This is my Code Of Controller
$datacc['user_id'] = $this->user_id;
$this->load->view("Templates/header",$this->data);
$this->load->view("Tax/Tax_Search",$datacc);
$this->load->view("Tax/Tax",$datacc);
in this, i want to pass "$datacc" to my both view files (Tax.php And Tax_Search)
but $datacc can't pass to Tax_Search.php file
can anyone help?
Thank You
You cannot call multiple view in one controller function.
This can be done in view file.
I suggest you that you should first create a template file and in that template call your views like this
template.php
$this->load->view("Tax/Tax");
$this->load->view("Tax/Tax_search");
<?php echo $content; ?>
$this->load->view("Tax/footer");
Let me know if you have queries
Related
I'm starting a large codeigniter project and would like to try to create some reusable 'mini' views for snippets of content like loops of data which may be displayed on different pages/controllers.
Is it better to call the views from within the main controller's view? If so, how? Or should I call the 'mini view' from the controller and thus pass the view's code to the main view?
Views within other views are called Nested views.
There are two ways of including nested views in CodeIgniter:
1. Load a nested view inside the controller
Load the view in advance and pass to the other view. First put this in the controller:
<?php
// the "TRUE" argument tells it to return the content, rather than display it immediately
$data['menu'] = $this->load->view('menu', NULL, TRUE);
$this->load->view ('home', $data);
?>
Then put <?=$menu?> in your view at the point you want the menu to appear.
2. Load a view "from within" a view
First put this in the controller:
<?php
$this->load->view('home');
?>
Then put this in the /application/views/home.php view:
<?php $this->view('menu'); ?>
<p>Other home content...</p>
About best method, I prefer the 1st method over 2nd one, because by using 1st method I don't have to mix up code, it is not like include php. Although indirectly both are same, the 1st method is clearer & cleaner than 2nd one!
Honestly I prefer to do this by having template views then loading that with the necessary data from the controller, it means a lot less repeated code and follows the DRY concept better than loading views from views. Especially for things like headers, footers and menus.
So my template view would look something like this:
template.php
$this->load->view('header',$title);
$this->load->view('sidebar',$sidebar_content);
$this->load->view('main_content',$main_content);
$this->load->view('footer');
Then in my controller I pass the data required to the template like this:
$data['title'] = 'Home Page';
$data['sidebar_content']='pages/standard_sidebar';
$data['main_content'] ='pages/my_home_page';
$this->load->view('template',$data);
There are a number of benefits to doing it this way. First is I can have multiple templates, for example I have, in my case, two main ones, one for full page views without a sidebar and one for pages with a sidebar, I also call an if statement to decide which header to include, the regular one or the one with the admin menu in it.
Yes I could include the header, sidebar and footer in every main view page, but that ends up in a ton of duplicate code. And what happens if for example I want all my pages to have something new, some other small snippet? Using templates I add the snippet to the appropriate template and it's done. Going the other route I find every page and add the snippet view there, it's the equivalent to having CSS in the page in my opinion, wasteful and not ultimately maintainable.
METHOD 1
I use this method into my view to insert the include view where I want
$this->load->view('include/include_view');
METHOD 2
or in the controller you can load more than a view like this:
$this->load->view('header_view');
$this->load->view('list_view');
$this->load->view('footer_view');
No one method is better than the other, it depends if you have to pass some data (in this case use method2) or if you want to include a view in a specific part of your main view (in this case is better to use method1)
METHOD 3
Passing data to your include view by your main view
into your controller:
$data['title'] = "Title";
$this->load->view('main_view',$data);
in your view
$data2['title'] = $title;
$this->load->view('include/include_view',$data2);
If you want to pass entire data to your include view you can do in this way:
in your controller:
$data['nestedView']['title'] = 'title';
in your view
$this->load->view('includes/included_view', $nestedView);
This a simple way of including views within views.there is no need to load views in advance.just pass view path to other view.
In your controller use this:
$data['middle'] = 'includeFolder/include_template_view'; //the view you want to include
$this->load->view('main_template_view',$data); //load your main view
and in main_template_view you can include other views :
$this->load->view($middle);
In my opinion for solve in more efficient way this problem I have done so:
You create a new helper (in application/helpers) with name (es. common_helpers.php, the underscore is important). In this file, you put all the functions for example build pieces of html in common.
