I'm having difficulty using a MySQL query in a for loop to produce an array of IDs. Essentially, I have an array of parent IDs which I feed into the query via a for loop and am expecting to return an array of campaign IDs.
Inside the for loop I can echo every campaign ID for every parent ID but can't seem to access this array outside of the loop. I'm assuming this is a scoping issue, and I've fiddled with the code but aren't able to access an array of campaign_ids in its entirety outside of the loop.
My code is as follows:
$campaigns[] = array();
for ($i=0; $i < count($multIO); $i++) {
$sql = 'SELECT DISTINCT campaign_id
FROM prod_appnexus.fact_network_analytics_feed_aggregated_364
WHERE insertion_order_id = '.$multIO[$i]['IO_ID'].';';
$retval = mysql_query($sql, $conn);
while ($row = mysql_fetch_array($retval)) {
$campaigns = $row['campaign_id'];
echo print_r($campaigns);
};
};
Does anybody know how I can troubleshoot this?
Any comments would be greatly appreciated!
Thanks,
Sam
Change the line with this:
$campaigns[] = $row['campaign_id'];
or:
$campaigns[$multIO[$i]['IO_ID']][] = $row['campaign_id'];
Your sql is wrong dont use t1. when you are using single table and also when doing alias dont add as
$campaigns[] = array();
for ($i=0; $i < count($multIO); $i++) {
$sql = 'SELECT DISTINCT campaign_id
FROM fact_network_analytics_feed_aggregated_364 T1
WHERE insertion_order_id = '.$multIO[$i]['IO_ID'].';';
$retval = mysql_query($sql, $conn);
while ($row = mysql_fetch_array($retval)) {
$campaigns = $row['campaign_id'];
echo print_r($campaigns);
};
};
Related
I am trying to query a db for an entire column of data, but can't seem to get back more than the first row.
What I have so far is:
$medicationItem = array();
$medicationItemSql = "SELECT medication FROM medication";
$medicationItemObj = mysqli_query($connection, $medicationItemSql);
if($row = mysqli_fetch_array($medicationItemObj, MYSQLI_NUM)){
echo count($row);
}
It's not my intention to just get the number of rows, I just have that there to see how many it was returning and it kept spitting out 1.
When I run the sql at cmd line I get back the full result. 6 items from 6 individual rows. Is mysqli_fetch_array() not designed to do this?
Well, I had a hard time understanding your question but i guess you are looking for this.
$medicationItem = array();
$medicationItemSql = "SELECT medication FROM medication";
$medicationItemObj = mysqli_query($connection, $medicationItemSql);
if($row = mysqli_num_rows($medicationItemObj))
{
echo $row;
}
Or
$medicationItem = array();
$medicationItemSql = "SELECT medication FROM medication";
$medicationItemObj = mysqli_query($connection, $medicationItemSql);
$i = 0;
while ($row = mysqli_fetch_array($medicationItemObj))
{
$medicationItem[] = $row[0];
$i++;
}
echo "Number of Rows: " . $i;
If you just want the number of rows i would suggest using the first method.
http://php.net/manual/en/mysqli-result.num-rows.php
You can wrote your code like below
$medicationItem = array();
$medicationItemSql = "SELECT medication FROM medication";
$medicationItemObj = mysqli_query($connection, $medicationItemSql);
while ($row = mysqli_fetch_assoc($medicationItemObj))
{
echo $row['medication'];
}
I think this you want
You could give this a try:
$results = mysqli_fetch_all($medicationItemObj, MYSQLI_NUM);
First, I would use the object oriented version of this and always use prepared statements!
//prepare SELECT statement
$medicationItemSQL=$connection->prepare("SELECT medication FROM medication");
// execute statement
$medicationItemSQL->execute();
//bind results to a variable
$medicationItemSQL->bind_result($medication);
//fetch data
$medicationItemSQL->fetch();
//close statement
$medicationItemSQL->close();
You can use mysqli_fetch_assoc() as below.
while ($row = mysqli_fetch_assoc($medicationItemObj)) {
echo $row['medication'];
}
I've looked for something similar on stack but nothing exactly as this.
