSE_ID FROM cs";
$result = $conn->query($sql);
$CS = array();
if ($result->num_rows > 0) {
// fill array with results
while($row = $result->fetch_assoc()) {
array_push($CS, $row);
}
} else {
echo "0 Results";
}
// encodes php array so it can be used in javascript
$json_array = json_encode($CS);
$conn->close();
// fills Computer_Science.js with the contents of the json_array and adds new lines in between
$json_array_lines = implode($json_array, "/n"); --> this line
$fp = fopen('..\js\DegreePlans\Computer_Science.js', 'w');
fwrite($fp, print_r($json_array_lines, TRUE));
fclose($fp);
?>
I'm at a loss on how to fix the error. Any help given will be appreciated.

I fixed it!
<?php
$servername = "*****";
$username = "****"; --> edited for privacy.
$password = "*******";
$database = "********";
// Create connection
$conn = new mysqli($servername, $username, $password, $database);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
echo "Connected successfully";
// sql statement for tables and naming array to hold it in
$sql = "SELECT COURSE_ID FROM cs";
$result = $conn->query($sql);
$CS = array();
if ($result->num_rows > 0) {
// fill array with results
while($row = $result->fetch_assoc()) {
array_push($CS, $row);
}
} else {
echo "0 Results";
}
$conn->close();
//encode the array so it can be used in javascript and use regular expressions to format it.
$json_string = json_encode($CS);
$re = "/.,/";
$subst = "},\r\n"; --> right here!
$json_string = preg_replace($re, $subst, $json_string);
$fp = fopen('..\js\DegreePlans\Computer_Science.js', 'w');
fwrite($fp, print_r($json_string, TRUE));
fclose($fp);
?>

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Unfortunately PHP file_get_contents not working

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Pulling data from mySQL to a text document php

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?>
Could it be because $namevals (replace) has one element and $placeholders (search) has two?
From the PHP doc:
If replace has fewer values than search, then an empty string is used for the rest of replacement values.

read a list of urls and read divs

Im trying to read the data of some divs in a list of urls, but i dont find the correct way, actually i only get a white page, but if do a print_r on the commented code (the $aElements) i can see the url loaded correctly, so i think the error is on the foreach, but i can't fix it, i need the link inside the div with the id=city
require_once('simple_html_dom.php');
set_time_limit (2000);
$servername = "localhost";
$username = "root";
$password = "";
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$conn = new mysqli($servername, $username, $password, $dbname);
if ($conn->connect_error) {
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}
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How to combine two MySQL connections into one MySQL connection?

