Processing the Search String with PHP and MySQL - php

Question

I'm in the process of making a web page that's meant to display data that's within a database. The database is stored in MySQL and I'm making the web page in PHP. The PHP code that I have is
<?php
$query = "select * from project where ".$searchtype." like '%".$searchterm."%'";
$result = mysqli_query($db,$query);
$num_results = mysqli_num_rows($results);
echo "<p>Number of projects found: ".$num_results."</p>";
for ($i=0; $i <$num_results; $i++) {
$row = mysqli_fetch_assoc($result);
echo "<p><strong>".($i+1).". Title: ";
echo htmlspecialchars(stripslashes($row['title']));
echo "</strong><br />Author: ";
echo stripslashes($row['author']);
echo "<br />ISBN: ";
echo stripslashes($row['isbn']);
echo "<br />Price: ";
echo stripslashes($row['price']);
echo "</p>";
}
$mysqli_free_result($result);
$mysqli_close($db);
?>
This PHP script is meant to load different projects that's within the database and in a welcome.php script that calls this script connects to the database and it does connect to it correctly. The problem that I'm having is when I run this script, is that I get the following:
Number of projects found:
As shown, it doesn't display any data from the database.
EDIT
My welcome.php script is
<?php
$hostname='mysql.uniwebsite.ac.uk';
$database='uniusername';
$username='database';
$password='password';
$db= mysql_connect($hostname, $username, $password);
if (!$link) {
die('Connection failed: ' . mysql_error());
}
else{
echo "Connection to MySQL server " .$hostname . " successful!
" . PHP_EOL;
}
$db_selected = mysql_select_db($database, $link);
if (!$db_selected) {
die ('Can\'t select database: ' . mysql_error());
}
else {
echo 'Database ' . $database . ' successfully selected!';
}
?>
EDIT #2
My projects.php code is
<?php
$searchtype=$_POST['searchtype'];
$searchterm=trim($_POST['searchterm']);
if (!$searchtype || !$searchterm) {
echo 'No search details. Go back and try again.';
exit;
}
$query = "select * from project where ".$searchtype." like '%".$searchterm."%'";
var_dump($query);
$result = mysqli_query($link,$query);
$num_results = mysqli_num_rows($result);
echo "<p>Number of projects found: ".$num_results."</p>";
for ($i=0; $i <$num_results; $i++) {
$row = mysqli_fetch_assoc($result);
echo "<p><strong>".($i+1).". Project Number: ";
echo htmlspecialchars(stripslashes($row['projectNo']));
echo "</strong><br />Project Name: ";
echo stripslashes($row['pjname']);
echo "<br />Project City: ";
echo stripslashes($row['city']);
echo "</p>";
}
mysqli_free_result($result);
mysqli_close($link);
?>
And when I run it, I get No search details. Go back and try again.
EDIT #3
In my projects.php I have now got
<form action="list_projects.php" method="post">
<p>Choose Search Type: <br /></p>
<select name="searchtype">
<option value="partNo">Part Number</option>
<option value="pname">Part Name</option>
<option value="color">Part Colour</option>
<option value="weight">Part Weight</option>
<option value="city">City</option>
</select>
<br />
<p>Enter Search Term: </p>
<br />
<input name="searchterm" type="text" size="20"/>
<br />
<input type="submit" name="submit" value="Search"/>
</form>
<?php
$searchtype=$_POST['searchtype'];
$searchterm=trim($_POST['searchterm']);
if (!$searchtype || !$searchterm) {
echo 'No search details. Go back and try again.';
exit;
}
$query = "select * from project where ".$searchtype." like '%".$searchterm."%'";
var_dump($query);
$result = mysqli_query($link,$query);
$num_results = mysqli_num_rows($result);
echo "<p>Number of projects found: ".$num_results."</p>";
for ($i=0; $i <$num_results; $i++) {
$row = mysqli_fetch_assoc($result);
echo "<p><strong>".($i+1).". Part Number: ";
echo htmlspecialchars(stripslashes($row['partNo']));
echo "</strong><br />Part Name: ";
echo stripslashes($row['pname']);
echo "<br />Part Colour: ";
echo stripslashes($row['color']);
echo "<br />Part Weight: ";
echo stripslashes($row['weight']);
echo "<br />City";
echo stripcslashes($row['city']);
echo "</p>";
}
mysqli_free_result($result);
mysqli_close($link);
?>
but when I run it, I get string(49) "select * from project where projectNo like '%J1%'"
Number of projects found:

Answer 1

EDIT
Here are the both files corrected. There were few more typos with function names like $mysqli_free_result($result) and $mysqli_close($db).
File welcome.php:
<?php
$hostname='mysql.uniwebsite.ac.uk';
$database='uniusername';
$username='database';
$password='password';
$link = mysql_connect($hostname, $username, $password);
if (!$link) {
die('Connection failed: ' . mysql_error());
}
else{
echo "Connection to MySQL server " .$hostname . " successful!
" . PHP_EOL;
}
$db_selected = mysql_select_db($database, $link);
if (!$db_selected) {
die ('Can\'t select database: ' . mysql_error());
}
else {
echo 'Database ' . $database . ' successfully selected!';
}
?>
<?php
$query = "select * from project where ".$searchtype." like '%".$searchterm."%'";
// var_dump($query); -- uncomment to make sure the final query makes sense after filling those variables
$result = mysqli_query($link,$query);
$num_results = mysqli_num_rows($result);
echo "<p>Number of projects found: ".$num_results."</p>";
for ($i=0; $i <$num_results; $i++) {
$row = mysqli_fetch_assoc($result);
echo "<p><strong>".($i+1).". Title: ";
echo htmlspecialchars(stripslashes($row['title']));
echo "</strong><br />Author: ";
echo stripslashes($row['author']);
echo "<br />ISBN: ";
echo stripslashes($row['isbn']);
echo "<br />Price: ";
echo stripslashes($row['price']);
echo "</p>";
}
mysqli_free_result($result);
mysqli_close($link);
?>

Answer 2

UPDATE
Remove mysql_close($link);
And then, instead of using $db in the rest of your code, use $link.
$result = mysqli_query($link, $query);