I (think I) need to generate a unique MySQL query inside a loop as each iteration needs to look up a different table. the loop is from an exploded $_GET array.
The problem is creating a differently named mysql query based on the loop iteration. I've done it where the $var name is different but it doesn't work, I think because it is a string not a variable?
Any help appreciated
$temps = explode(",", $_GET['temps']);
$tempCount = count($temps);
for ($i=0; $i<$tempCount; $i++)
{
/*'normal' database lookup
$check = mysql_query("SELECT * FROM _db_".$temps[$i]."");
$checks = array();
while ($row = mysql_fetch_assoc($check)) {
$checks[] = $row;
}*/
//here's where I'm trying to build a 'dynamic' lookup for each loop iteration
$checkTemp=$check.$temps[$i];
$checkTempArray=$check.$temps[$i].'Array';
$checkTemp = mysql_query("SELECT * FROM _db_".$temps[$i]."");
$checkTempArray = array();
while ($row = mysql_fetch_assoc($checkTemp)) {
$checkTempArray[] = $row;
}
}
If I understand correctly you're trying to SELECT * from all tables seperated by , in the $_GET["temps"]
$temps = explode(",", $_GET['temps']);
$tempCount = count($temps);
$allResults = array();
for ($i=0; $i<$tempCount; $i++)
{
$checkTemp = mysql_query("SELECT * FROM _db_".mysql_real_escape_string($temps[$i]));
$allResults[$temps[$i]] = array();
while ($row = mysql_fetch_assoc($checkTemp))
{
$allResults[$temps[$i]][] = $row;
}
}
// Now for example $allResults["john"][3] contains the fourth row in the table _db_john
print_r($allResults["sally"][2]); // print the third row in _db_sally
Seems like a typo in your code
$checkTemp = mysql_query("SELECT * FROM db".$temp[$i]."");
either use
$temps[$i] or just $temp
$temp[$i] doesn't makes any sense
so your query should be instead
$checkTemp = mysql_query("SELECT * FROM db".$temps[$i]."");
EDIT:
for your array part you can use
$$temp = array();
while ($row = mysql_fetch_assoc($checkTemp)) {
$$temp[] = $row;
}
I have an MSSQL query where it SELECTS all rows that meet a specific criteria. In PHP I want to fetch that array, but then I want to convert it into one array per row. So if my query returns 3 rows, I want to have 3 unique arrays that I can work with.
I'm not sure how to go about this. Any help would be greatly appreciated!
Thanks, Nathan
EDIT:
$query = "SELECT * FROM applicants WHERE applicants.user_id ='{$_SESSION['user_id']}'";
$query_select = mssql_query($query , $connection);
if (mssql_num_rows($query_select) == 2){
$message = '2 students created successfully';
}
$i = 0;
while($row = mssql_fetch_array($query_select)) {
$student.$i['child_fname'][$i] = $row['child_fname'];
$student.$i['child_lname'][$i] = $row['child_lname'];
$i++;
}
$query_array1 = $student0;
$query_array2 = $student1;
You will notice from the code above that I am expecting two rows to be returned. Now, I want to take those two rows and create two arrays from the results. I tried using the solution that was give below. Perhaps my syntax is incorrect or I didn't understand how to properly implement his solution. But any help would be greatly appreciated.
$query = mssql_query('SELECT * FROM mytable');
$result = array();
if (mssql_num_rows($query)) {
while ($row = mssql_fetch_assoc($query)) {
$result[] = $row;
}
}
mssql_free_result($query);
Now you can work with array like you want:
print_r($result[0]); //first row
print_r($result[1]); //second row
...