I have two MySQL connections for the same database in the one .php file.
Second connection is base on the result of First one.
How can I combine two connection into one ? Please help & teach me how to modify it ?
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<?php
header('Content-Type: text/html; charset=utf-8');
$servername = "localhost";
$username = "abcabc";
$password = "12341234";
$dbname = "abc1234";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
$conn->set_charset("utf8");
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
// Logic data
$previous_page = ($_GET['crno'] - 1);
$next_page = ($_GET['crno'] + 1);
// select data
$sql = 'SELECT * FROM ComData WHERE com_no = '. $_GET['crno'];
$result = $conn->query($sql);
if ($result->num_rows > 0) {
// output data of each row
while($row = $result->fetch_assoc()) {
$pageTitle = $row['com_eng_name'] . $row['com_chi_name'];
$com_no = $row['com_no'];
$br_no = $row['br_no'];
$com_eng_name = $row['com_eng_name'];
$com_chi_name = $row['com_chi_name'];
$com_type = $row['com_type'];
$date_of_incorp = $row['date_of_incorp'];
$active_status = $row['active_status'];
$date_commenced_dormancy = $row['date_commenced_dormancy'];
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$date_of_dissolution = $row['date_of_dissolution'];
$register_charges = $row['register_charges'];
$name_history = $row['name_history'];
$phone = $row['phone'];
$email = $row['email'];
$address = $row['address'];
$website = $row['website'];
$background = $row['background'];
$update_time = $row['update_time'];
}
} else {
echo "No Results";
}
$conn->close();
?>
Second connection:
<?php
header('Content-Type: text/html; charset=utf-8');
$servername = "localhost";
$username = "abcabc";
$password = "12341234";
$dbname = "abc1234";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
$conn->set_charset("utf8");
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
// select data for similar search
$string = "$com_eng_name";
$words = implode(' ', array_slice(explode(' ', $string ), 0, 2));
$sql = "SELECT * FROM ComData
WHERE com_eng_name REGEXP '$words'
ORDER BY com_no
DESC
LIMIT 20";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
echo "<table><tr><th>CR No.</th><th>Company Name</th><th>Active Status</th></tr>";
// output data of each row
while($row = $result->fetch_assoc()) {
echo "<tr><td>".$row["com_no"]."</td><td><a href='search.php?crno=".$row["com_no"]."' >".$row["com_eng_name"]." ".$row["com_chi_name"]."</a></td><td>".$row["active_status"]."</td></tr>";
}
echo "</table>";
} else {
echo "0 results";
}
$conn->close();
?>
If those 2 pieces of code both exist in the same physical file then as the variable holding your connection in both cases is $conn you can just throw away the second attempt at making a connection to the database.
So just remove of comment out this code from the piece of code you called Second Connection i.e. this bit
$servername = "localhost";
$username = "abcabc";
$password = "12341234";
$dbname = "abc1234";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
$conn->set_charset("utf8");
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
Then remove this line
$conn->close();
from the piece of code you called First Connetion so you do not close the connection before the second piece of code runs.
However if in fact those 2 pieces of code are in seperate .php files. they have to stays the way they are.
It's not clear either if your two connection are in the same page or not, and if your two queries are execute sequentially or alternately.
Anyway, if the queries are on the same page or if you want put it in same page, sure you can use one only connection.
Start your script in this way:
header('Content-Type: text/html; charset=utf-8');
$servername = "localhost";
$username = "abcabc";
$password = "12341234";
$dbname = "abc1234";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
$conn->set_charset("utf8");
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
then, if you have to performs both queries, continue in this way:
// Logic data
$previous_page = ($_GET['crno'] - 1);
$next_page = ($_GET['crno'] + 1);
// select data
$sql = 'SELECT * FROM ComData WHERE com_no = '. $_GET['crno'];
$result = $conn->query($sql);
if ($result->num_rows > 0) {
(...)
} else {
echo "No Results";
}
// select data for similar search
$string = "$com_eng_name";
$words = implode(' ', array_slice(explode(' ', $string ), 0, 2));
(...)
$conn->close();
Otherwise, if the queries are executed only on condition, after connection check continue in this way:
if( /* Your Condition Here */ )
{
// Logic data
$previous_page = ($_GET['crno'] - 1);
(...)
}
else
{
// select data for similar search
$string = "$com_eng_name";
(...)
}
If you want use connection in any different file, you can create a file dbconnect.php with this content:
$servername = "localhost";
$username = "abcabc";
$password = "12341234";
$dbname = "abc1234";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
$conn->set_charset("utf8");
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
Then, in each file with db query, include it in this way:
header('Content-Type: text/html; charset=utf-8');
include( 'dbconnect.php' );
// Logic data
$previous_page = ($_GET['crno'] - 1);
(...)
header('Content-Type: text/html; charset=utf-8');
include( 'dbconnect.php' );
// select data for similar search
$string = "$com_eng_name";
(...)
etc...
Please note that, depending on 'dbconnect.php' file location, you can have to change include( 'dbconnect.php' ) with include( '/Full/Or/Relative/Path/dbconnect.php' ).

JSON_Encoded Value to be used in snother file

<?php
echo $xml = file_get_contents("C:\wamp\www\Sample API\index.php");
$result = json_decode($xml);
var_dump ($result);
?>
Index.php:
<?php
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$username = "root";
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{
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}
$output = (array('posts' => $data));
$out =json_encode($output);
echo $out;
?>
i am trying to get output value of index.php in this file and i'm trying this given code but $result returns the null value.Where as the included file returns the desire value but in this case json_decode returns null value.
You can just change this:
echo $out;
to:
return $out;
And then you just can require the file into the other one like this:
$xml = require_once("C:\wamp\www\Sample API\index.php");
$result = json_decode($xml);
var_dump($result);

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