<?php if ( ! defined('BASEPATH')) exit('No direct script access allowed');
function getHead(){
require_once(APPPATH."views/common/head.php");
}
function getScripts(){
require_once(APPPATH."views/common/scripts.php");
}
function getFooter(){
require_once(APPPATH."views/common/footer.php");
}
In your controller you call only one view in respect of MVC and call the functions from your custom helper.
class Hello extends CI_Controller {
public function index(){
$this->load->helper('common');
$this->load->view('index');
}
}
In the controller
controller
<?php
public function view($page = NULL)
{
if ( ! file_exists(APPPATH.'views/pages/'.$page.'.php'))
{
$data['title'] = ucfirst($page); // Capitalize the first letter
// Whoops, we don't have a page for that
show_404();
}
$data= array('');
$data['title'] = ucfirst($page); // Capitalize the first letter
$data['page_layout']='pages/'.$page;
$this->load->view('page_layout', $data);
}
?>
In the Views folder create a page called page_layout.php
page_layout.php
//This is where you set the layout to call any view through a variable called $page_layout declared in the controller//
<?php
$this->load->view('header');
$this->view($page_layout);
$this->load->view('footer');
?>
I have a view that is rendered with its controller. The function that calls the view is linked in my routes. It works fine when directly accessing the route, but obviously my controller is not included when I include it in my template.
How do I use my controller when I include my view?
I'm on Laravel 3.
Right now I have my controller :
public function get_current()
{
// $sales = ...
return View::make('sale.current')->with('sales',$sales);
}
My route (which obv only work on GET /current) :
Route::get('current', 'sale#current');
My master view
#include('sale.current')
Then my sale.current view calls $sales
#foreach($sales as $sale)
Thanks!
So this is the case when you want to call some laravel controller action from view to render another partial view. Although you can find one or another hack around it. However, please note that laravel controllers are not meant for that.
When you encounter this scenario when you want to reuse the same view again but don't want to supply all necessary data again & again in multiple controller actions, it's the time you should explore the Laravel View Composers.
Here is the official documentation link : https://laravel.com/docs/master/views#view-composers
Here is the more detailed version of it :
https://scotch.io/tutorials/sharing-data-between-views-using-laravel-view-composers
This is the standard way of achieving it without any patch work.
Your question is still unclear but I can try to help you. I did a small example with the requirements you gave. I create a route to an action controller as follows:
Route::get('test', 'TestController#test');
In TestController I define the action test as follows:
public function test()
{
return View::make('test.home')->with('data', array('hello', 'world', '!'));
}
According to your asking, you defined a view who includes content from another view (layout) and in that layout you use the data passed for the action controller. I create the views as follows:
// home.blade.php
<h1>Message</h1>
#include('test.test')
and
// test.blade.php
<?php print_r($data); ?>
When I access to "test" I can see print_r output. I don't know if that is what you are doing, but in my case works fine.
I hope that can help you.
Code from controller:
public function actionSomeName($param){
do something here...
$this->renderPartial('_formCalculations', array(
'modelX'=>$modelX,
'modelY'=>$modelY,
));
}
I want to call that function in my view, but it won't work.
Is $this->renderPartial correct ? I think not, because it's only for views? But which function do I have to use then?
$this->renderPartial('Controllername/Somename',array("param"=>"value"));
You can't call the controller/action directly in the view.
You can user render/renderPartial. Render/renderPartial reference
a view file, not a controller action
You could put in your logic in the code as well (in your example, the "do something here..." part) but that is not good MVC!
The other alternative is to use a widget
Surly you can`t use renserPartial individually, but you can do it so:
$body = $this->renderPartial('Controllername/Somename',array("param"=>"value"),true);
In this code you have that view file`s scripts and you can use them anywhere you need.
I want to get the current controller name that handles the current action.
but the in my case I will look for the current controller in my main.php in my layout files.
this is my small view of my directory structure to give you an idea where is my layout files and the file where i will put my codes in searching of my controller name
/protected
/themes
/mylayout
/layouts
main.php
column1.php
column2.php
/site
index.php
Is this possible? im trying the following codes but i failed to get my current controller name...
echo Yii::app()->controller->getId;
echo Yii:app()->getController->id;
echo Yii:app()->controller->uniqueID;
thanks
Like this
Yii::app()->controller->id
or
Yii::app()->getController()->getId()
http://www.yiiframework.com/doc/api/1.1/CApplication#getController-detail
Controller Id :
$this->id
Here $this refers to controller.
And
For getting action id :
$this->action->id
<?php echo $this->getUniqueId();?>
this will show current controller
You're not actually required to use the static function. Whenever in a view( or template) you can use echo $this->getUniqueId(); to get the unique controller ID.
Yii2:
Yii::$app->controller->id
(Documentation: Application and Controller)
I load a helper file and it is included successfully
The constants variable in helper file such as
Define("FIELD_VALID", "valid");
If i echo FIELD_VALID in view file...it works
But there is assigned variable in helper file such as
$strSite="http://www.mysite.com/";
If i echo $strSite in view file, it prints nothing
Hoping for the answer
Thanks.
What you are trying to do would be much better accomplished with a custom config file. Look at this: http://codeigniter.com/user_guide/libraries/config.html