$i=0;
while( $row = mysql_fetch_array(query){
$field1['Namefield1'][$i] = $row['Namefield1'];
$field2['Namefield2'][$i] = $row['Namefield2'];
$field3['Namefield3'][$i] = $row['Namefield3'];
$i++;
}
or if you preffer an bidimensional array:
$i=0;
while( $row = mysql_fetch_array(query){
$result['Namefield1'][$i] = $row['Namefield1'];
$result['Namefield2'][$i] = $row['Namefield2'];
$result['Namefield3'][$i] = $row['Namefield3'];
$i++
}
I have a script like this:
$result = array();
$sql = "SELECT DISTINCT Name FROM servers"; //doesn't really matter what this MySQL script is
//storing the same query in two different variables
$result[0] = mysql_query($sql);
$result[1] = $result[0];
for($i = 0; $i < 3; $i++) {
$result[0] = $result[1];
while($ret = mysql_fetch_array($result[0]) {
//run some code
}
}
Unfortunately, the above code executes once and then for the next iterations returns nothing. What am I doing wrong?
I am not so sure what are you trying to do. but if i understand, try this. remove the for loop, just put the while loop and do what ever you want to.
$sql = "SELECT DISTINCT Name FROM servers";
$result = mysql_query($sql);
while($ret = mysql_fetch_array($result) {
//run some code
echo $ret['Name'];
}
}
you will get all 3 records in each iteration and do what ever process you want to do for each record. no need to make a three 3 query for 3 records. One query will have all records and do while loop to get each record. hope it helps.
I need to print a wine list from a database.
I need to print at first a categorie and after all the items that are inside. Thats the order. And i have multiple categorie. So at the end the result will be categorie1, many items, categorie2 many items...
This is the code that i write from now: I think that my problem is to print items according to the id of the alcool_categorie !!
$q_vine = "SELECT * FROM alcool_categorie ";
$r_vine = mysql_query($q_vine,$connection);
$n_vine = mysql_num_rows($r_vine);
$q_bouteille = "SELECT * FROM alcool_item where ALCNID = '$alid'";
$r_bouteille = mysql_query($q_bouteille,$connection);
$n_bouteille = mysql_num_rows($r_bouteille);
for($i = 0; $i < $n_vine; $i++){
echo mysql_result($r_vine,$i,'named').'<br/><br/>';
for($z = 0; $k < $n_bouteille; $k++){
echo mysql_result($r_bouteille,$k,'name').'<br/>';
}
}
I think it's best to use a "JOIN" in your query and then order the rows in the way you want them to be ordered, then you'll only need one loop. While running the loop you compare the category name with the previous category name and if it changes display the category name.
Example
$sql = "SELECT categoryName, bottleName FROM category INNER JOIN bottle ON category.categoryId = bottle.categoryId ORDER BY category.categoryId";
$result = mysql_query($sql,$connection);
$categoryName = ''; //just to make sure the first time the Category is named
while ($row = mysql_fetch_assoc($result)) {
if($categoryName != row['categoryName']){
$categoryName = row['categoryName'];
echo '<h1>'.$categoryName.'</h1>';
}
echo row['bottleName'].'<br/>';
}
Try this after correctly giving the category id field name in the query and inside the first while loop.
$q_vine = "SELECT id, named FROM alcool_categorie ";
$r_vine = mysql_query($q_vine,$connection);
$n_vine = mysql_num_rows($r_vine);
while ($row = mysql_fetch_assoc($r_vine)) {
$categories[$row['id']] = $row;
}
$q_bouteille = "SELECT name, ALCNID FROM alcool_item ";
$r_bouteille = mysql_query($q_bouteille,$connection);
$n_bouteille = mysql_num_rows($r_bouteille);
while ($row = mysql_fetch_assoc($r_bouteille)) {
$items[$row['ALCNID']] = $row;
}
foreach ($categories as $category_id=>$category) {
echo "<ul><li>{$category['named']}<ul>";
foreach ($items[$category_id] as $item) {
echo "<li>{$item['name']}</li>";
}
echo "</ul></li></ul>";
}
You will want to look into PHP's foreach construct. Foreach loops through an entire array of results, for each element inside the array, it extracts its value and optionally also its key. This will not require the use of mysql_num_rows.
Instead of calling mysql_result, you could use mysql_fetch_assoc to get a row's value from your mysql_query. The row's To get all values, you can incorporate this into a loop even. If you do the latter, you can create your own array of key/value pairs and use this inside a foreach construct.
Also note that the use of mysql is outdated, you will want to use mysqli now, which is very similar to mysql.